如果使用 Combine 和 Swift 第一次解码失败，则解码另一个响应

Question

我有以下型号：

struct Response: Decodable {
    let message: String
}

struct ErrorResponse: Decodable {
    let errorMessage: String
}

enum APIError: Error {
    case network(code: Int, description: String)
    case decoding(description: String)
    case api(description: String)
}

我正在尝试获取 url 并使用此流程解析 JSON 响应：

func fetch(url: URL) -> AnyPublisher<Response, APIError> {
    URLSession.shared.dataTaskPublisher(for: URLRequest(url: url))

        // #1 URLRequest fails, throw APIError.network
        .mapError { .network(code: [=12=].code.rawValue, description: [=12=].localizedDescription) }

        // #2 try to decode data as a `Response`
        .tryMap { JSONDecoder().decode(Response.self, from: [=12=].data) }

        // #3 if decoding fails, decode as an `ErrorResponse`
        //    and throw `APIError.api(description: errorResponse.errorMessage)`

        // #4 if both fail, throw APIError.decoding
        
        // #5 return
        .eraseToAnyPublisher()
}

我对 #3 有疑问：如何解码 tryMap 部分之后的原始数据？

似乎我可以访问的唯一值是来自 tryMap 的错误，但我需要原始数据来解码 ErrorRepsonse.

注意：不幸的是，错误响应带有 200 状态，区分它们的唯一方法是解码它们。

Answer 1

您可以使用 flatMap 并在其中处理解码：

URLSession.shared.dataTaskPublisher(for: URLRequest(url: url))
   // #1 URLRequest fails, throw APIError.network
   .mapError { 
       APIError.network(code: [=10=].code.rawValue, description: [=10=].localizedDescription) 
   }

   .flatMap { data -> AnyPublisher<Response, APIError> in
      // #2 try to decode data as a `Response`
      if let response = try? JSONDecoder().decode(Response.self, from: data) {
         return Just(response).setFailureType(to: APIError.self)
                    .eraseToAnyPublisher()
      }

      do {
         // #3 if decoding fails, decode as an `ErrorResponse`
         let error = try decoder.decode(ErrorResponse.self, from: data)
             
         // and throw `APIError.api(description: errorResponse.errorMessage)`
         return Fail(error: APIError.api(description: errorResponse.errorMessage))
                    .eraseToAnyPublisher()
      } catch {
         // #4 if both fail, throw APIError.decoding
         return Fail(error: APIError.decoding(description: error.localizedDescription))
                    .eraseToAnyPublisher()
      }
   }

编辑

如果您想以“纯粹的”合并方式执行此操作，那么您仍然希望使用 flatMap 来访问原始数据并回避最初可能出现的网络错误，然后使用tryCatch处理失败路径

请注意，第 4 步位于第 3 步的两个部分之间：

URLSession.shared.dataTaskPublisher(for: URLRequest(url: url))
   // #1 URLRequest fails, throw APIError.network
   .mapError { 
       APIError.network(code: [=11=].code.rawValue, description: [=11=].localizedDescription) 
   }
   .flatMap { v in
      Just(v)

         // #2 try to decode data as a `Response`
         .decode(type: Response.self, decoder: JSONDecoder())

         // #3 if decoding fails,
         .tryCatch { _ in
            Just(v)
               // #3.1 ... decode as an `ErrorResponse`
               .decode(type: ErrorResponse.self, decoder: JSONDecoder())
               
               // #4 if both fail, throw APIError.decoding
               .mapError { _ in APIError.decoding(description: "error decoding") }

               // #3.2 ... and throw `APIError.api
               .tryMap { throw APIError.api(description: [=11=].errorMessage) }
         }

         // force unwrap is not terrible here, since you know 
         // that `tryCatch` only ever throws APIError
         .mapError { [=11=] as! APIError }
   }

如果使用 Combine 和 Swift 第一次解码失败，则解码另一个响应

Decode another response if first decoding failed using Combine and Swift

json

swift

combine

decodable