按角色获取用户

Question

我在一个实体（用户）中有一个实体（组）数组，在我的查询生成器中，我想按角色检索用户。

我正在尝试这样做：

public function findUsersByRole($role){
    $qb = $this->createQueryBuilder('u');
    $qb->select('u')
       ->where('u.roles LIKE :role')
       ->setParameter('role', $role);

    return $qb->getQuery()->getResult();
}

但是我没有得到结果。

我也试过：

public function findUsersByRole($role)
{
  $qb = $this->createQueryBuilder('u');
  $qb->select('u')
      ->where(':role MEMBER OF u.roles')
      ->setParameter('role', $role);
  return $qb->getQuery()->getResult();
}

但我收到错误消息：

[Semantical Error] line 0, col 62 near 'roles': Error: Invalid PathExpression. Must be a CollectionValuedAssociationField.

我做错了什么？

角色存储在 JSON 类型的用户 table 字段角色字段中，如下所示：

[
    "ROLE_USER",
    "ROLE_ADMIN"
]

这是用户class的函数，在数据库中存储用户角色：

public function setRoles(array $roles){
    $this->roles = $roles;
}

这是我正在编写的单元测试，用于测试 testFindUsersByRole 函数：

public function testFindUsersByRole() {
    $user1 = $this->createUser(1, "Developer", "John", "Smith", "smith@test.com");
    $user2 = $this->createUser(2, "Developer", "Joe", "Black", "joe@test.com");
    $user3 = $this->createUser(3, "Developer", "Jack", "Blade", "blade@test.com");

    $roles1 = ['ROLE_ADMIN','ROLE_USER'];
    $roles2 = ['ROLE_USER'];

    $user1->setRoles($roles1);
    $user2->setRoles($roles2);

    $response = $this->userRepository->findUsersByRole('ROLE_ADMIN');
    $this->assertCount(1, $response);

    $this->purge([$user1, $user2, $user3]);
}

Answer 1

我发现我做错了什么。
在我的单元测试中，我没有在分配角色后将用户实体保存在数据库中。所以我已经修复了这样的单元测试。

public function testFindUsersByRole() {
    $user1 = $this->createUser(1, "Developer", "John", "Smith", "smith@test.com");
    $user2 = $this->createUser(2, "Developer", "Joe", "Black", "joe@test.com");
    $user3 = $this->createUser(3, "Developer", "Jack", "Blade", "blade@test.com");

    $roles1 = ['ROLE_ADMIN','ROLE_USER'];
    $roles2 = ['ROLE_USER'];

    $user1->setRoles($roles1);
    $user2->setRoles($roles2);

    $this->entityManager->persist($user1);
    $this->entityManager->persist($user2);
    $this->entityManager->flush();

    $response = $this->userRepository->findUsersByRole('ROLE_ADMIN');
    $this->assertCount(1, $response);

    $this->purge([$user1, $user2, $user3]);
}

这个函数就是有效的函数：

public function findUsersByRole($role){
    $qb = $this->createQueryBuilder('u');
    $qb->select('u')
       ->where('u.roles LIKE :roles')
       ->setParameter('roles', '%"'.$role.'"%');
    
    return $qb->getQuery()->getResult();
  }

按角色获取用户

Get users by role

doctrine

doctrine-orm