计算 Swift 5 中结构数组数组中的元素数

Question

作为新手，我真的很苦恼如何解决计算结构数组中元素的问题。我尝试了几种不同的方法，但没有给我所需的结果。

所以我有一个名为 Card 的结构，定义如下：

 struct Card: Hashable {
    
    var dateGroup: DateGroup
    var countryGroup: CountryGroup
    var icon1: IconGroup
    var icon2: IconGroup
    
    init(dateGroup: DateGroup, countryGroup: CountryGroup, icon1: IconGroup, icon2: IconGroup) {
        
        self.dateGroup = dateGroup
        self.countryGroup = countryGroup
        self.icon1 = icon1
        self.icon2 = icon2
   
    } 
}

作为参考，Card 的元素使用以下代码定义为枚举：

enum DateGroup: String {
    
    case DG1, DG2, DG3
    
    static let allValues = [DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG1,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG2,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3, DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3,    DG3]
    
}

enum CountryGroup: String {
    
    case IT, NE, FS, US
    
    static let allValues = [IT,    IT,    IT,    IT,    IT,    IT,    IT,    IT,    NE,     NE,     IT,    NE,     NE,     NE,     IT,    IT,    IT,    NE,     IT,    NE,     IT,    IT,    IT,    NE,     IT,    IT,    IT,    IT,    NE,     IT,    NE,     NE,     FS,    FS,    NE,     IT,    IT,    NE,     NE,     IT,    IT,    NE,     FS,    FS,    FS,    NE,     FS,    NE,     NE,     NE,     NE,     FS,    NE,     NE,     FS,    NE,     IT,    NE,     NE,     FS,    FS,    NE,     IT,    NE,     FS,    NE,     NE,     NE,     NE,     FS,    FS,    FS,    FS,    FS,    US,    FS,    FS,    FS,    FS,    NE,     FS,    FS,    FS,    NE,     US,    IT]
    
}

enum IconGroup: String {
    
    case Portrait, People, Still, Scape, Setting
    
    static let allValues1 = [Portrait,     People,    People,    Portrait,     Portrait,     People,    People,    People,    People,    Portrait,     People,    Portrait,     People,    People,    People,    Portrait,     People,    Portrait,     People,    Portrait,     Portrait,     People,    People,    Portrait,     People,    People,    Portrait,     People,    Portrait,     People,    Portrait,     People,    Portrait,     People,    People,    People,    People,    Still,    People,    Portrait,     People,    Portrait,     Still,    People,    People,    People,    Portrait,     Still,    People,    Portrait,     Portrait,     People,    Still,    Still,    People,    Still,    People,    Portrait,     Portrait,     People,    People,    People,    People,    Portrait,     Portrait,     People,    Scape,    Scape,    Setting,    People,    People,    Still,    People,    Still,    Setting,    Scape,    People,    People,    People,    Still,    Still,    Portrait,     People,    Portrait,     People,    People]
    
    static let allValues2 = [Setting,    Setting,    Setting,    Setting,    Setting,    Setting,    Setting,    Scape,    Setting,    Setting,    Scape,    Scape,    Setting,    Setting,    Scape,    Scape,    Setting,    Scape,    Setting,    Scape,    Scape,    Scape,    Scape,    Setting,    Scape,    Scape,    Setting,    Scape,    Setting,    Setting,    Portrait,     Setting,    Setting,    Setting,    Scape,    Portrait,     Setting,    Still,    Scape,    Setting,    Scape,    Setting,    Still,    Scape,    Scape,    Scape,    Setting,    Still,    Scape,    Portrait,     Setting,    Setting,    Still,    Still,    Scape,    Still,    Scape,    Portrait,     Scape,    Setting,    Scape,    Setting,    Scape,    Setting,    Setting,    Scape,    Scape,    Scape,    Scape,    Scape,    Scape,    Still,    Scape,    Still,    Still,    Scape,    Setting,    Setting,    Scape,    Still,    Still,    Setting,    Setting,    Setting,    Setting,    Setting]
    
}

我创建了一个名为 DeckOfCards 的 class，其功能是洗牌并向指定数量的玩家发牌。我最终完成了所有工作，并通过在控制台中打印结果进行了检查，并且全部检查完毕。

所以每个玩家都有 10 张牌，并且被定义为 Card 类型的数组（另外，玩家也存储在一个名为 newGame 的数组中）。所以 newGame[0] 是玩家 1，newGame[0][0] 是玩家手中的第一张牌。因此，我可以通过 newgame[0][0].dateGroup 引用该卡的日期组，例如。

我想要实现的是检查玩家是否有一套 5 张或更多张牌，其中两张牌的元素相同。我首先尝试对玩家手中的卡片元素进行计数。因此，例如，有多少卡片有 DG1 的日期组，DG2 等有多少，国家组有多少 IT 等。

我尝试过使用 joined() 然后进行计数，但没有成功。我正在考虑返回一个数组，其中包含每种可能的元素类型的计数，并从这个非常骨架的代码开始：

  func createIconCount(playerHand: [Card] ) -> [String : Int] {
        
        var counts: [String: Int] = [:]

        //insert counting code here

        return counts
    }

所以我会得到一个数组，其中包含 [DG1: 3, DG2: 3, ....... IT: 4, NE: 5, .... Portrait: 6, People: 4、.....]

求助！有什么想法吗？

罗布

Answer 1

这是您要查找的函数：

func createIconCount(playerHand: [Card] ) -> [String : Int] {
    
    var counts: [String: Int] = [:]

    //insert counting code here
    //=========================
    for player in playerHand {
        if(!counts.keys.contains(player.dateGroup.rawValue)) {
            counts[player.dateGroup.rawValue] = 0;
        }
        counts[player.dateGroup.rawValue]! += 1;
    }
    //=========================

    return counts
}

Answer 2

使用属性的 rawValue 和字典查找中的 default 总数 0 来计算总值：

func createIconCount(playerHand: [Card] ) -> [String : Int] {
    
    var counts: [String: Int] = [:]

    for card in playerHand {
        counts[card.dateGroup.rawValue, default: 0] += 1
        counts[card.countryGroup.rawValue, default: 0] += 1
        counts[card.icon1.rawValue, default: 0] += 1
        // Don't count icon2 if it is the same as icon1
        if card.icon2 != card.icon1 {
            counts[card.icon2.rawValue, default: 0] += 1
        }
    }

    return counts
}

正在创建带有图标的卡片索引数组：

您可以创建一个玩家手牌索引数组，而不是创建带有匹配图标的牌数。首先将 .enumerated 添加到 playerHand 以获取索引，然后将 idx 附加到数组。这里我们使用 [] 作为默认字典查找值，如果不存在则创建一个空数组。

func createIconCount(playerHand: [Card] ) -> [String : [Int]] {
    
    var counts: [String: [Int]] = [:]

    for (idx, card) in playerHand.enumerated() {
        counts[card.dateGroup.rawValue, default: []].append(idx)
        counts[card.countryGroup.rawValue, default: []].append(idx)
        counts[card.icon1.rawValue, default: []].append(idx)
        // Don't count icon2 if it is the same as icon1
        if card.icon2 != card.icon1 {
            counts[card.icon2.rawValue, default: []].append(idx)
        }
    }

    return counts
}

计算 Swift 5 中结构数组数组中的元素数

Counting number of elements in an array of array of struct in Swift 5

arrays

counting

swift