配置Spring Boot安全,允许路径)未授权401

Configuring Springboot security, permitted path(s) not authorised 401

我有一个 Springboot REST API,它有端点

我已按如下方式设置我的安全 class;

@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    UserDetailsService userDetailsService;

    /* This sets up the security on specified paths according to role of client */
    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.csrf().disable()
                .httpBasic()
                .and().authorizeRequests()
                .antMatchers("/api/quizzes/**").hasRole("USER")
//                .antMatchers("/api/register/").permitAll() // have tried this, still 401
                .antMatchers("/**").permitAll() // does not permit `/api/register` but does `/` and `h2- 
                                                // console
                .and().headers().frameOptions().disable();
    }

    /* This sets up the user roles by searching the database for a match, so they can access the 
    endpoints configured above */
    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService);

    }

    @Bean
    public PasswordEncoder getPasswordEncoder() {
        return NoOpPasswordEncoder.getInstance();
    }
}

现在,当我尝试在 Postman 中访问 /api/register 时,响应是 401 unauthorised。我可以访问 /。我知道 /** 是这个目录和任何子目录的通配符,所以它应该匹配 root 和 /api/register,以及 permitAll()?

编辑:更多信息

我想知道,所有 /api/quizzes 端点都在 QuizController 下,但是 /api/register 端点在它自己的 @RestController 控制器 class 下。我错过了注释吗?看不到,设置一样。

我知道 Spring 没有查看我的 UserService,因为没有打印 sout 消息。昨天我确实在某个时候使用了它,它正在从数据库 table 中获取 User。我不确定发生了什么变化。

这是我的用户服务


@Service
public class UserService implements UserDetailsService {

    @Autowired
    static UserRepository userRepository;

    @Override
    public UserDetails loadUserByUsername(String email) {

        Optional<User> user = userRepository.findByEmail(email);
        System.out.println("loadByUsername called");
        if (user.isPresent()) {
            System.out.println("loadUserByUsername called: user.isPresent() = true");
            return new MyUserDetails(user.get().getEmail(), user.get().getPassword());
        } else {
            throw new UsernameNotFoundException("User: " + email + " not found");
        }
    }

    public static void saveUserToDB(User user) {

        if (user.getPassword().length() < 5) {
            throw new UsernameNotFoundException("password too short.");
        }

        Pattern pattern = Pattern.compile("simon\.aust@hotmail\.com");
        Matcher matcher = pattern.matcher(user.getEmail());

        if (!matcher.matches()) {
            throw new UsernameNotFoundException("email not correct format");
        }

        userRepository.save(user);
    }

}

用户存储库

public interface UserRepository extends CrudRepository<User, Long> {

    Optional<User> findByEmail(String email);

}

我的用户详细信息

public class MyUserDetails implements UserDetails {

    private final String username;
    private final String password;

    public MyUserDetails(String username, String password) {
        this.username = username;
        this.password = password;
    }

    @Override
    public Collection<? extends GrantedAuthority> getAuthorities() {
        return Arrays.asList(new SimpleGrantedAuthority("ROLE_USER"));
    }

    @Override
    public String getPassword() {
        return password;
    }

    @Override
    public String getUsername() {
        return username;
    }

    @Override
    public boolean isAccountNonExpired() {
        return true;
    }

    @Override
    public boolean isAccountNonLocked() {
        return true;
    }

    @Override
    public boolean isCredentialsNonExpired() {
        return true;
    }

    @Override
    public boolean isEnabled() {
        return true;
    }
}

编辑2; 通过内存中身份验证,我可以使用某些端点进行身份验证,但同样不能 /api/register

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception{
    
        auth.inMemoryAuthentication()
           .passwordEncoder(org.springframework.security.crypto.password.NoOpPasswordEncoder.getInstance())
                .withUser("user1")
                .password("password")
                .roles("USER");

}
    

试试这个:

@Override
protected void configure(HttpSecurity http) throws Exception {
    http
            .csrf().disable()
            .httpBasic()
            .and()
            .authorizeRequests()
            .antMatchers("/api/register/**").permitAll()
            .antMatchers("/api/quizzes/**").authenticated()
            .and()
            .sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS);
}

@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
    auth
            .userDetailsService(userDetailsService)
            .passwordEncoder(passwordEncoder);
}

这是我费了好大劲才改过来的错误。 由于我的天真和忽略了我处理异常的位置,我实际上是在某些 if/else 语句上返回带有自定义异常的 HTTP 状态。这让我误以为用户身份验证不起作用,而事实上它是有效的。 今日课程:使用断点和调试 :)