为什么 object.name 中的这些更改会导致不同的显示？

Question

我正在做一些简单的事情 - 绘制一系列图块，将它们放置在库中并在属性中进行链接，然后创建一个由随机选择的图块组成的大矩形。我还希望能够独立访问每个图块，因此我为每个图块使用了数组类型的命名系统。然后我遇到了这种情况，如果我使用变量彼此相邻的命名方案（而不是拆分他们用字符串文字）。

谁能解释一下原因： floor.name = "floorR"+字符串(n)+"C"+字符串(m); //表现正常，如预期

给出不同的显示结果： floor.name = "floorRC"+字符串(n)+字符串(m); //转换为下面代码中的注释，往往会放错tile

在以下最少的、可重现的提取物中：

//initialize standard counters
var i:uint = 0;
var j:uint = 0;
var m:uint = 0;
var n:uint = 0;
var lvlAdd:uint = 0; //designates add level (display)


//starting location of tiles
var bigMapX0:uint = 15;
var bigMapY0:uint = 75;

//dimensions of completed tile set
var bigMapWidth:uint = 375;
var bigMapHeight:uint = 675;


//initialize max row and column
var rowMax = 25;
var columnMax = 15;

//initialize unit-cell dimensions
var cellWidth = bigMapWidth/columnMax;
var cellHeight = bigMapHeight/rowMax;

//backdrop rectangle: black
var backFieldColor = 0x000000;
var backField:Shape = new Shape();
backField.graphics.beginFill(backFieldColor);
backField.graphics.drawRect(bigMapX0,bigMapY0,bigMapWidth,bigMapHeight); //dimensions of standard stage
backField.graphics.endFill();
this.addChildAt(backField,lvlAdd); //sets black as bottommost static backdrop

//set down tiles
var floor:DisplayObject;
var floorName:DisplayObject;
for (m=0; m<columnMax; m++) {
    for (n=0; n<rowMax; n++){
        floor = new Floor0(); //"floor" is in the library with linkage named Floor0 (part of an assortment of tiles randomly chosen, and not shown here to reduce lines of code
        //floor.name = "floorR"+String(n)+"C"+String(m); 
        floor.name = "floorRC"+String(n)+String(m); //error happens if this line is used instead of the commented line above it
        lvlAdd++;
        this.addChildAt(floor, lvlAdd);
        //floorName = this.getChildByName("floorR"+String(n)+"C"+String(m));
        floorName = this.getChildByName("floorRC"+String(n)+String(m)); //this is the paired statement with the floor.name 3 lines prior, and causes an error in display if used instead of the commented line above it
        floorName.x = bigMapX0 + m*cellWidth;
        floorName.y = bigMapY0 + n*cellHeight;
    }
}

this.stop();

谢谢你的时间。

格雷格

Answer 1

因为这个

"floorRC"+String(n)+String(m);

会在某些情况下对不同的 n 和 m 产生相同的结果，例如

(n = 1, m = 12)
(n = 11, m = 2)

另一个

"floorR"+String(n)+"C"+String(m);

将始终生成唯一的 String。

为什么 object.name 中的这些更改会导致不同的显示？

Why do these changes in object.name result in different displays?

actionscript-3

flash

linkage

displayobject