如何制作开关，它们在单击时有自己的 StatelessWidget Class 切换？

Question

我试图让两个开关在点击时在打开和关闭之间切换。我为开关的设计创建了一个 StatelessWidget class。但是，当我使用它并在我的用户界面 class 中调用 class 时，开关不会改变状态。如何更新我的代码以允许更改？

import 'package:flutter/material.dart';

class NotificationItem extends StatelessWidget {
  NotificationItem(
      {@required this.title,
      @required this.pushStatus,
      @required this.emailStatus});

  String title;
  bool pushStatus;
  bool emailStatus;

  @override
  Widget build(BuildContext context) {
    return Row(
      children: <Widget>[
        Expanded(
          child: Padding(
            padding: EdgeInsets.all(20),
            child: Text(
              title,
              style: TextStyle(
                  fontFamily: kFontFamilyNormal,
                  fontSize: 17,
                  color: AppColor.text,
                  fontWeight: FontWeight.w500),
            ),
          ),
        ),
        Expanded(
          child: Row(
            mainAxisAlignment: MainAxisAlignment.spaceEvenly,
            children: <Widget>[
              Switch(
                value: emailStatus,
                onChanged: (value) {
                  emailStatus = value;
                  print(emailStatus);
                },
                activeTrackColor: AppColor.primaryColorDark,
                activeColor: AppColor.white,
              ),
              Switch(
                value: pushStatus,
                onChanged: (value) {
                  pushStatus = value;
                  print(pushStatus);
                },
                activeTrackColor: AppColor.primaryColorDark,
                activeColor: AppColor.white,
              ),
            ],
          ),
        ),
      ],
    );
  }
}

下面的代码是我调用它的方式：

NotificationItem(
                title: 'New messages',
                emailStatus: emailStatus,
                pushStatus: pushStatus,
              )

Answer 1

为了改变UI状态你必须使用StatefulWidget 您可以将 NotificationItem 转换为 StatefulWidget 或将每个开关提取到其自己的 StatefulWidget

或者我建议您使用 Get libary or Stacked

查看 MVVM 模式

您的 Get 代码如下所示：

import 'package:flutter/material.dart';
import 'package:get/get.dart';

class NotificationItemViewModel extends GetxController {
  bool pushStatus = false;
  bool emailStatus = false;

  void changeEmailStatus(bool newValue) {
    emailStatus = newValue;
    print(emailStatus);
    update();
  }

  void changePushStatus(bool newValue) {
    pushStatus = newValue;
    print(pushStatus);
    update();
  }
}

class NotificationItem extends StatelessWidget {
  const NotificationItem({@required this.title});

  final String title;

  @override
  Widget build(BuildContext context) {
    return GetBuilder<NotificationItemViewModel>(
      init: NotificationItemViewModel(),
      builder: (model) {
        return Row(
          children: <Widget>[
            Expanded(
              child: Padding(
                padding: const EdgeInsets.all(20),
                child: Text(
                  title,
                  style: TextStyle(
                    fontFamily: kFontFamilyNormal,
                    fontSize: 17,
                    color: AppColor.text,
                    fontWeight: FontWeight.w500,
                  ),
                ),
              ),
            ),
            Expanded(
              child: Row(
                mainAxisAlignment: MainAxisAlignment.spaceEvenly,
                children: <Widget>[
                  Switch(
                    value: model.emailStatus,
                    onChanged: model.changeEmailStatus,
                    activeTrackColor: AppColor.primaryColorDark,
                    activeColor: AppColor.white,
                  ),
                  Switch(
                    value: model.pushStatus,
                    onChanged: model.changePushStatus,
                    activeTrackColor: AppColor.primaryColorDark,
                    activeColor: AppColor.white,
                  ),
                ],
              ),
            ),
          ],
        );
      },
    );
  }
}

Answer 2

既然你要改变状态，它必须是一个StatefulWidget。像这样：

class NotificationItem extends StatefulWidget {
  const NotificationItem({
    Key key,
    @required this.title,
    @required this.pushStatus,
    @required this.emailStatus,
  });
  final String title;
  final bool pushStatus;
  final bool emailStatus;

  @override
  _NotificationItemState createState() => _NotificationItemState();
}

class _NotificationItemState extends State<NotificationItem> {
  String _title;
  bool _pushStatus;
  bool _emailStatus;
  
  void initState() {
    super.initState();
    _title = widget.title;
    _pushStatus = widget.pushStatus;
    _emailStatus = widget.emailStatus;
  }

  @override
  Widget build(BuildContext context) {
    return Row(
      children: <Widget>[
        Expanded(
          child: Padding(
            padding: const EdgeInsets.all(16.0),
            child: Text(
              _title,
            ),
          ),
        ),
        Expanded(
          child: Row(
            mainAxisAlignment: MainAxisAlignment.spaceEvenly,
            children: <Widget>[
              Switch(
                value: _emailStatus,
                onChanged: (value) {
                  setState(() => _emailStatus = value);
                  print(_emailStatus);
                },
              ),
              Switch(
                value: _pushStatus,
                onChanged: (value) {
                  setState(() => _pushStatus = value);
                  print(_pushStatus);
                },
              ),
            ],
          ),
        ),
      ],
    );
  }
}

如何制作开关，它们在单击时有自己的 StatelessWidget Class 切换？

How can I make the switches, which have their own StatelessWidget Class toggle when clicked?

android-studio

flutter

dart

uiswitch

statefulwidget