无法查看美国各州的热图
Not able to view US-states heatmap
我编写了以下代码来加热美国各州的热图。但是我无法在 Google Colab 中获取输出图像。
州代码是美国特定州的两个字母代码。
temp = pd.DataFrame(project_data.groupby("school_state")["project_is_approved"].apply(np.mean)).reset_index()
temp.columns = ['state_code', 'num_proposals']
scl = [[0.0, 'rgb(242,240,247)'],[0.2, 'rgb(218,218,235)'],[0.4, 'rgb(188,189,220)'],\
[0.6, 'rgb(158,154,200)'],[0.8, 'rgb(117,107,177)'],[1.0, 'rgb(84,39,143)']]
data = [ dict(
type='choropleth',
colorscale = scl,
autocolorscale = False,
locations = temp['state_code'],
z = temp['num_proposals'].astype(float),
locationmode = 'USA-states',
text = temp['state_code'],
marker = dict(line = dict (color = 'rgb(255,255,255)',width = 2)),
colorbar = dict(title = "% of pro")
) ]
layout = dict(
title = 'Project Proposals % of Acceptance Rate by US States',
geo = dict(
scope='usa',
projection=dict( type='albers usa' ),
showlakes = True,
lakecolor = 'rgb(255, 255, 255)',
),
)
fig = dict(data=data, layout=layout)
offline.iplot(fig, filename='us-map-heat-map')
我导入了以下库:
from chart_studio import plotly
import plotly.offline as offline
import plotly.graph_objs as go
offline.init_notebook_mode()
from collections import Counter
import chart_studio.plotly as py
使用您的数据尝试以下代码:
(我试着把你的变量放在正确的位置)
choropleth = go.Choropleth(
locations=temp['state_code'],
locationmode='USA-states',
z = temp['num_proposals'].astype(float),
zmin = 0,
zmax = max(temp['num_proposals'].astype(float)),
colorscale=scl,
autocolorscale=False,
text='Proposals',
marker_line_color='white',
colorbar_title="% Acceptance Rate"
)
fig = go.Figure(data=choropleth)
fig.update_layout(
title_text='Project Proposals % of Acceptance Rate by US States',
geo = dict(
scope='usa',
projection=go.layout.geo.Projection(type = 'albers usa'),
showlakes=True,
lakecolor='rgb(255, 255, 255)'),
)
fig.show()
此代码的工作原理是使用您的数据创建 Plotly Choropleth Graph Object,然后将其 object 加载到 Plotly Figure Graph Object,然后更新布局(以获得正确的标题和缩放),最后显示图形。
我编写了以下代码来加热美国各州的热图。但是我无法在 Google Colab 中获取输出图像。
州代码是美国特定州的两个字母代码。
temp = pd.DataFrame(project_data.groupby("school_state")["project_is_approved"].apply(np.mean)).reset_index()
temp.columns = ['state_code', 'num_proposals']
scl = [[0.0, 'rgb(242,240,247)'],[0.2, 'rgb(218,218,235)'],[0.4, 'rgb(188,189,220)'],\
[0.6, 'rgb(158,154,200)'],[0.8, 'rgb(117,107,177)'],[1.0, 'rgb(84,39,143)']]
data = [ dict(
type='choropleth',
colorscale = scl,
autocolorscale = False,
locations = temp['state_code'],
z = temp['num_proposals'].astype(float),
locationmode = 'USA-states',
text = temp['state_code'],
marker = dict(line = dict (color = 'rgb(255,255,255)',width = 2)),
colorbar = dict(title = "% of pro")
) ]
layout = dict(
title = 'Project Proposals % of Acceptance Rate by US States',
geo = dict(
scope='usa',
projection=dict( type='albers usa' ),
showlakes = True,
lakecolor = 'rgb(255, 255, 255)',
),
)
fig = dict(data=data, layout=layout)
offline.iplot(fig, filename='us-map-heat-map')
我导入了以下库:
from chart_studio import plotly
import plotly.offline as offline
import plotly.graph_objs as go
offline.init_notebook_mode()
from collections import Counter
import chart_studio.plotly as py
使用您的数据尝试以下代码:
(我试着把你的变量放在正确的位置)
choropleth = go.Choropleth(
locations=temp['state_code'],
locationmode='USA-states',
z = temp['num_proposals'].astype(float),
zmin = 0,
zmax = max(temp['num_proposals'].astype(float)),
colorscale=scl,
autocolorscale=False,
text='Proposals',
marker_line_color='white',
colorbar_title="% Acceptance Rate"
)
fig = go.Figure(data=choropleth)
fig.update_layout(
title_text='Project Proposals % of Acceptance Rate by US States',
geo = dict(
scope='usa',
projection=go.layout.geo.Projection(type = 'albers usa'),
showlakes=True,
lakecolor='rgb(255, 255, 255)'),
)
fig.show()
此代码的工作原理是使用您的数据创建 Plotly Choropleth Graph Object,然后将其 object 加载到 Plotly Figure Graph Object,然后更新布局(以获得正确的标题和缩放),最后显示图形。