Oracle 查询优化建议
Oracle query optimization recommendation
下面的查询只需要很长时间,下面的谓词只用于获取唯一的记录,因此想知道是否有不同的方法可以重写相同的查询而无需多次调用下面的谓词,以获得唯一的编号.
select max(c.id) from plocation c where c.ids = y.ids and c.idc = y.idc)
select max(cr.id) from plocation_log cr where cr.ids = yt.ids and cr.idc = yt.idc)
select max(pr.id) from patentpr where pr.ids = p.ids and pr.idc = p.idc)
我的完整示例查询
SELECT to_char(p.pid) AS patentid,
p.name,
x.dept,
y.location
FROM patent p
JOIN pdetails x ON p.pid = x.pid AND x.isactive = 1
JOIN plocation y
ON y.idr = p.idr
AND y.idc = p.idc
AND y.id = *(select max(c.id) from plocation c where c.ids = y.ids and c.idc = y.idc)*
AND y.idopstype in (36, 37)
JOIN plocation_log yt
ON yt.idr = y.idr
AND yt.idc= y.idc
AND yt.id = *(select max(cr.id) from plocation_log cr where cr.ids = yt.ids and cr.idc = yt.idc)*
AND yt.idopstype in (36,37)
WHERE
p.idp IN (10,20,30)
AND p.id = *(select max(pr.id) from patent pr where pr.ids = p.ids and pr.idc = p.idc)*
AND p.idopstype in (36,37)
正如 The Impaler 评论的那样,一种选择是使用分析函数而不是相关子查询。这个想法是使用 RANK()
对子查询中的记录进行排名,然后在外部查询(连接条件或 WHERE
子句)中进行过滤。
考虑:
SELECT to_char(p.pid) AS patentid,
p.name,
x.dept,
y.location
FROM (SELECT p.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM patinet) p
JOIN pdetails x ON p.pid = x.pid AND x.isactive = 1
JOIN (SELECT y.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM plocation y) y
ON y.idr = p.idr
AND y.idc = p.idc
AND y.idopstype in (36, 37)
AND y.rn = 1
JOIN (SELECT y.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM plocation_log yt) yt
ON yt.idr = y.idr
AND yt.idc= y.idc
AND yt.idopstype in (36,37)
AND yt.rn = 1
WHERE
p.idp IN (10,20,30)
AND p.idopstype in (36,37)
AND p.rn = 1
考虑加入聚合 CTE 以计算每组 MAX
值一次,而不是对每个外部查询行按行 MAX
计算。此外,请务必使用信息量更大的 table 别名,而不是 a, b, c
或 x, y, z
样式。
WITH loc_max AS
(select ids, idc, max(id) as max_id from plocation group ids, idc)
, log_max AS
(select ids, idc, max(id) as max_id from plocation_log group by ids, idc)
, pat_max AS
(select ids, idc, max(id) as max_id from patent pr group by ids, idc)
SELECT to_char(pat.pid) AS patentid
, pat.name
, det.dept
, loc.location
FROM patent pat
JOIN pdetails det
ON pat.pid = det.pid
AND det.isactive = 1
JOIN plocation loc
ON loc.idr = pat.idr
AND loc.idc = pat.idc
AND loc.idopstype IN (36, 37)
JOIN loc_max -- ADDED CTE JOIN
ON loc.id = loc_max.max_id
AND loc.ids = loc_max.ids
AND loc.idc = loc_max.idc
JOIN plocation_log log
ON log.idr = log.idr
AND log.idc = log.idc
AND log.idopstype in (36,37)
JOIN log_max -- ADDED CTE JOIN
ON log.id = log_max.max_id
AND log.ids = log_max.ids
AND log.idc = log_max.idc
JOIN pat_max -- ADDED CTE JOIN
ON pat.id = pat_max.max_id
AND pat.ids = pat_max.ids
AND pat.idc = pat_max.idc
WHERE pat.idp IN (10, 20, 30)
AND pat.idopstype IN (36, 37)
下面的查询只需要很长时间,下面的谓词只用于获取唯一的记录,因此想知道是否有不同的方法可以重写相同的查询而无需多次调用下面的谓词,以获得唯一的编号.
select max(c.id) from plocation c where c.ids = y.ids and c.idc = y.idc)
select max(cr.id) from plocation_log cr where cr.ids = yt.ids and cr.idc = yt.idc)
select max(pr.id) from patentpr where pr.ids = p.ids and pr.idc = p.idc)
我的完整示例查询
SELECT to_char(p.pid) AS patentid,
p.name,
x.dept,
y.location
FROM patent p
JOIN pdetails x ON p.pid = x.pid AND x.isactive = 1
JOIN plocation y
ON y.idr = p.idr
AND y.idc = p.idc
AND y.id = *(select max(c.id) from plocation c where c.ids = y.ids and c.idc = y.idc)*
AND y.idopstype in (36, 37)
JOIN plocation_log yt
ON yt.idr = y.idr
AND yt.idc= y.idc
AND yt.id = *(select max(cr.id) from plocation_log cr where cr.ids = yt.ids and cr.idc = yt.idc)*
AND yt.idopstype in (36,37)
WHERE
p.idp IN (10,20,30)
AND p.id = *(select max(pr.id) from patent pr where pr.ids = p.ids and pr.idc = p.idc)*
AND p.idopstype in (36,37)
正如 The Impaler 评论的那样,一种选择是使用分析函数而不是相关子查询。这个想法是使用 RANK()
对子查询中的记录进行排名,然后在外部查询(连接条件或 WHERE
子句)中进行过滤。
考虑:
SELECT to_char(p.pid) AS patentid,
p.name,
x.dept,
y.location
FROM (SELECT p.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM patinet) p
JOIN pdetails x ON p.pid = x.pid AND x.isactive = 1
JOIN (SELECT y.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM plocation y) y
ON y.idr = p.idr
AND y.idc = p.idc
AND y.idopstype in (36, 37)
AND y.rn = 1
JOIN (SELECT y.*, RANK() OVER(PARTITION BY ids, idc ORDER BY id) rn FROM plocation_log yt) yt
ON yt.idr = y.idr
AND yt.idc= y.idc
AND yt.idopstype in (36,37)
AND yt.rn = 1
WHERE
p.idp IN (10,20,30)
AND p.idopstype in (36,37)
AND p.rn = 1
考虑加入聚合 CTE 以计算每组 MAX
值一次,而不是对每个外部查询行按行 MAX
计算。此外,请务必使用信息量更大的 table 别名,而不是 a, b, c
或 x, y, z
样式。
WITH loc_max AS
(select ids, idc, max(id) as max_id from plocation group ids, idc)
, log_max AS
(select ids, idc, max(id) as max_id from plocation_log group by ids, idc)
, pat_max AS
(select ids, idc, max(id) as max_id from patent pr group by ids, idc)
SELECT to_char(pat.pid) AS patentid
, pat.name
, det.dept
, loc.location
FROM patent pat
JOIN pdetails det
ON pat.pid = det.pid
AND det.isactive = 1
JOIN plocation loc
ON loc.idr = pat.idr
AND loc.idc = pat.idc
AND loc.idopstype IN (36, 37)
JOIN loc_max -- ADDED CTE JOIN
ON loc.id = loc_max.max_id
AND loc.ids = loc_max.ids
AND loc.idc = loc_max.idc
JOIN plocation_log log
ON log.idr = log.idr
AND log.idc = log.idc
AND log.idopstype in (36,37)
JOIN log_max -- ADDED CTE JOIN
ON log.id = log_max.max_id
AND log.ids = log_max.ids
AND log.idc = log_max.idc
JOIN pat_max -- ADDED CTE JOIN
ON pat.id = pat_max.max_id
AND pat.ids = pat_max.ids
AND pat.idc = pat_max.idc
WHERE pat.idp IN (10, 20, 30)
AND pat.idopstype IN (36, 37)