在 Swift 中获取和解码未知错误
Fetching and decoding unkwown error in Swift
我正在尝试获取数据并将其解码为结构,然后在列表中显示该数据。
我使用 quicktype.io 将 JSON 解析为 Swift。这部分好像还行。
struct Response: Codable {
var results: [User]
}
struct User: Codable {
let id: String
let isActive: Bool
let name: String
let age: Int
let company, email, address, about: String
let registered: Date
let tags: [String]
let friends: [Friend]
}
struct Friend: Codable {
let id, name: String
}
这是代码的其余部分,我在其中尝试解码数据(发生错误的地方)。这里是 link 到 JSON.
struct ContentView: View {
@State private var users = [User]()
var body: some View {
List {
ForEach(users, id: \.id) { user in
Text(user.name)
}
}.onAppear(perform: loadData)
}
func loadData() {
guard let url = URL(string: "https://www.hackingwithswift.com/samples/friendface.json") else {
print("Invalid URL")
return
}
let request = URLRequest(url: url)
URLSession.shared.dataTask(with: request) { data, response, error in
if let data = data {
if let decodedResponse = try? JSONDecoder().decode(Response.self, from: data) {
// we have good data – go back to the main thread
DispatchQueue.main.async {
// update our UI
print(decodedResponse.results)
users = decodedResponse.results
}
// everything is good, so we can exit
return
}
}
// if we're still here it means there was a problem
print("Fetch failed: \(error?.localizedDescription ?? "Unknown error")")
}.resume()
}
}
您必须根据类型 [User]
而不是 Response
进行解码。查看响应,您会发现顶级 JSON
是 Array
,而不是 Dictionary
。此外,更新您的代码以获得有意义的错误消息。使用 do try catch
语法代替 if let try?
.
func loadData() {
guard let url = URL(string: "https://www.hackingwithswift.com/samples/friendface.json") else {
print("Invalid URL")
return
}
let request = URLRequest(url: url)
URLSession.shared.dataTask(with: request) { data, response, error in
if let data = data {
do {
let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .iso8601
let users = try decoder.decode([User].self, from: data)
DispatchQueue.main.async {
print(users)
self.users = users
}
} catch {
print(error)
}
} else {
// if we're still here it means there was a problem
print("Fetch failed: \(error?.localizedDescription ?? "Unknown error")")
}
}.resume()
}
更新:另外,需要添加dateDecodingStrategy
才能使解码正常工作。
我正在尝试获取数据并将其解码为结构,然后在列表中显示该数据。 我使用 quicktype.io 将 JSON 解析为 Swift。这部分好像还行。
struct Response: Codable {
var results: [User]
}
struct User: Codable {
let id: String
let isActive: Bool
let name: String
let age: Int
let company, email, address, about: String
let registered: Date
let tags: [String]
let friends: [Friend]
}
struct Friend: Codable {
let id, name: String
}
这是代码的其余部分,我在其中尝试解码数据(发生错误的地方)。这里是 link 到 JSON.
struct ContentView: View {
@State private var users = [User]()
var body: some View {
List {
ForEach(users, id: \.id) { user in
Text(user.name)
}
}.onAppear(perform: loadData)
}
func loadData() {
guard let url = URL(string: "https://www.hackingwithswift.com/samples/friendface.json") else {
print("Invalid URL")
return
}
let request = URLRequest(url: url)
URLSession.shared.dataTask(with: request) { data, response, error in
if let data = data {
if let decodedResponse = try? JSONDecoder().decode(Response.self, from: data) {
// we have good data – go back to the main thread
DispatchQueue.main.async {
// update our UI
print(decodedResponse.results)
users = decodedResponse.results
}
// everything is good, so we can exit
return
}
}
// if we're still here it means there was a problem
print("Fetch failed: \(error?.localizedDescription ?? "Unknown error")")
}.resume()
}
}
您必须根据类型 [User]
而不是 Response
进行解码。查看响应,您会发现顶级 JSON
是 Array
,而不是 Dictionary
。此外,更新您的代码以获得有意义的错误消息。使用 do try catch
语法代替 if let try?
.
func loadData() {
guard let url = URL(string: "https://www.hackingwithswift.com/samples/friendface.json") else {
print("Invalid URL")
return
}
let request = URLRequest(url: url)
URLSession.shared.dataTask(with: request) { data, response, error in
if let data = data {
do {
let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .iso8601
let users = try decoder.decode([User].self, from: data)
DispatchQueue.main.async {
print(users)
self.users = users
}
} catch {
print(error)
}
} else {
// if we're still here it means there was a problem
print("Fetch failed: \(error?.localizedDescription ?? "Unknown error")")
}
}.resume()
}
更新:另外,需要添加dateDecodingStrategy
才能使解码正常工作。