Hackerrank 稀疏数组

Hackerrank Sparse Arrays

import java.io.*;
import java.util.*;

class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int nStrings = sc.nextInt();
        String entries[] = new String[nStrings];
        for (int i=0;i<nStrings;i++)
            entries[i] = sc.nextLine();

        sc.nextLine();

        int nQueries = sc.nextInt();
        String queries[] = new String[nQueries];
        for (int i=0;i<nQueries;i++)
            queries[i] = sc.nextLine();

        sc.nextLine();

        int result[] = new int[nQueries];
        for (int i=0;i<nQueries;i++)
            result[i] = 0;

        for (int i=0;i<nQueries;i++){
            for (int j=0;j<nStrings;j++){
                if (queries[i].equals(entries[j]))
                    result[i]++;
                else
                    continue;
            }
        }
        System.out.println(Arrays.toString(result));
    }
}

谁能帮我解决这个问题输出不太正确但代码似乎是正确的。似乎在比较查询和条目时存在一些问题,因为针对此输入交换了特定索引中的正确元素

4
aba
baba
aba
xbxa
3
aba
xbxa
s

输出为 [1, 2, 0] 但应该是 [2,1,0]

您在错误的步骤中使用了 sc.nextLine(); 指令...您应该在 sc.nextInt();.

下面的代码将通过所有测试用例...在您的代码进行一些更改后。

import java.io.*;
import java.util.*;

class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int nStrings = sc.nextInt();
        sc.nextLine();
        String entries[] = new String[nStrings];
        for (int i=0;i<nStrings;i++)
            entries[i] = sc.nextLine();


        int nQueries = sc.nextInt();
        sc.nextLine();
        String queries[] = new String[nQueries];
        for (int i=0;i<nQueries;i++)
            queries[i] = sc.nextLine();

        int result[] = new int[nQueries];
        for (int i=0;i<nQueries;i++)
            result[i] = 0;



        for (int i=0;i<nQueries;i++){
            for (int j=0;j<nStrings;j++){
                if (queries[i].equals(entries[j]))
                    result[i]++;
            }
        }
        
        for(int i=0;i<nQueries;i++)
            System.out.println(result[i]);
    }
}