Cypher 查询 return 图作为对象，其中每个父节点包含其子节点的数组？

Question

我有一张如下图所示的图表：

我必须使用什么密码查询才能return将图形作为对象，其中每个父节点都包含其子节点的数组？

示例：

state: {
  name: 'New York'
  publishingCompanies: [
    {
      name: 'Penguin'
      authors: [
        {
          name: 'George Orwell',
          books: [
            { name: 'Why I Write'},
            { name: 'Animal Farm'},
            { name: '1984' }
          ]
        },
        {
          name: 'Vladimir Nobokov'
          books: [
            { name: 'Lolita' }
          ]
        },
        ...
      ]
    },
    { 
      name: 'Random House',
      authors: [
        ...
      ]
    }
  ]
}

我尝试使用 apoc.convert.toTree，但它 return 编辑了从 State 到 Book 的路径数组。

Answer 1

这应该 return state 对象（假设状态名称是通过 stateName parameter 传入的）：

MATCH (s:State)
WHERE s.name = $stateName
OPTIONAL MATCH (s)-[:IS_STATE_OF]->(c)
OPTIONAL MATCH (c)-[:PUBLISHED_FOR]->(a)
OPTIONAL MATCH (a)-[:WROTE]->(b)
WITH s, c, a, CASE WHEN b IS NULL THEN [] ELSE COLLECT({name: b.name}) END AS books
WITH s, c, CASE WHEN a IS NULL THEN [] ELSE COLLECT({name: a.name, books: books}) END AS authors
WITH s, CASE WHEN c IS NULL THEN [] ELSE COLLECT({name: c.name, authors: authors}) END AS pcs
RETURN {name: s.name, publishingCompanies: pcs} AS state

Cypher 查询 return 图作为对象，其中每个父节点包含其子节点的数组？

Cypher query to return graph as object, where each parent node contains an array of its children?

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