SQL:Select条条目中"reviews"条的数量最多，然后按平均条数最高的条数排序

Question

我有以下代码：

select
  count(restaurants.id) as restaurant_count,
  `restaurants`.*,
  round(AVG(restaurant_reviews.rate), 1) as rate
from
  `restaurants`
  inner join `restaurant_reviews` on `restaurant_reviews`.`restaurant_id` = `restaurants`.`id`
group by
  `restaurants`.`id`
order by
  `restaurant_count` desc
limit
  3

这个returns我是这样的：

restaurant_count, id,     name     , rate
      25        , 12, Restaurant 12, 4.6
      22        , 08, Restaurant 08, 4.1
      17        , 19, Restaurant 19, 4.4

这意味着它 returns 拥有最多 restaurant_reviews 数量的前 3 家餐厅（评论数量显示在 restaurant_count）。我想要实现的是，之后，按比率降序排列这些结果。例如：

restaurant_count, id,     name     , rate
      25        , 12, Restaurant 12, 4.6
      17        , 19, Restaurant 19, 4.4
      22        , 08, Restaurant 08, 4.1

我该怎么做？我在 SQL 中写了所有内容，但也欢迎 laravel 查询构建器。

我尝试简单地将 order by 更改为：

order by
  `restaurant_count` desc,
  `rate` desc
limit
  3

但它会先按 restaurant_count 排序，之后只会按比率对具有相同数量 restaurant_count 的条目排序。这意味着每家拥有最大 restaurant_count 的餐厅将始终处于更高的位置，无论其价格如何。这就是问题。

Answer 1

使用子查询：

select r.*
from (select count(*) as review_count, r.*, round(avg(rr.rate), 1) as rate
      from restaurants r join
           restaurant_reviews rr
           on rr.restaurant_id = r.id
      group by r.id
      order by review_count desc
      limit 3
     ) r
order by rate desc;

SQL:Select条条目中"reviews"条的数量最多，然后按平均条数最高的条数排序

SQL: Select entries with the biggest amount of "reviews" and then order the result by the highest average rate of them

mysql

sql

query-builder

laravel

laravel-query-builder