如何将多个单独的 for 循环输出打印为 bash 中的列
how to print multiple separate for loop outputs as columns in bash
我有一个脚本，我想读取二进制值列表并按如下方式打印它们（在列中，但不一定相应地标记）-
binary decimal truncated truncated-decimal
等等
-后续列被越来越高的值顺序截断。到目前为止我只有 3 个。
for z in {1..3};
do
p2=$(for n2 in $(cat binary_primes.txt );
do echo $n2;
done) #prints original values
p10=$(for n10 in $(echo $p2);
do echo "ibase=2;$n10;obase=10" | bc;
done) #prints original values in decimal
a2=$(for y in $(cat binary_primes.txt );
do
xx=${y:0:${#y}-$z} 2>/dev/null; echo
$xx;
done) #original value truncated by 1 bit
a10=$(for y2 in $(echo $a2);
do echo "ibase=2;$y2;obase=10" | bc;
done) #the latter in decimal
b2=$(for x in $(cat binary_primes.txt );
do xx=${x:0:${#x}-$z} 2>/dev/null;
echo $xx;
done) #original value truncated by 2 bits
b10=$(for x2 in $(echo $b2);
do echo "ibase=2;$x2;obase=10" | bc;
done) #the latter in decimal
c2=$(for w in $(cat binary_primes.txt );
do xx=${w:0:${#w}-$z} 2>/dev/null;
echo $xx;
done) #original value truncated by 3 bits
c10=$(for w2 in $(echo $c2);
do echo "ibase=2;$w2;obase=10" | bc;
done) #the latter in decimal
echo $p2 $p10 $a2 $a10 $b2 $b10 $c2 $c10;
done
我试过使用 column -t、column -x、paste 和 join，但我总是收到错误。我想避免输出到一堆文本文件然后再阅读它们 - 最好保持这种独立。
我也想知道是否有人能告诉我最干净的方法是简单地忽略超过原始值位数的截断值的实例（即用大于“9”的值截断 100010101，等等） ). - 这就是所有 2>/dev/nulls 都在（笨拙地，我知道）试图避免的。
这是引用的文本文件的前 30 行，也是唯一（理想情况下）需要的文件：
100111101010011111101
100111101010011101001
100111101010011011001
100111101010011000101
100111101010010111111
100111101010010110101
100111101010010101111
100111101010010010001
100111101010001111111
100111101010001100001
100111101010001010101
100111101010001001101
100111101010000101011
100111101010000100011
100111101010000000001
100111101001111111011
100111101001111111001
100111101001111101111
100111101001111101101
100111101001110110011
100111101001110110001
100111101001110100111
100111101001110011111
100111101001110010101
100111101001110001111
100111101001110001101
100111101001101111011
100111101001101110101
100111101001101100011
100111101001101011001
输出文件会更长，因为它打印了很多截断，但基于原始数字扩展，我最终希望达到 21（文件中最大的位权重），但这里是再次比较前30行：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 10011110101001111110 649854
100111101010011111101 1299709 1001111010100111111 324927
100111101010011111101 1299709 100111101010011111 162463
100111101010011111101 1299709 10011110101001111 81231
100111101010011111101 1299709 1001111010100111 40615
100111101010011111101 1299709 100111101010011 20307
100111101010011111101 1299709 10011110101001 10153
100111101010011111101 1299709 1001111010100 5076
100111101010011111101 1299709 100111101010 2538
100111101010011111101 1299709 10011110101 1269
100111101010011111101 1299709 1001111010 634
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 10011110 158
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 100111 39
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 1001 9
100111101010011111101 1299709 100 4
100111101010011111101 1299709 10 2
100111101010011111101 1299709 1 1
100111101010011101001 1299689 100111101010011101001 1299689
100111101010011101001 1299689 10011110101001110100 649844
100111101010011101001 1299689 1001111010100111010 324922
100111101010011101001 1299689 100111101010011101 162461
100111101010011101001 1299689 10011110101001110 81230
100111101010011101001 1299689 1001111010100111 40615
100111101010011101001 1299689 100111101010011 20307
100111101010011101001 1299689 10011110101001 10153
100111101010011101001 1299689 1001111010100 5076
最终我想要第 5 列，它不会出现在标准输出中，但会在脚本运行时根据第 4 列中的值进行分解生成，然后 grepping/awking 这样就不会被截断将打印不是质数的值：
1299709: 1299709
649854: 2 3 3 79 457
324927: 3 3 79 457
162463: 7 23209
81231: 3 27077
40615: 5 8123
20307: 3 7 967
10153: 11 13 71
5076: 2 2 3 3 3 47
2538: 2 3 3 3 47
1269: 3 3 3 47
634: 2 317
317: 317
158: 2 79
79: 79
39: 3 13
19: 19
9: 3 3
4: 2 2
2: 2
1:
1299689: 1299689
649844: 2 2 13 12497
324922: 2 13 12497
162461: 13 12497
81230: 2 5 8123
40615: 5 8123
20307: 3 7 967
10153: 11 13 71
5076: 2 2 3 3 3 47
一旦 greped+awked 只有这些是质数：
1299709: 1299709
317: 317
79: 79
19: 19
2: 2
1299689: 1299689
我遇到的另一个问题是我不确定如何让两列继续打印相同的值，而其他列递增。
即这个：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 10 2
而不是这个：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010000101011 1299499 100111101 317
100111101010000000001 1299457 1001111 79
100111101001111111001 1299449 10011 19
100111101001110110011 1299379 10 2
所以我最终想要做的完整最终结果的前 30 行是：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 10 2
100111101010011101001 1299689 100111101010011101001 1299689
100111101010011101001 1299689 100111101 317
100111101010011101001 1299689 1001111 79
100111101010011101001 1299689 10011 19
100111101010011101001 1299689 10 2
100111101010011011001 1299673 100111101010011011001 1299673
100111101010011011001 1299673 100111101 317
100111101010011011001 1299673 1001111 79
100111101010011011001 1299673 10011 19
100111101010011011001 1299673 10 2
100111101010011000101 1299653 100111101010011000101 1299653
100111101010011000101 1299653 100111101 317
100111101010011000101 1299653 1001111 79
100111101010011000101 1299653 10011 19
100111101010011000101 1299653 10 2
100111101010010111111 1299647 100111101010010111111 1299647
100111101010010111111 1299647 100111101 317
100111101010010111111 1299647 1001111 79
100111101010010111111 1299647 10011 19
100111101010010111111 1299647 10 2
100111101010010110101 1299637 100111101010010110101 1299637
100111101010010110101 1299637 100111101 317
100111101010010110101 1299637 1001111 79
100111101010010110101 1299637 10011 19
100111101010010110101 1299637 10 2
要求似乎是从文件中读取（二进制）数字，并为每个值生成多行，显示（值，value/2，value/4，。 .., 值/(2^n))
解决方案是pure-bash，这意味着它将对相对较大的文件执行良好（无需重复调用'bc' 实用程序）。二进制转十进制是用bash算术表达式。
#! /bin/bash
while read b ; do
# Convert binary 'b' to decimal 'd'
d=$((2#$b))
bb=$b
dd=$d
b_len=${#b}
while (( dd > 0 )) ; do
printf "%s %d %-${b_len}s %d\n" $b $d $bb $dd
dd=$((dd/2))
bb=${bb:0:${#bb}-1}
done
done < binary_primes.txt
我有一个脚本，我想读取二进制值列表并按如下方式打印它们（在列中，但不一定相应地标记）-
binary decimal truncated truncated-decimal
等等
-后续列被越来越高的值顺序截断。到目前为止我只有 3 个。
for z in {1..3};
do
p2=$(for n2 in $(cat binary_primes.txt );
do echo $n2;
done) #prints original values
p10=$(for n10 in $(echo $p2);
do echo "ibase=2;$n10;obase=10" | bc;
done) #prints original values in decimal
a2=$(for y in $(cat binary_primes.txt );
do
xx=${y:0:${#y}-$z} 2>/dev/null; echo
$xx;
done) #original value truncated by 1 bit
a10=$(for y2 in $(echo $a2);
do echo "ibase=2;$y2;obase=10" | bc;
done) #the latter in decimal
b2=$(for x in $(cat binary_primes.txt );
do xx=${x:0:${#x}-$z} 2>/dev/null;
echo $xx;
done) #original value truncated by 2 bits
b10=$(for x2 in $(echo $b2);
do echo "ibase=2;$x2;obase=10" | bc;
done) #the latter in decimal
c2=$(for w in $(cat binary_primes.txt );
do xx=${w:0:${#w}-$z} 2>/dev/null;
echo $xx;
done) #original value truncated by 3 bits
c10=$(for w2 in $(echo $c2);
do echo "ibase=2;$w2;obase=10" | bc;
done) #the latter in decimal
echo $p2 $p10 $a2 $a10 $b2 $b10 $c2 $c10;
done
我试过使用 column -t、column -x、paste 和 join，但我总是收到错误。我想避免输出到一堆文本文件然后再阅读它们 - 最好保持这种独立。
我也想知道是否有人能告诉我最干净的方法是简单地忽略超过原始值位数的截断值的实例（即用大于“9”的值截断 100010101，等等） ). - 这就是所有 2>/dev/nulls 都在（笨拙地，我知道）试图避免的。
这是引用的文本文件的前 30 行，也是唯一（理想情况下）需要的文件：
100111101010011111101
100111101010011101001
100111101010011011001
100111101010011000101
100111101010010111111
100111101010010110101
100111101010010101111
100111101010010010001
100111101010001111111
100111101010001100001
100111101010001010101
100111101010001001101
100111101010000101011
100111101010000100011
100111101010000000001
100111101001111111011
100111101001111111001
100111101001111101111
100111101001111101101
100111101001110110011
100111101001110110001
100111101001110100111
100111101001110011111
100111101001110010101
100111101001110001111
100111101001110001101
100111101001101111011
100111101001101110101
100111101001101100011
100111101001101011001
输出文件会更长，因为它打印了很多截断，但基于原始数字扩展，我最终希望达到 21（文件中最大的位权重），但这里是再次比较前30行：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 10011110101001111110 649854
100111101010011111101 1299709 1001111010100111111 324927
100111101010011111101 1299709 100111101010011111 162463
100111101010011111101 1299709 10011110101001111 81231
100111101010011111101 1299709 1001111010100111 40615
100111101010011111101 1299709 100111101010011 20307
100111101010011111101 1299709 10011110101001 10153
100111101010011111101 1299709 1001111010100 5076
100111101010011111101 1299709 100111101010 2538
100111101010011111101 1299709 10011110101 1269
100111101010011111101 1299709 1001111010 634
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 10011110 158
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 100111 39
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 1001 9
100111101010011111101 1299709 100 4
100111101010011111101 1299709 10 2
100111101010011111101 1299709 1 1
100111101010011101001 1299689 100111101010011101001 1299689
100111101010011101001 1299689 10011110101001110100 649844
100111101010011101001 1299689 1001111010100111010 324922
100111101010011101001 1299689 100111101010011101 162461
100111101010011101001 1299689 10011110101001110 81230
100111101010011101001 1299689 1001111010100111 40615
100111101010011101001 1299689 100111101010011 20307
100111101010011101001 1299689 10011110101001 10153
100111101010011101001 1299689 1001111010100 5076
最终我想要第 5 列，它不会出现在标准输出中，但会在脚本运行时根据第 4 列中的值进行分解生成，然后 grepping/awking 这样就不会被截断将打印不是质数的值：
1299709: 1299709
649854: 2 3 3 79 457
324927: 3 3 79 457
162463: 7 23209
81231: 3 27077
40615: 5 8123
20307: 3 7 967
10153: 11 13 71
5076: 2 2 3 3 3 47
2538: 2 3 3 3 47
1269: 3 3 3 47
634: 2 317
317: 317
158: 2 79
79: 79
39: 3 13
19: 19
9: 3 3
4: 2 2
2: 2
1:
1299689: 1299689
649844: 2 2 13 12497
324922: 2 13 12497
162461: 13 12497
81230: 2 5 8123
40615: 5 8123
20307: 3 7 967
10153: 11 13 71
5076: 2 2 3 3 3 47
一旦 greped+awked 只有这些是质数：
1299709: 1299709
317: 317
79: 79
19: 19
2: 2
1299689: 1299689
我遇到的另一个问题是我不确定如何让两列继续打印相同的值，而其他列递增。
即这个：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 10 2
而不是这个：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010000101011 1299499 100111101 317
100111101010000000001 1299457 1001111 79
100111101001111111001 1299449 10011 19
100111101001110110011 1299379 10 2
所以我最终想要做的完整最终结果的前 30 行是：
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 10 2
100111101010011101001 1299689 100111101010011101001 1299689
100111101010011101001 1299689 100111101 317
100111101010011101001 1299689 1001111 79
100111101010011101001 1299689 10011 19
100111101010011101001 1299689 10 2
100111101010011011001 1299673 100111101010011011001 1299673
100111101010011011001 1299673 100111101 317
100111101010011011001 1299673 1001111 79
100111101010011011001 1299673 10011 19
100111101010011011001 1299673 10 2
100111101010011000101 1299653 100111101010011000101 1299653
100111101010011000101 1299653 100111101 317
100111101010011000101 1299653 1001111 79
100111101010011000101 1299653 10011 19
100111101010011000101 1299653 10 2
100111101010010111111 1299647 100111101010010111111 1299647
100111101010010111111 1299647 100111101 317
100111101010010111111 1299647 1001111 79
100111101010010111111 1299647 10011 19
100111101010010111111 1299647 10 2
100111101010010110101 1299637 100111101010010110101 1299637
100111101010010110101 1299637 100111101 317
100111101010010110101 1299637 1001111 79
100111101010010110101 1299637 10011 19
100111101010010110101 1299637 10 2
要求似乎是从文件中读取（二进制）数字，并为每个值生成多行，显示（值，value/2，value/4，。 .., 值/(2^n))
解决方案是pure-bash，这意味着它将对相对较大的文件执行良好（无需重复调用'bc' 实用程序）。二进制转十进制是用bash算术表达式。
#! /bin/bash
while read b ; do
# Convert binary 'b' to decimal 'd'
d=$((2#$b))
bb=$b
dd=$d
b_len=${#b}
while (( dd > 0 )) ; do
printf "%s %d %-${b_len}s %d\n" $b $d $bb $dd
dd=$((dd/2))
bb=${bb:0:${#bb}-1}
done
done < binary_primes.txt