如何在 Python 中循环我的倒数计时器？

Question

我正在尝试循环我的计时器，所以它会告诉我还剩多少秒。现在它只显示从启动脚本开始还剩多少秒，但我希望它每秒都在变化。 我要运行这个脚本 24/7，所以我需要实时结果。

我的计时器：

from datetime import datetime from threading import Timer import time x = datetime.now() y=x.replace(hour=12, minute=0, second=0) t=y-x secs=t.seconds

我在想while循环，但我不知道如何在这段代码中使用它。如果你愿意，你可以更改我的计时器我只想让它告诉我指定时间还剩多少秒。

我是怎么解决的：

from datetime import datetime from threading import Timer import time while True: time.sleep(1) x=datetime.today() y=x.replace(hour=17, minute=10, second=0) t=y-x secs=t.seconds

Answer 1

它“说”“你好！” 4:20 的每一天。您需要在线程上调用 time_to_sleep 或运行它。此外，您可以更改您的时间 (HOUR、MINUTE、SECOND) 和频率 (NEXT_DAY)

from datetime import datetime, timedelta

from time import sleep
HOUR = 4
MINUTE = 20
SECOND = 0
NEXT_DAY = 1

def time_to_sleep():
    a = datetime.now()
    a += timedelta(days=NEXT_DAY)

    a = a.replace(hour=HOUR, minute=MINUTE, second=SECOND)

    return (a - datetime.now()).total_seconds()

# you may wont to run this on a thread 
def your_print():
    while True:
        sleep(time_to_sleep())
        print("Hello!")

Answer 2

import time, datetime

designated_date = datetime.datetime(2021, 1, 6, 15, 8, 24) # designated_date
designated_time = time.mktime(designated_date.timetuple()) # designated unix time in seconds

while True:
    time.sleep(1)         # 1 second delay
    current_time = int(time.time())      # every second get current unix time
    left = designated_time - current_time # calculation how much seconds left to desingated time
    print(left) # print results

如何在 Python 中循环我的倒数计时器？

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