C中不同的数据类型
data types different in C
我们如何在 C 中声明并行数组。还有,如何在单个数组中添加多个数据类型。例如,我想在同一个数组中声明 int 和 char 数据类型
#include <stdio.h>
int main()
double linetotal= qty*price;
printf("line total =%lf\n",linetotal);
double subtotal = line total - discount ;
}
}
现在检查解决方案。
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define NUM_CODE 10
const char *CODE[NUM_CODE] = {"B100","B122","B134","B138","B145","B160","B165","B178","B186","B194"};
double PRICE[NUM_CODE]={12.8,18.7,20.5,11.5,25.5,20.55,25.65,14.85,22.2,24.25};
int main()
{
char name[20];
printf("Enter buyer name: ");
scanf("%s",name);
int entry;
printf("Enter number of entries for the invoice: ");
scanf("%d",&entry);
char code[10];
int quantity;
double price,linetotal=0;
int i;
for(i=1;i<=entry;i++)
{
printf("Enter Code: ");
scanf("%s",code);
printf("Enter Quantity: ");
scanf("%d",&quantity);
printf("Enter Unit Price: ");
scanf("%lf",&price);
int j;
int flag=0;
for(j=1;j<=NUM_CODE;j++){
// how do i print values like B100 without getting errors//
printf("%s ",CODE[j-1]);
// how to match the user input with parallel arrays?//
if(strcmp(CODE[j-1],code)==0 && PRICE[j-1]==price){
//If correct code and price found do
printf("\nValid Code and price found\n");
//set the flag and break from the loop
flag=1;
break;
}
}
if(flag==0){
//Exit the program with invalid entry
printf("\nInvalid Code and price found\n");
printf("The program will close now...\n");
exit(1);
}
// how do calculate line total,and subtotal after discount//
// discount is 10% if line total is greater than Rs5000//
linetotal = price * quantity + linetotal;
printf("\n");
}
double subtotal;
if(linetotal>5000){
subtotal = 0.9*linetotal;
}
else if(linetotal>=1000 && linetotal<=5000){
subtotal = 0.95*linetotal;
}
else{
subtotal = linetotal;
}
printf("Discount: %0.2lf%%\nTotal Price: %lf\n",((linetotal-subtotal)/linetotal)*100,subtotal);
return 0;
}
我们如何在 C 中声明并行数组。还有,如何在单个数组中添加多个数据类型。例如,我想在同一个数组中声明 int 和 char 数据类型
#include <stdio.h>
int main()
double linetotal= qty*price;
printf("line total =%lf\n",linetotal);
double subtotal = line total - discount ;
}
}
现在检查解决方案。
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define NUM_CODE 10
const char *CODE[NUM_CODE] = {"B100","B122","B134","B138","B145","B160","B165","B178","B186","B194"};
double PRICE[NUM_CODE]={12.8,18.7,20.5,11.5,25.5,20.55,25.65,14.85,22.2,24.25};
int main()
{
char name[20];
printf("Enter buyer name: ");
scanf("%s",name);
int entry;
printf("Enter number of entries for the invoice: ");
scanf("%d",&entry);
char code[10];
int quantity;
double price,linetotal=0;
int i;
for(i=1;i<=entry;i++)
{
printf("Enter Code: ");
scanf("%s",code);
printf("Enter Quantity: ");
scanf("%d",&quantity);
printf("Enter Unit Price: ");
scanf("%lf",&price);
int j;
int flag=0;
for(j=1;j<=NUM_CODE;j++){
// how do i print values like B100 without getting errors//
printf("%s ",CODE[j-1]);
// how to match the user input with parallel arrays?//
if(strcmp(CODE[j-1],code)==0 && PRICE[j-1]==price){
//If correct code and price found do
printf("\nValid Code and price found\n");
//set the flag and break from the loop
flag=1;
break;
}
}
if(flag==0){
//Exit the program with invalid entry
printf("\nInvalid Code and price found\n");
printf("The program will close now...\n");
exit(1);
}
// how do calculate line total,and subtotal after discount//
// discount is 10% if line total is greater than Rs5000//
linetotal = price * quantity + linetotal;
printf("\n");
}
double subtotal;
if(linetotal>5000){
subtotal = 0.9*linetotal;
}
else if(linetotal>=1000 && linetotal<=5000){
subtotal = 0.95*linetotal;
}
else{
subtotal = linetotal;
}
printf("Discount: %0.2lf%%\nTotal Price: %lf\n",((linetotal-subtotal)/linetotal)*100,subtotal);
return 0;
}