根据值对组进行排序

Question

I have a group named p. On performing certain operations on this group, I get the corresponding output as shown-

p.all()

>> 01: {key: "A", value: {count:2}}
>> 102: {key: "B", value: {count:10}}
>> 103: {key: "C", value: {count:4}}

p5.all()[0].value.count

>> 2

p5.all()[1].value.count

>> 10

p5.all()[1].key

>> "B"

我想根据计数对前 2 个值进行排序。这样输出应该是：

{key: "B", value: {count:10}}
{key: "C", value: {count:4}}

如何排序？

Answer 1

const myArray = [
  {key: "A", value: {count:2}},
  {key: "B", value: {count:10}},
  {key: "C", value: {count:4}},
]

const sortedArray = myArray.sort((a, b) => b.value.count - a.value.count);

console.log(sortedArray);

Answer 2

const groupP = [
  {key: "A", value: {count:2}},
  {key: "B", value: {count:10}},
  {key: "C", value: {count:4}},
]

const sortedGroupP = groupP.sort((a, b) => a.value.count - b.value.count);

console.log(sortedGroupP[groupP.length -2]);
console.log(sortedGroupP[groupP.length - 1]);

Answer 3

const myArray = [
  { key: "A", value: { count: 2 } },
  { key: "B", value: { count: 10 } },
  { key: "C", value: { count: 4 } },
];

const result = myArray.sort((a, b) => b.value.count - a.value.count).splice(0, 2);

console.log(result);

根据值对组进行排序

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