使用多个电话号码和电子邮件循环遍历数据库 mysql php

Question

我正在尝试遍历数据库并为每个用户获取正确的数据。但是我有多个 phone 和每个用户的邮件。当我尝试循环时，我只能为每个用户获得一个（正确的data/user）号码，当我尝试子循环时，我只从数据库中获取前两个数字。所以第一个用户有正确的 phone 和邮件数据，其余用户有 phone 和来自第一个用户的邮件数据。我不知道从这里可以做什么☹。

<?php
/**
 * @author Johan Fuchs
 * @copyright 2020
 */
//LEDEN.PHP
//login.php========================================================
  require_once 'login.php';
  $conn = new mysqli($hostname, $username, $password, $database);
  if ($conn->connect_error) die("Fatal Error");
//begin html gedeelte==============================================  
  echo <<<_END
<html>
  <head>
  <title>display test</title>
  <link href="" rel="stylesheet" type="text/css">
  </head>
<body>
 <h2>display test</h2>
</body>
</html>
_END;
//display leden===========================================================================================================================================================================
      
      $query  = "SELECT * FROM lid";
      $result = $conn->query($query);
      if (!$result) die ("Database access failed");

      $rows = $result->num_rows;

      for ($j = 0 ; $j < $rows ; ++$j)
      {
      $row = $result->fetch_array(MYSQLI_NUM);

      $rs0 = htmlspecialchars($row[0]);
      $rs1 = htmlspecialchars($row[1]);
      $rs2 = htmlspecialchars($row[2]);
      $rs3 = htmlspecialchars($row[3]);
      $rs4 = htmlspecialchars($row[4]);
         
//get info telefoonnummer lid======================================
     
      $subquery  = "SELECT * FROM telefoonnummer WHERE lidnummer='$row[0]'";
      $subresult = $conn->query($subquery);
      if (!$subresult) die ("Database access failed");
    
      $subrows = $subresult->num_rows;
        
      $t = 0;
    
      while ($t < $subrows)
      {
      $subrow = $subresult->fetch_array(MYSQLI_NUM);
    
      $rs7 = htmlspecialchars($subrow[1]);
    
      $tels[] = $rs7;
      $t++;    
      }
    
      $tel1s = $tels[0];
      $tel2s = $tels[1];
      
      
//get info email lid================================================
  
      $subquery  = "SELECT * FROM email WHERE lidnummer='$row[0]'";
      $subresult = $conn->query($subquery);
      if (!$subresult) die ("Database access failed");
    
      $subrows = $subresult->num_rows;
    
      $m = 0;
     
      while ($m < $subrows)
    
     {
     $subrow = $subresult->fetch_array(MYSQLI_NUM);
    
     $rs8 = htmlspecialchars($subrow[1]);
    
     $mails[] = $rs8;
     $m++;
     }
    
     $mail1s = $mails[0];
     $mail2s = $mails[1]; 
     
//get info  postcode lid============================================
     $subquery  = "SELECT * FROM postcode WHERE postcode='$row[4]'";
     $subresult = $conn->query($subquery);
     if (!$subresult) die ("Database access failed");
    
     $subrow = $subresult->fetch_array(MYSQLI_NUM);
    
     $ps4 = htmlspecialchars($subrow[0]);
     $rs6 = htmlspecialchars($subrow[1]);
     $rs5 = htmlspecialchars($subrow[2]);
     
//display data lid=================================================
    
  echo <<<_END
  =================================================================
  <pre>
  Lidnummer         :$rs0
  Voornaam          :$rs2
  Achternaam        :$rs1 
  Adres             :$rs5
  Huisnummer        :$rs3
  Postcode          :$rs4
  Woonplaats        :$rs6
  Telefoonnummer    :$rs7 :$tel1s :$tel2s
  Email             :$rs8 :$mail1s :$mail2s 
  </pre>
_END;
} 
?>

用户数据结果

display test
================================================================= 
  Lidnummer         :1
  Voornaam          :firstname01
  Achternaam        :surname01 
  Adres             :street01
  Huisnummer        :01
  Postcode          :1111AA
  Woonplaats        :city01
  Telefoonnummer    :0611111111 :0601010101 :0611111111
  Email             :test@mail11.com :test@mail01.com :test@mail11.com 
  
================================================================= 
  Lidnummer         :2
  Voornaam          :firstname02
  Achternaam        :surname02 
  Adres             :street02
  Huisnummer        :02
  Postcode          :2222bb
  Woonplaats        :city02
  Telefoonnummer    :0622222222 :0601010101 :0611111111
  Email             :test@mail22 :test@mail01.com :test@mail11.com 
  
================================================================= 
  Lidnummer         :3
  Voornaam          :firstname03
  Achternaam        :surename03 
  Adres             :street03
  Huisnummer        :03
  Postcode          :3333cc
  Woonplaats        :city03
  Telefoonnummer    :0633333333 :0601010101 :0611111111
  Email

任何解决此问题的线索？

提前致谢:)

Answer 1

您需要在每次迭代中使用 unset() 函数来取消设置 $tels 和 $mails 数组的数组键。如果你不这样做，这就是将要发生的事情：

第一次迭代

$tels[0] will have First User Mobile
$tels[1] will have First User Mobile

第二次迭代

$tels[0] will have First User Mobile
$tels[1] will have First User Mobile
$tels[2] will have Second User Mobile
$tels[3] will have Second User Mobile

等等 mails 也是如此

在代码中，您只分配前 2 个键值，它们始终包含第一个用户的详细信息。

  $tel1s = $tels[0];
  $tel2s = $tels[1];

所以解决方案是在sub-query底部添加unset()函数，用于电话和电子邮件。

while ($t < $subrows)
  {
  $subrow = $subresult->fetch_array(MYSQLI_NUM);

  $rs7 = htmlspecialchars($subrow[1]);

  $tels[] = $rs7;
  $t++;    
  }

  $tel1s = $tels[0];
  $tel2s = $tels[1]; 
  unset($tels);  /* This will unset the array $tels for next iteration */

这将确保在每次迭代时，$tels[0] 和 $tels[1] 将被重新分配，您将获得所需的信息。

类似地，在将值分配给变量 $mail1s 和 $mail2s 之后，也取消设置 $mails[] 数组。这应该可以解决您的问题。

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