Java 创建一个通用 class 实现另一个带有约束的通用接口

Question

要实现的接口：

public interface Message {
}

public interface Handles<T extends Message>  {
    void hanlde(T message);
}

具体实现：

public class EnforcementHandler<T extends Handles<T extends Message>> {

}

意外绑定

这种模式在 Java 中可能吗？

Answer 1

必须写成EnforcementHandler<M extends Message, T extends Handles<M>>。

Answer 2

你的 EnforcementHandler 的确切责任是什么，是模棱两可的。

根据其名称的“Handler”部分，我认为它的职责是“handle”。所以这似乎是对 my 理解的适当实施…

public class EnforcementHandler<M extends Message> implements Handler<M>{ 
    
    public void handle( M msg ) { out.printf( "%1s%n ", msg.read( ) ); }
}

This demo shows how it could be used…

  ...
  Message msg = ( ) -> "Friends of space, how are you all? Have you eaten yet? Come visit us if you have time.";
  
  EnforcementHandler< Message > handler = new EnforcementHandler< >( );
  
  handler.handle( msg );
  ...

…将此友好消息打印到stdout…

Friends of space, how are you all? Have you eaten yet? Come visit us if you have time.

Java 创建一个通用 class 实现另一个带有约束的通用接口

Java creating a generic class that implement another generic interface with constraints

java

generics

javacompiler