我想从我的 flutter 应用程序启动 WhatsApp 应用程序

I want to launch WhatsApp application from my flutter application

我正在使用此依赖项 url_launcher: ^5.4.1 在我的项目中通过我的 flutter 应用程序启动 whatsapp 但是当我按下按钮启动应用程序时它不工作但在模拟器上显示错误消息无法打开 link。 下面给出的是我用来启动 whatsapp 的功能代码。

import 'package:flutter/material.dart';
import 'package:url_launcher/url_launcher.dart';
import 'dart:io';


void main() => runApp(Wapp());

class Wapp extends StatelessWidget {
  // This widget is the root of your application.
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      debugShowCheckedModeBanner: false,
      title: 'Flutter Demo',
      theme: ThemeData(
          primarySwatch: Colors.orange,
      ),
      home: MyHomePage(title: 'Flutter Demo Home Page'),
    );
  }
}

class MyHomePage extends StatefulWidget {
  MyHomePage({Key key, this.title}) : super(key: key);

final String title;

  @override
  _MyHomePageState createState() => _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {
 void launchWhatsApp(
    {@required int phone,
    @required String message,
    }) async {
  String url() {
    if (Platform.isAndroid) {
      return "whatsapp://wa.me/$phone:03452121308:/?text=${Uri.parse(message)}";
    } else {
      return "whatsapp://send?   phone=$phone&text=${Uri.parse(message)}";
    }
  }

  if (await canLaunch(url())) {
    await launch(url());
  } else {
    throw 'Could not launch ${url()}';
  }
}


Widget build(BuildContext context){
  return Scaffold(
    appBar: AppBar(
      title: Text("Home"), 
    ),

  body: Center(
    child: RaisedButton(
      
      color: Colors.orange,
      textColor: Colors.black,
      padding: EdgeInsets.symmetric(vertical: 20.0, horizontal: 60.0),
      highlightColor: Colors.green,
      onPressed: () {
        launchWhatsApp(phone: 03452121308, message: 'Hello');
      },
      child: Text("Place Your Order",style: TextStyle(
          
          fontWeight: FontWeight.bold,
          fontSize: 15
          
        )
      )
    )
  )

  );
}

}

您的 url 中缺少 https://

用您的 url() 方法替换下面的代码:

  String url() {
    if (Platform.isAndroid) {
      // add the [https]
      return "https://wa.me/$phone/?text=${Uri.parse(message)}"; // new line
    } else {
      // add the [https]
      return "https://api.whatsapp.com/send?phone=$phone=${Uri.parse(message)}"; // new line
    }
  }
 String url() {
      if (Platform.isIOS) {
        return "whatsapp://wa.me/$phone/?text=${Uri.encodeFull(message)}";
      } else {
        return "whatsapp://send?phone=$phone&text=${Uri.encodeFull(message)}";
      }
    }

我找到了将此代码添加到 android/app/src/main/AndroidManifest 的解决方案。xml

<queries>
<intent>
    <action android:name="android.intent.action.VIEW" />
    <data android:scheme="https" />
</intent>
<intent>
    <action android:name="android.intent.action.DIAL" />
    <data android:scheme="tel" />
</intent>
<intent>
    <action android:name="android.intent.action.SEND" />
    <data android:mimeType="*/*" />
</intent>