如何 select 具有 Mongodb 核心查询 API 的字段符合我的条件
How to select a field with Mongodb Core Query API matching my criteria
我需要 select 我的集合中只有一个字段名称 (categoryName) 符合我的条件。相反,所有字段都从以下代码的集合中返回:
import org.springframework.data.mongodb.core.MongoTemplate;
import org.springframework.data.mongodb.core.query.Criteria;
import org.springframework.data.mongodb.core.query.Query;
public ServiceList findOneByCategoryName(String categoryName) {
// TODO Auto-generated method stub
Query query = new Query() ;
query.addCriteria(Criteria.where("categoryName").is(categoryName));
return (ServiceList) mongoTemplate.findOne(query,ServiceList.class);
}
ServiceList.java
@Document(collection = "services")
public class ServiceList {
@Id
private String id;
@Field("categoryName")
@JsonProperty("categoryName")
private String categoryName;
@Field("serviceTypes")
@JsonProperty("Service Types")
private List<ServiceType> serviceTypes;
public String getMfServicesId() {
return id;
}
public void setMfServicesId(String mfServicesId) {
this.id = mfServicesId;
}
public String getCategoryName() {
return categoryName;
}
public void setCategoryName(String categoryName) {
this.categoryName = categoryName;
}
public List<ServiceType> getServiceTypes() {
return serviceTypes;
}
public void setServiceTypes(List<ServiceType> serviceTypes) {
this.serviceTypes = serviceTypes;
}
}
对于此代码,所有字段均从集合中返回。我不知道如何 select 我选择显示的特定字段。
我认为这可能有效,使用 fields()
方法:
Query query = new Query();
query.addCriteria(Criteria.where("categoryName").is(categoryName));
query.fields().include("categoryName");
query.fields().exclude("id"); // Not sure you have to exclude Id explicitly
return (String) mongoTemplate.findOne(query,String.class);
以下代码用于 select 并使用 include 函数显示文档中的特定列。
import org.springframework.data.mongodb.core.MongoTemplate;
import org.springframework.data.mongodb.core.query.Criteria;
import org.springframework.data.mongodb.core.query.Query;
public ServiceList findOneByCategoryName(String categoryName) {
Query query = new Query() ;
query.addCriteria(Criteria.where("categoryName").is(categoryName));
query.fields().include("categoryName");
return (ServiceList) mongoTemplate.findOne(query,ServiceList.class);
}
我需要 select 我的集合中只有一个字段名称 (categoryName) 符合我的条件。相反,所有字段都从以下代码的集合中返回:
import org.springframework.data.mongodb.core.MongoTemplate;
import org.springframework.data.mongodb.core.query.Criteria;
import org.springframework.data.mongodb.core.query.Query;
public ServiceList findOneByCategoryName(String categoryName) {
// TODO Auto-generated method stub
Query query = new Query() ;
query.addCriteria(Criteria.where("categoryName").is(categoryName));
return (ServiceList) mongoTemplate.findOne(query,ServiceList.class);
}
ServiceList.java
@Document(collection = "services")
public class ServiceList {
@Id
private String id;
@Field("categoryName")
@JsonProperty("categoryName")
private String categoryName;
@Field("serviceTypes")
@JsonProperty("Service Types")
private List<ServiceType> serviceTypes;
public String getMfServicesId() {
return id;
}
public void setMfServicesId(String mfServicesId) {
this.id = mfServicesId;
}
public String getCategoryName() {
return categoryName;
}
public void setCategoryName(String categoryName) {
this.categoryName = categoryName;
}
public List<ServiceType> getServiceTypes() {
return serviceTypes;
}
public void setServiceTypes(List<ServiceType> serviceTypes) {
this.serviceTypes = serviceTypes;
}
}
对于此代码,所有字段均从集合中返回。我不知道如何 select 我选择显示的特定字段。
我认为这可能有效,使用 fields()
方法:
Query query = new Query();
query.addCriteria(Criteria.where("categoryName").is(categoryName));
query.fields().include("categoryName");
query.fields().exclude("id"); // Not sure you have to exclude Id explicitly
return (String) mongoTemplate.findOne(query,String.class);
以下代码用于 select 并使用 include 函数显示文档中的特定列。
import org.springframework.data.mongodb.core.MongoTemplate;
import org.springframework.data.mongodb.core.query.Criteria;
import org.springframework.data.mongodb.core.query.Query;
public ServiceList findOneByCategoryName(String categoryName) {
Query query = new Query() ;
query.addCriteria(Criteria.where("categoryName").is(categoryName));
query.fields().include("categoryName");
return (ServiceList) mongoTemplate.findOne(query,ServiceList.class);
}