如何根据海龟的颜色和最小距离将海龟分组

How to group turtles together depending on their colour and minimum distance

我正在 NetLogo 中编写一个模型,我从 5 个颜色(蓝色、绿色、黄色、红色、白色)的海龟种群开始,起始坐标是随机的。当我 运行 模型时,我希望当白色乌龟遇到绿色或黄色或红色乌龟时,它们会加入并作为一个整体移动。当白海龟遇到蓝海龟时,它与蓝海龟分开并继续随机移动。我在模型库中看到了鸟群的示例模型,我一直在尝试为我的模型修改它(见附件代码)。

在模型库的 'flocking example' 中,海龟被设置为在彼此太近时对齐、凝聚和分离(取决于最近邻和最小分离的距离)。这很有效,我能够用它告诉海龟聚集在一起,在它们继续移动时保持它们作为一个整体完整。我的问题是如何让(绿、黄、红)海龟遇到白海龟时只聚集在一起,而让蓝海龟随机移动。

turtles-own [
  flockmates         ;; agentset of nearby turtles
  nearest-neighbor   ;; closest one of our flockmates
]
;Setting up the 5 turtles here
to setup
  clear-all
  create-turtles pop1
    [ set color blue ; all pop
      set size 1.5  ;; easier to see
      setxy random-xcor random-ycor
      set shape "person"]
        
  create-turtles pop2
    [ set color green ; stage1
      set size 1.5  ;; easier to see
      setxy random-xcor random-ycor
      set shape "person"]
  
    create-turtles pop3
    [ set color yellow ; stage2
      set size 1.5  ;; easier to see
      setxy random-xcor random-ycor
      set shape "person"]
  
    create-turtles pop4
    [ set color red ;stage3
      set size 1.5  ;; easier to see
      setxy random-xcor random-ycor
      set shape "person"]
  
    create-turtles pop5
    [ set color white ; chv
      set size 1.5  ;; easier to see
      setxy random-xcor random-ycor
      set shape "person"]
  reset-ticks
end
to go
  ask turtles [ flock ]
  ;ask turtles [ meet]
  ;; the following line is used to make the turtles   ;; animate more smoothly.
  repeat 5 [ ask turtles [ fd 0.2 ] ] ;this seems much faster
  ;; for greater efficiency, at the expense of smooth
  ;; animation, substitute the following line instead:
  ;ask turtles [ fd 1 ] ;than this
  tick
end
;How do I make to get only the (green, yellow, red) turtles to flock when 
;they meet the white turtles. Leaving the blue turtles moving randomly. How can do that? 
;  find-samecolor
;  if any? flock
;   ifelse separate
;end
;If green, yellow, red meets white turtle, they move together; nearest distance
to flock  ;; turtle procedure
  find-flockmates
  if any? flockmates
    [ find-nearest-neighbor
      ifelse 
        distance nearest-neighbor < minimum-separation
        [ align ]
        [ cohere ]    
      ;[separate]
  ]
       
end
;If blue meets white turtle, they move together; nearest distance
to find-flockmates  ;; turtle procedure
  set flockmates other turtles in-radius vision
end
to find-nearest-neighbor ;; turtle procedure
  set nearest-neighbor min-one-of flockmates [distance myself]
end
;;; SEPARATE
;to separate  ;; turtle procedure 
;  turn-away ([heading] of nearest-neighbor) max-separate-turn
;end
;;; ALIGN
to align  ;; turtle procedure
  turn-towards average-flockmate-heading max-align-turn
end
to-report average-flockmate-heading  ;; turtle procedure
  ;; We can't just average the heading variables here.
  ;; For example, the average of 1 and 359 should be 0,
  ;; not 180.  So we have to use trigonometry.
  let x-component sum [dx] of flockmates
  let y-component sum [dy] of flockmates
  ifelse x-component = 0 and y-component = 0
    [ report heading ]
    [ report atan x-component y-component ]
end
;;; COHERE
to cohere  ;; turtle procedure
  turn-towards average-heading-towards-flockmates max-cohere-turn
end
to-report average-heading-towards-flockmates  ;; turtle procedure
  ;; "towards myself" gives us the heading from the other turtle
  ;; to me, but we want the heading from me to the other turtle,
  ;; so we add 180
  let x-component mean [sin (towards myself + 180)] of flockmates
  let y-component mean [cos (towards myself + 180)] of flockmates
  ifelse x-component = 0 and y-component = 0
    [ report heading ]
    [ report atan x-component y-component ]
end
;;; HELPER PROCEDURES
to turn-towards [new-heading max-turn]  ;; turtle procedure
  turn-at-most (subtract-headings new-heading heading) max-turn
end
;to turn-away [new-heading max-turn]  ;; turtle procedure
;  turn-at-most (subtract-headings heading new-heading) max-turn
;end
;; turn right by "turn" degrees (or left if "turn" is negative),
;; but never turn more than "max-turn" degrees
to turn-at-most [turn max-turn]  ;; turtle procedure
  ifelse abs turn > max-turn
    [ ifelse turn > 0
        [ rt max-turn ]
        [ lt max-turn ] ]
    [ rt turn ]
end

您可以制作两种不同类型的 turtles-own,它们都有自己的规则。我做了一个多代理工作,每个人都有自己的规则,并且有聋人 turtles-own 组一切都像魅力一样。

ant-own[ velocita-ant metabolismo-ant sf ;;scorta ants massimo_sf] killer own[velocita-killer metabolismo-killer sk ;;scorta killers massimo_sk]

抱歉耽搁了,由于某些原因,当你第一次问这个问题时我没有看到它。这段代码中的关键过程是:

to find-flockmates  ;; turtle procedure
  set flockmates other turtles in-radius vision
end

这是说源龟可以看到的任何龟都被认为是群友。您想要做的是说蓝海龟不能成为群友(也就是说,它们不会自己创建群,并且不会被其他有色海龟视为群友)。试试这个:

to find-flockmates  ;; turtle procedure
  if color != blue
  [ set flockmates other turtles with [color != blue] in-radius vision
  ]
end

第一行让蓝龟找不到 flockmates。第二行将蓝海龟排除在其他海龟群之外。

-----更新----

你实际上在一个关于植绒的乌龟程序中有这个程序。此过程将变量 'flockmates' 设置为找到的海龟集合,但是,如果海​​龟是蓝色的,则没有 flockmates 并且它不是 return 空海龟集合。修复它的最佳方法是使用 to-report 过程,这样所有海龟的变量都会有合适的数据类型(海龟集)。

to-report find-flockmates  ;; turtle procedure
  ifelse color = blue
  [ report no-turtles ]    ; this is an empty turtle-set
  [ report other turtles with [color != blue] in-radius vision ]
end

然后,要使用此程序,您需要更改:

to flock  ;; turtle procedure
  find-flockmates
  if any? flockmates

对此:

to flock  ;; turtle procedure
  set flockmates find-flockmates
  if any? flockmates