当我尝试从 2 个文件创建 zip 时出错

Question

我正在尝试将 2 个文件合并到一个 zip 文件中

myMainMethod

private void downloadFileByTypeInner(StaticDocument file, String productCode, int productVersion) throws IOException, TechnicalException {
    ExternalContext ec = FacesContext.getCurrentInstance().getExternalContext();
    HttpServletResponse response = (HttpServletResponse) ec.getResponse();
    String distrib = MultinetFrontHelper.getDefaultDitrib();
    String realPath = findRealPath(ec, file.getPath().replace("{DISTRIB}", distrib));
    String downloadName = file.getDownloadFileName() != null ? file.getDownloadFileName() : file.getPath();

    if (file.getAction() == null || file.getAction().trim().isEmpty() || file.getAction().equals("download")) {
        List<java.io.File> l = new ArrayList<>();
        java.io.File f = new java.io.File(realPath);
        l.add(f);
        if(file.getDependOnCodeFiles() != null){
            String[] paths  = file.getDependOnCodeFiles().split(",");
            for (String codefile : paths) {

                StaticDocument file2 = libraryBusinessService.getFileByCodeType(codefile, productCode, productVersion);
                if((file2 != null)) {
                    l.add(new java.io.File(findRealPath(ec, file2.getPath())));
                }
            }
            downloadName = downloadName.substring(0,downloadName.lastIndexOf("."))+".zip";
        }
        InputStream pathStream = DownLoadHelper.getStreamAllFiles(l.toArray(new java.io.File[0]), downloadName);

        if (pathStream != null) {
            if(downloadName.indexOf('/')!=-1) {
                downloadName = downloadName.substring(downloadName.lastIndexOf('/')+1);
            }
            DownLoadHelper.downLoadFile(response, pathStream, downloadName);
        } else {
            logger.error("Le fichier " + realPath + " est introuvable!");
            throw new TechnicalException(CodeError.CODE_ERTEMO0001, null);
        }

    } else if (file.getAction().equals("open")) {
        final FacesContext ctx = FacesContext.getCurrentInstance();
        final ExternalContext extContext = ctx.getExternalContext();
        try {
            extContext.redirect(file.getPath());
        } catch (final IOException ioe) {
            throw new FacesException(ioe);

        }
    }
}

getStreamAllFiles

public static InputStream getStreamAllFiles(final File[] listDoc, String nameZIP) throws IOException {
    InputStream stream = null;
    if (listDoc != null) {
        if (listDoc.length == 1) {
            stream = new  ByteArrayInputStream(FileUtils.readFileToByteArray(listDoc[0]));
        } else if (listDoc.length > 1) {
            try( ByteArrayOutputStream baos = new ByteArrayOutputStream();ZipOutputStream zos = new ZipOutputStream(baos)){

                for (int i = 0; i < listDoc.length; i++) {

                    try(InputStream fis = new  ByteArrayInputStream(FileUtils.readFileToByteArray(listDoc[i]));BufferedInputStream bis = new BufferedInputStream(fis)){
                        zos.putNextEntry(new ZipEntry(listDoc[i].getName()));
                        byte[] bytes = new byte[1024];
                        int bytesRead;
                        while ((bytesRead = bis.read(bytes)) != -1) {
                            zos.write(bytes, 0, bytesRead);
                        }
                    }
                }

                zos.closeEntry();

                stream = new ByteArrayInputStream(baos.toByteArray());
            }
        }
    }
    return stream;
}

downLoadFile

public static void downLoadFile(HttpServletResponse response,InputStream pathStream,String fileName) throws IOException {
    response.setContentType("application/octet-stream");
    response.setHeader("Content-Disposition",
            "attachment;filename=" + fileName);


    ServletOutputStream out = response.getOutputStream();
    IOUtils.copyLarge(pathStream, out);
    out.flush();
    FacesContext.getCurrentInstance().responseComplete();
    IOUtils.closeQuietly(pathStream);
    IOUtils.closeQuietly(out);

}

我在尝试打开 zip 文件时遇到此错误

Answer 1

我假设您正在尝试制作一个包含多个文件的 zip 文件。问题出在您的 getStreamAllFiles 方法中，因为您在放置文件内容后没有关闭 zip 条目，并且您没有关闭 ZipOutputStream 和循环结束，所以文件循环应如下所示：

for (int i = 0; i < listDoc.length; i++) {

    try(InputStream fis = new  ByteArrayInputStream(FileUtils.readFileToByteArray(listDoc[i]));BufferedInputStream bis = new BufferedInputStream(fis)){
        zos.putNextEntry(new ZipEntry(listDoc[i].getName()));
        byte[] bytes = new byte[1024];
        int bytesRead;
        while ((bytesRead = bis.read(bytes)) != -1) {
            zos.write(bytes, 0, bytesRead);
        }
        zos.closeEntry();
    }
}
zos.close();
stream = new ByteArrayInputStream(baos.toByteArray());

即在文件循环中移动 zos.closeEntry()。

如果不将其移动到 listDoc.length 循环内，如果您有多个文件，您将无法在每个条目末尾正确关闭 ZipEntry。您还需要在 ZipOutputStream 上发出 close()，否则它不会写入 end-of-zip 目录（如果您在命令行工具下测试该文件，则显示为错误 End-of-central-directory signature not found .

In addition, I'd move the allocation of the byte buffer outside the file loop as you only need to allocate it once, and reuse the same buffer for all the files you're writing.

当我尝试从 2 个文件创建 zip 时出错

Error when i am trying to create a zip from 2 files

java

spring

inputstream