C#:带有 JsonConvert.SerializeObject() 的 Dapper 无法正常工作
C#: Dapper with JsonConvert.SerializeObject() not working properly
我是 Newtonsoft.Json 和 Dapper 的新手。
我正在执行 SQL 查询,并使用查询的结果将其转换为 JSON 字符串以使其看起来像这样:
{ "Orders" : [{"OrderID":10248, "Quantity":12}, {"OrderID":10343, "Quantity":4}, ...etc...]}
然而,当我 运行 我的 C# 代码时,我的输出看起来完全不同,还有一些意外的添加:
[
{
"JSON_F52E2B61-18A1-11d1-B105-00805F49916B": "{\"Orders\":[{\"OrderID\":10248,\"Quantity\":12},{\"OrderID\":10248,\"Quantity\":10}{\"OrderID\":10271,\"Quantity\":24},{\"OrderID\":10272,\"Quantity\":6},{\"OrderID\":1027"
},
{
"JSON_F52E2B61-18A1-11d1-B105-00805F49916B": "2,\"Quantity\":40},{\"OrderID\":10272,\"Quantity\":24}, ...etc... ]
如您所见,我不明白为什么要添加额外的“JSON_F52E2B61-18A1-11d1-B105-00805F49916B”。我如何删除这些?如何更改我的代码以使其看起来像我想要的输出 json 字符串?
这是我的代码。我还制作了一个 fiddle,但我得到的输出不正确 https://dotnetfiddle.net/uWV6vs :
// Dapper Plus
// Doc: https://dapper-tutorial.net/query
// @nuget: Dapper -Version 1.60.6
using Newtonsoft.Json;
using Dapper;
using System;
using System.Data.SqlClient;
public class Program
{
public class OrderDetail
{
public int OrderDetailID { get; set; }
public int OrderID { get; set; }
public int ProductID { get; set; }
public int Quantity { get; set; }
}
public static void Main()
{
string sql = "SELECT OrderID, Quantity FROM OrderDetails FOR JSON PATH, root ('Orders'), INCLUDE_NULL_VALUES";
using (var connection = new SqlConnection(FiddleHelper.GetConnectionStringSqlServerW3Schools()))
{
dynamic orderDetail = connection.Query(sql);
//edit: the answer is to use connection.Query<string>, orderDetail[0]
orderDetail = JsonConvert.SerializeObject(orderDetail,Formatting.Indented);
Console.WriteLine(orderDetail);
}
}
}
我相信你不需要向SQL请求JSON,Dapper会自动将结果解析为对象
删除“FOR JSON PATH, root ('Orders'), INCLUDE_NULL_VALUES”应该会有所帮助
string sql = "SELECT OrderID, Quantity FROM OrderDetails";
更新:
抱歉,请继续更新答案。这个为您提供具有正确结构且没有额外反斜杠的对象
using Newtonsoft.Json;
using Dapper;
using System;
using System.Data.SqlClient;
using System.Collections.Generic;
public class Program
{
public class OrderDetail
{
public int OrderDetailID { get; set; }
public int OrderID { get; set; }
public int ProductID { get; set; }
public int Quantity { get; set; }
}
public class Result
{
public IEnumerable<OrderDetail> Orders { get; set; }
}
public static void Main()
{
string sql = "SELECT OrderID, Quantity FROM OrderDetails";
using (var connection = new SqlConnection(FiddleHelper.GetConnectionStringSqlServerW3Schools()))
{
var orderDetail = connection.Query<OrderDetail>(sql);
var str = JsonConvert.SerializeObject(new Result { Orders = orderDetail },Formatting.Indented);
Console.WriteLine(str);
}
}
}
我是 Newtonsoft.Json 和 Dapper 的新手。
我正在执行 SQL 查询,并使用查询的结果将其转换为 JSON 字符串以使其看起来像这样:
{ "Orders" : [{"OrderID":10248, "Quantity":12}, {"OrderID":10343, "Quantity":4}, ...etc...]}
然而,当我 运行 我的 C# 代码时,我的输出看起来完全不同,还有一些意外的添加:
[
{
"JSON_F52E2B61-18A1-11d1-B105-00805F49916B": "{\"Orders\":[{\"OrderID\":10248,\"Quantity\":12},{\"OrderID\":10248,\"Quantity\":10}{\"OrderID\":10271,\"Quantity\":24},{\"OrderID\":10272,\"Quantity\":6},{\"OrderID\":1027"
},
{
"JSON_F52E2B61-18A1-11d1-B105-00805F49916B": "2,\"Quantity\":40},{\"OrderID\":10272,\"Quantity\":24}, ...etc... ]
如您所见,我不明白为什么要添加额外的“JSON_F52E2B61-18A1-11d1-B105-00805F49916B”。我如何删除这些?如何更改我的代码以使其看起来像我想要的输出 json 字符串?
这是我的代码。我还制作了一个 fiddle,但我得到的输出不正确 https://dotnetfiddle.net/uWV6vs :
// Dapper Plus
// Doc: https://dapper-tutorial.net/query
// @nuget: Dapper -Version 1.60.6
using Newtonsoft.Json;
using Dapper;
using System;
using System.Data.SqlClient;
public class Program
{
public class OrderDetail
{
public int OrderDetailID { get; set; }
public int OrderID { get; set; }
public int ProductID { get; set; }
public int Quantity { get; set; }
}
public static void Main()
{
string sql = "SELECT OrderID, Quantity FROM OrderDetails FOR JSON PATH, root ('Orders'), INCLUDE_NULL_VALUES";
using (var connection = new SqlConnection(FiddleHelper.GetConnectionStringSqlServerW3Schools()))
{
dynamic orderDetail = connection.Query(sql);
//edit: the answer is to use connection.Query<string>, orderDetail[0]
orderDetail = JsonConvert.SerializeObject(orderDetail,Formatting.Indented);
Console.WriteLine(orderDetail);
}
}
}
我相信你不需要向SQL请求JSON,Dapper会自动将结果解析为对象
删除“FOR JSON PATH, root ('Orders'), INCLUDE_NULL_VALUES”应该会有所帮助
string sql = "SELECT OrderID, Quantity FROM OrderDetails";
更新:
抱歉,请继续更新答案。这个为您提供具有正确结构且没有额外反斜杠的对象
using Newtonsoft.Json;
using Dapper;
using System;
using System.Data.SqlClient;
using System.Collections.Generic;
public class Program
{
public class OrderDetail
{
public int OrderDetailID { get; set; }
public int OrderID { get; set; }
public int ProductID { get; set; }
public int Quantity { get; set; }
}
public class Result
{
public IEnumerable<OrderDetail> Orders { get; set; }
}
public static void Main()
{
string sql = "SELECT OrderID, Quantity FROM OrderDetails";
using (var connection = new SqlConnection(FiddleHelper.GetConnectionStringSqlServerW3Schools()))
{
var orderDetail = connection.Query<OrderDetail>(sql);
var str = JsonConvert.SerializeObject(new Result { Orders = orderDetail },Formatting.Indented);
Console.WriteLine(str);
}
}
}