僵尸进程未使用 waitpid 调用进行清理

Question

我正在使用 htop 观察进程，我发现即使我使用 waitpid 调用清理，子进程仍保持僵尸状态。知道为什么会发生这种情况吗？

非常感谢！

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#include <errno.h>
#include <unistd.h>
#include <sys/types.h>
#include <signal.h>

void child_signal_handler(int signal) {
  printf("Someone is stabbed me with signal %d\n", signal);
}

int main(int argc, char** argv)
{
  const pid_t child = fork();

  if (child == 0) {
    struct sigaction sa;
    memset(&sa, 0, sizeof(sa));
    sa.sa_handler = &child_signal_handler;
    sigaction(SIGTERM, &sa, NULL);
    printf("Child is started in busy loop\n");
    while (true)
      ;
  } else {
    const int mercy_period = 3;
    printf("Parent is angry and gonna kill his child in %d sec\n", mercy_period);
    sleep(mercy_period);
    kill(child, SIGTERM);
    // clean-up zombie child process as it is terminated before we can wait on
    // it
    int status = 0;
    while(waitpid(-1, &status, WNOHANG) > 0);
  }

  return EXIT_SUCCESS;
}

Answer 1

waitpid glibc 实现评论

If PID is (pid_t) -1, match any process. If the WNOHANG bit is set in OPTIONS, and that child is not already dead, return (pid_t) 0.

while 循环显然立即退出，因为 0 > 0 为假。

将 else 和信号更改为 SIGKILL

} else {
    const int mercy_period = 3;
    printf("Parent is angry and gonna kill his child in %d sec\n", mercy_period);
    sleep(mercy_period);
    kill(child, SIGKILL);
 
    int status = 0;
    pid_t pid = waitpid(-1, &status, WNOHANG);
    while(!pid) {
        pid = waitpid(-1, &status, WNOHANG);
        printf("%d\n", pid);    
    }
}

几次尝试后 waitpid 将 return 子进程的 pid。成功了。

僵尸进程未使用 waitpid 调用进行清理

Zombie process is not cleanup with waitpid call

c++

unix

fork

parent-child

waitpid