Json 修补删除数组中的子元素

Json Patch removing sub elements in an array

我想从数组中删除子元素,例如

{
    "employees": [
        {
            "name": "name1",
            "id": "id1"
        },
        {
            "name": "name2",
            "id": "id2"
        },
        {
            "name": "name3",
            "id": "id3"
        }
    ]
}

我需要一个补丁来删除所有 ID,这样我就可以做这样的事情

[{ "op": "remove", "path": "/employees/0/id"},
{ "op": "remove", "path": "/employees/1/id"},
{ "op": "remove", "path": "/employees/2/id"}]

但是有什么方法可以指定通配符给select数组中的所有id元素

我一直在看 JSON patch draft but didn't find anything about regular expressions. One solution is to use some JSON parse tools to create it, like jq and python-json-patch。第一个删除所有 id 键,第二个从差异创建补丁,使用如下:

jq 'del(.employees[].id)' jsonfile | jsondiff jsonfile -

它产生:

[{"op": "replace", "path": "/employees/2", "value": {"name": "name3"}}, 
 {"op": "replace", "path": "/employees/1", "value": {"name": "name2"}}, 
 {"op": "replace", "path": "/employees/0", "value": {"name": "name1"}}]

同时使用 jsonpatch 工具应用补丁,似乎生成了正确的输出,如:

jq 'del(.employees[].id)' jsonfile | jsondiff jsonfile - | jsonpatch jsonfile -

它产生:

{"employees": [{"name": "name1"}, {"name": "name2"}, {"name": "name3"}]}