如何使用 python 查找和更新 XML 文件内容

Question

例如

 <managedObject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedObject>
<managedObject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedObject>

在此示例中，首先我想将 (distName="MB-85404/TB-85404/ST-4/[a or b or c]") 更新为 (distName="MB-85409/TB-85409/ST-4/[a or b or c]")

对整个 XML 文件执行此操作后。

完成此操作后，我想更新标签 name="a" 的值 <managedObject class="New" distName="MB-85409/TB-85409/ST-4/[a or b or c] >

我该怎么做，我有一个 40000 多行的 XML 文件。

编辑1

with open("C:/files/abcd.xml", "w+") as file:
    xml_data = file.read()
    xml_data.replace("85409","85904")
    file.write("outPuta.xml")

编辑2

soup = bs(content,"xml")
    loc = re.compile(r'[A-Z]+-+[0-9]+/+SMOD+-+[1-9]')
    for i in soup.find_all('managedObject', distName=loc):
        locat=i.find('p',{'name':'moduleLocation'})
        locat.string="3444 South texas"

通过这段代码，我试图找到与 regex loc 匹配的 distname，在 managedObject 中，我试图找到标签 <p name="moduleLocation" 4444 New York> 并且我想更新 "4444 New York" 到 "3444 South texas" 这给了我下面提到的错误

locat.string="3444 South texas"
AttributeError: 'NoneType' object has no attribute 'string'

Answer 1

我希望我理解你的问题，这将找到所有 distName="MB-85404/TB-85404/ST-4/[a or b or c]" 标签并将 85404 替换为 85409 并更新 <p name="a"> 标签：

import re
from bs4 import BeautifulSoup


xml_data = ''' <managedObject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedObject>
<managedObject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedObject>'''

soup = BeautifulSoup('<data>' + xml_data + '</data>', 'xml')

r = re.compile(r'^MB-85404/TB-85404/ST-4/(?:a|b|c)')

for o in soup.find_all('managedObject', distName=r):
    o['distName'] = o['distName'].replace('85404', '85409')
    p = o.find('p', {'name':'a'})
    p.string = 'UPDATED ' + p.string

soup.data.unwrap()
print(soup)

打印：

<?xml version="1.0" encoding="utf-8"?>
 <managedObject class="New" distName="MB-85409/TB-85409/ST-4/a" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="b">enabled</p>
<p name="c">640ms</p>
<p name="d">320ms</p>
<p name="e">640ms</p>
<p name="f">1280ms</p>
<p name="g">6</p>
</managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" operation="open" version="xL20A_1911_002">
<p name="h">320ms</p>
<p name="i">enabled</p>
<p name="j">640ms</p>
<p name="k">320ms</p>
<p name="l">640ms</p>
<p name="a">1280ms</p>
<p name="l">6</p>
</managedObject>
<managedObject class="New" distName="MB-85409/TB-85409/ST-4/c" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="p">enabled</p>
<p name="q">640ms</p>
<p name="r">320ms</p>
<p name="s">640ms</p>
<p name="t">1280ms</p>
<p name="u">6</p>
</managedObject>

编辑：要在每个 distName= 中将 85404 更改为 85409，您可以这样做：

for o in soup.find_all('managedObject', {'distName': True}):
    o['distName'] = o['distName'].replace('85404', '85409')

EDIT2：替换整个文件：

with open("C:/files/abcd.xml", "r") as f_in:
    xml_data = f_in.read()

with open("C:/files/output.xml", "w") as f_out:
    f_out.write(xml_data.replace("85409","85904"))

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