如何将子字符串括在方括号中 python

Question

我有一个很长的文本，其中部分包含在 +++ 中，我想用方括号括起来

se1 = "+++TEXT:+++ Moshe Morgenstern is on his way to the main synagogue in the center of Bnei Brak, home to a largely ultra-orthodox - or haredi - community. +++ : Bnei Brak, Tel Aviv + Jerusalem ))+++"

我想将 +++ 中包含的文本转换为 [[]]，所以，

+++TEXT+++ should become [[TEXT]]

我的代码：

import re


se1 = "+++TEXT:+++ Moshe Morgenstern is on his way to the main synagogue in the center of Bnei Brak, home to a largely ultra-orthodox - or haredi - community. +++ Karte Israel mit: Bnei Brak, Tel Aviv + Jerusalem ))+++"

comments = re.sub(r"\+\+\+.*?\+\+\+", r"[[.*?]]", se1)
print(comments)

但它给出了错误的输出

[[.*?]] Moshe Morgenstern is on his way to the main synagogue in the center of Bnei Brak, home to a largely ultra-orthodox - or haredi - community. [[.*?]]

Answer 1

您需要使用 () 捕获组，然后使用 </code></p> 引用该匹配组 <p>这应该可以正常工作：</p> <pre><code>>>> comments = re.sub(r"\+\+\+(.*?)\+\+\+", r"[[]]", se1) >>> comments '[[TEXT:]] Moshe Morgenstern is on his way to the main synagogue in the center of Bnei Brak, home to a largely ultra-orthodox - or haredi - community. [[ Karte Israel mit: Bnei Brak, Tel Aviv + Jerusalem ))]]'

考虑到 \+\+\+ 也可以简化为 \+{3}。

Answer 2

你可以使用这个：

re.sub(r'\+\+\+(.*?)\+\+\+',r'[[]]',se1)

由于第二个字符串中的.*?被视为纯字符串而不是匹配字符串中.*?的替换，(.*?)表示将这部分保存为在替换字符串中使用，是保存的数据。

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