link 中包含“&”时 WhatsApp 共享无法正常工作

Question

示例代码：

let sampleURL = "http://Hello/site/link?id=MTk=&fid=MTA="
let urlWhats = "whatsapp://send?text=\(sampleURL)"
if let urlString = urlWhats.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed) {
   if let whatsappURL = NSURL(string: urlString) {
      if UIApplication.shared.canOpenURL(whatsappURL as URL) {
           UIApplication.shared.open(whatsappURL as URL)
      }
      else {
           // Open App Store.
      }
   }
}

添加到 .plist 文件

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>whatsapp</string>
</array>

面临的问题是在与 & 分享 link 时文本没有出现在 &

之后

对于以上 url 文本即将出现 http://Hello/site/link?id=MTk=

提前致谢

Answer 1

尝试直接初始化为 URL 而不是 NSURL

let whatsappURL = URL(string: urlString)

并可能使用完成处理程序进一步调试

UIApplication.shared.open(whatsappURL, options: [:], completionHandler: nil)

Answer 2

经过一些研究和测试后，我发现在 AllowedCharacters 中使用 .urlQueryAllowed 将允许 URL 并且在 URL 这就是为什么会出现这个问题。

只需在您的文本中使用 .init()，而不包含在该编码中 whatsapp://send?text= 如下图

let sampleURL = "http://Hello/site/link?id=MTk=&fid=MTA="
if let urlString = sampleURL.addingPercentEncoding(withAllowedCharacters: .init()) {
    let urlWhats = "whatsapp://send?text=\(urlString)"
    if let whatsappURL = NSURL(string: urlWhats) {
       if UIApplication.shared.canOpenURL(whatsappURL as URL) {
            UIApplication.shared.open(whatsappURL as URL)
       }
    }
}

Answer 3

一个URL的不同部分有不同的编码规则。 addingPercentEncoding 很难正确使用。通常，您不应尝试对自己的 URL 进行编码。让系统为你做 URLComponents:

//For the constant part of the link, it's fine to just use a string
var sample = URLComponents(string: "whatsapp://send")!

// Then add a query item
sample.queryItems = [URLQueryItem(name: "text", value: "http://Hello/site/link?id=MTk=&fid=MTA=")]

// Extract the URL, which will have the correct encoding
print(sample.url!)
// whatsapp://send?text=http://Hello/site/link?id%3DMTk%3D%26fid%3DMTA%3D

link 中包含“&”时 WhatsApp 共享无法正常工作

WhatsApp share not working properly while "&" is contain in link

ios

whatsapp

swift