将 table 中的数据格式化为百分比

Question

我有一个如下所示的数据框：

这是创建此 DF 的代码：

structure(list(ethnicity = structure(c(1L, 2L, 3L, 5L), .Label = c("AS", 
"BL", "HI", "Others", "WH", "Total"), class = "factor"), `Strongly agree` = c(30.7, 
26.2, 37.4, 31.6), Agree = c(43.9, 34.5, 41, 45.4), `Neither agree nor disagree` = c(9.4, 
14.3, 8.6, 8.7), Disagree = c(10, 15.5, 9.9, 9.7), `Strongly disagree` = c(6, 
9.5, 3.2, 4.6)), row.names = c(NA, -4L), class = "data.frame")

我想添加数据条并将这些数字显示为百分比。我尝试使用格式 table 库来做到这一点（请参阅下面的代码）。

formattable(df,align=c("l","l","l","l","l","l"),
        list(`ethnicity` = formatter("span", style = ~ style(color = "grey", font.weight = "bold"))
            ,area(col = 2:6) ~ function(x) percent(x / 100, digits = 0)
            ,area(col = 2:6) ~ color_bar("#DeF7E9")))

我面临 2 个问题：

数字在 table 输出中不显示为百分比。
最后一列的对齐似乎不对，即

如果有人能帮助我理解我在这里缺少什么，我将不胜感激？

Answer 1

这是一个解决方案，但它需要大量输入，我想可以使用 mutate_at() 但我只是找不到如何在 percent() 部分传递列名.使用 . 会产生错误。

这适用于大量输入：

library(dplyr)
library(formattable)

df %>% 
  mutate(`Strongly agree` = color_bar("#DeF7E9")(formattable::percent(`Strongly agree`/100))) %>% 
  mutate(`Agree` = color_bar("#DeF7E9")(formattable::percent(`Agree`/100))) %>% 
  mutate(`Disagree` = color_bar("#DeF7E9")(formattable::percent(`Disagree`/100))) %>%
  mutate(`Neither agree nor disagree` = color_bar("#DeF7E9")(formattable::percent(`Neither agree nor disagree`/100))) %>%
  mutate(`Strongly disagree` = color_bar("#DeF7E9")(formattable::percent(`Strongly disagree`/100))) %>%
  formattable(.,
              align=c("l","l","l","l","l","l"),
              `ethnicity` = formatter("span", style = ~ style(color = "grey", font.weight = "bold")))

这不起作用，但可能会得到改进：

df %>% 
  mutate_at(.vars = 2:6, .funs = color_bar("#DeF7E9")(formattable::percent(./100))) %>% 
  formattable(...)

Some more informations about this "strange" structure var = color_bar(...)(var)

将 table 中的数据格式化为百分比

Formatting data in a table as percentage

r

formattable

kableextra