将字符串转换为时间戳 Java

Question

所以我遇到了这个问题，我无法解决这个问题。我读过类似的问题，但我发现格式有问题，我的格式是正确的。

基本上我在尝试将字符串转换为时间戳，但出现无法解析的日期错误。

import java.sql.Timestamp;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class Hello {

public static Timestamp convertStringToTimestamp(String str_date) {
    try {

        SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss,SSS");
        Date date = formatter.parse(str_date);
        java.sql.Timestamp timeStampDate = new Timestamp(date.getTime());
        return timeStampDate;

    } catch (ParseException e) {
        System.out.println("Exception :" + e);
        return null;
    }
}

public static void main(String[] args) {
    Timestamp ts = convertStringToTimestamp("2015-06-09 11:51:12,708");
    Timestamp ts2 = convertStringToTimestamp("2015-04-17 11:29:49.564");
    System.out.println(ts +" | "+ts2);


}

}

输出：

Exception :java.text.ParseException: Unparseable date: "2015-06-09 11:51:12,708"
Exception :java.text.ParseException: Unparseable date: "2015-04-17 11:29:49.564"
null | null

有什么想法吗？

Answer 1

**Update**
import java.sql.Timestamp;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;


public class SomeClass {

    public static void main(String[] args) {


         System.out.println(convertStringToTimestamp("2015-06-09 11:51:12,708"));
         //be consistent here with , and .
         System.out.println(convertStringToTimestamp("2015-04-17 11:29:49.564"));
         System.out.println();


    }

    private static Timestamp  convertStringToTimestamp(String something) {


SimpleDateFormat dateFormat = null;
        if(something.contains(".")) {
            dateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.SSS");
        } 
        if(something.contains(",")) {
            dateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss,SSS");
        }
        Timestamp timestamp = null;
            Date parsedDate;
            try {
                parsedDate = dateFormat.parse(something);
                 timestamp = new java.sql.Timestamp(parsedDate.getTime());

            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            return timestamp;
    }



}

Answer 2

这对我来说非常有用。

我刚刚将正确的模式作为输入传递。

public static Timestamp convertStringToTimestamp(String str_date, String pattern) {
        try {

            SimpleDateFormat formatter = new SimpleDateFormat(pattern);
            Date date = formatter.parse(str_date);
            java.sql.Timestamp timeStampDate = new Timestamp(date.getTime());
            return timeStampDate;

        } catch (ParseException e) {
            System.out.println("Exception :" + e);
            return null;
        }
    }

    public static void main(String[] args) {
        Timestamp ts = convertStringToTimestamp("2015-06-09 11:51:12,708", "yyyy-MM-dd HH:mm:ss,SSS");
        Timestamp ts2 = convertStringToTimestamp("2015-04-17 11:29:49.564", "yyyy-MM-dd HH:mm:ss.SSS");
        System.out.println(ts +" | "+ts2);


    }

输出为：

2015-06-09 11:51:12.708 | 2015-04-17 11:29:49.564

Answer 3

" 2015-06-09 11:51:12,708" 对我有用，但 " 2015-04-17 11:29:49.564" 不会。您为“，”指定了正则表达式，所以“。”不会。完全正常。

Answer 4

你需要修正逗号

Timestamp ts2 = convertStringToTimestamp("2015-04-17 11:29:49.564");

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