在 C# 中解构元组的性能损失?
Performance penalties to deconstructing tuples in c#?
如果我们这样做
var (hello, world) = GetHelloAndWorldStrings();
if (hello == "hello" && world == "world")
Environment.Exit(0);
除执行以下操作外,是否会产生任何额外费用:
var helloAndWorld = GetHelloAndWorldStrings();
if (helloAndWorld.Hello == "hello" && helloAndWorld.World == "world")
Environment.Exit(0);
还是全是语法糖——最终生成的代码总是使用 Item1 和 Item2。
它们生成的 IL 实际上是相同的,只有很小的 emitted 差异,However。 .. 他们可能会 jitted 并优化为 完全 相同的指令。
给定
private (String hello,string world) GetHelloAndWorldStrings()
{
return ("asdsd","sadfsdf");
}
...
public int Test1()
{
var asd = GetHelloAndWorldStrings();
if (asd.hello == "hello" && asd.world == "world")
return 1;
return 0;
}
public int Test2()
{
var (hello, world) = GetHelloAndWorldStrings();
if (hello == "hello" && world == "world")
return 1;
return 0;
}
基本上会发出作为
public int Test1()
{
ValueTuple<string, string> helloAndWorldStrings = GetHelloAndWorldStrings();
if (helloAndWorldStrings.Item1 == "hello" && helloAndWorldStrings.Item2 == "world")
{
return 1;
}
return 0;
}
public int Test2()
{
ValueTuple<string, string> helloAndWorldStrings = GetHelloAndWorldStrings();
string item = helloAndWorldStrings.Item1;
string item2 = helloAndWorldStrings.Item2;
if (item == "hello" && item2 == "world")
{
return 1;
}
return 0;
}
这里是 JIT ASM 的例子
C.Test1()
L0000: push ebp
L0001: mov ebp, esp
L0003: push esi
L0004: mov ecx, [0x11198648]
L000a: mov esi, [0x1119864c]
L0010: mov edx, [0x11198650]
L0016: call System.String.Equals(System.String, System.String)
L001b: test eax, eax
L001d: je short L0038
L001f: mov edx, [0x11198654]
L0025: mov ecx, esi
L0027: call System.String.Equals(System.String, System.String)
L002c: test eax, eax
L002e: je short L0038
L0030: mov eax, 1
L0035: pop esi
L0036: pop ebp
L0037: ret
L0038: xor eax, eax
L003a: pop esi
L003b: pop ebp
L003c: ret
对
C.Test2()
L0000: push ebp
L0001: mov ebp, esp
L0003: push esi
L0004: mov ecx, [0x11198648]
L000a: mov esi, [0x1119864c]
L0010: mov edx, [0x11198650]
L0016: call System.String.Equals(System.String, System.String)
L001b: test eax, eax
L001d: je short L0038
L001f: mov edx, [0x11198654]
L0025: mov ecx, esi
L0027: call System.String.Equals(System.String, System.String)
L002c: test eax, eax
L002e: je short L0038
L0030: mov eax, 1
L0035: pop esi
L0036: pop ebp
L0037: ret
L0038: xor eax, eax
L003a: pop esi
L003b: pop ebp
L003c: ret
简而言之,担心这个的净收益.. 减去你生命中的 5 分钟,你将永远无法回来
第三个选项与第一个相同:
public int Test3()
{
var asd = GetHelloAndWorldStrings();
if (asd == ("hello", "world"))
return 1;
return 0;
}
它同样翻译成(sharplab.io):
public int Test3()
{
ValueTuple<string, string> helloAndWorldStrings = GetHelloAndWorldStrings();
if (helloAndWorldStrings.Item1 == "hello" && helloAndWorldStrings.Item2 == "world")
{
return 1;
}
return 0;
}
.method public hidebysig
instance int32 Test3 () cil managed
{
// Method begins at RVA 0x2064
// Code size 47 (0x2f)
.maxstack 2
.locals init (
[0] valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string>
)
IL_0000: ldarg.0
IL_0001: call instance valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string> C::GetHelloAndWorldStrings()
IL_0006: stloc.0
IL_0007: ldloc.0
IL_0008: ldfld !0 valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string>::Item1
IL_000d: ldstr "hello"
IL_0012: call bool [System.Private.CoreLib]System.String::op_Equality(string, string)
IL_0017: brfalse.s IL_002d
IL_0019: ldloc.0
IL_001a: ldfld !1 valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string>::Item2
IL_001f: ldstr "world"
IL_0024: call bool [System.Private.CoreLib]System.String::op_Equality(string, string)
IL_0029: brfalse.s IL_002d
IL_002b: ldc.i4.1
IL_002c: ret
IL_002d: ldc.i4.0
IL_002e: ret
} // end of method C::Test3
如果我们这样做
var (hello, world) = GetHelloAndWorldStrings();
if (hello == "hello" && world == "world")
Environment.Exit(0);
除执行以下操作外,是否会产生任何额外费用:
var helloAndWorld = GetHelloAndWorldStrings();
if (helloAndWorld.Hello == "hello" && helloAndWorld.World == "world")
Environment.Exit(0);
还是全是语法糖——最终生成的代码总是使用 Item1 和 Item2。
它们生成的 IL 实际上是相同的,只有很小的 emitted 差异,However。 .. 他们可能会 jitted 并优化为 完全 相同的指令。
给定
private (String hello,string world) GetHelloAndWorldStrings()
{
return ("asdsd","sadfsdf");
}
...
public int Test1()
{
var asd = GetHelloAndWorldStrings();
if (asd.hello == "hello" && asd.world == "world")
return 1;
return 0;
}
public int Test2()
{
var (hello, world) = GetHelloAndWorldStrings();
if (hello == "hello" && world == "world")
return 1;
return 0;
}
基本上会发出作为
public int Test1()
{
ValueTuple<string, string> helloAndWorldStrings = GetHelloAndWorldStrings();
if (helloAndWorldStrings.Item1 == "hello" && helloAndWorldStrings.Item2 == "world")
{
return 1;
}
return 0;
}
public int Test2()
{
ValueTuple<string, string> helloAndWorldStrings = GetHelloAndWorldStrings();
string item = helloAndWorldStrings.Item1;
string item2 = helloAndWorldStrings.Item2;
if (item == "hello" && item2 == "world")
{
return 1;
}
return 0;
}
这里是 JIT ASM 的例子
C.Test1()
L0000: push ebp
L0001: mov ebp, esp
L0003: push esi
L0004: mov ecx, [0x11198648]
L000a: mov esi, [0x1119864c]
L0010: mov edx, [0x11198650]
L0016: call System.String.Equals(System.String, System.String)
L001b: test eax, eax
L001d: je short L0038
L001f: mov edx, [0x11198654]
L0025: mov ecx, esi
L0027: call System.String.Equals(System.String, System.String)
L002c: test eax, eax
L002e: je short L0038
L0030: mov eax, 1
L0035: pop esi
L0036: pop ebp
L0037: ret
L0038: xor eax, eax
L003a: pop esi
L003b: pop ebp
L003c: ret
对
C.Test2()
L0000: push ebp
L0001: mov ebp, esp
L0003: push esi
L0004: mov ecx, [0x11198648]
L000a: mov esi, [0x1119864c]
L0010: mov edx, [0x11198650]
L0016: call System.String.Equals(System.String, System.String)
L001b: test eax, eax
L001d: je short L0038
L001f: mov edx, [0x11198654]
L0025: mov ecx, esi
L0027: call System.String.Equals(System.String, System.String)
L002c: test eax, eax
L002e: je short L0038
L0030: mov eax, 1
L0035: pop esi
L0036: pop ebp
L0037: ret
L0038: xor eax, eax
L003a: pop esi
L003b: pop ebp
L003c: ret
简而言之,担心这个的净收益.. 减去你生命中的 5 分钟,你将永远无法回来
第三个选项与第一个相同:
public int Test3()
{
var asd = GetHelloAndWorldStrings();
if (asd == ("hello", "world"))
return 1;
return 0;
}
它同样翻译成(sharplab.io):
public int Test3()
{
ValueTuple<string, string> helloAndWorldStrings = GetHelloAndWorldStrings();
if (helloAndWorldStrings.Item1 == "hello" && helloAndWorldStrings.Item2 == "world")
{
return 1;
}
return 0;
}
.method public hidebysig
instance int32 Test3 () cil managed
{
// Method begins at RVA 0x2064
// Code size 47 (0x2f)
.maxstack 2
.locals init (
[0] valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string>
)
IL_0000: ldarg.0
IL_0001: call instance valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string> C::GetHelloAndWorldStrings()
IL_0006: stloc.0
IL_0007: ldloc.0
IL_0008: ldfld !0 valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string>::Item1
IL_000d: ldstr "hello"
IL_0012: call bool [System.Private.CoreLib]System.String::op_Equality(string, string)
IL_0017: brfalse.s IL_002d
IL_0019: ldloc.0
IL_001a: ldfld !1 valuetype [System.Private.CoreLib]System.ValueTuple`2<string, string>::Item2
IL_001f: ldstr "world"
IL_0024: call bool [System.Private.CoreLib]System.String::op_Equality(string, string)
IL_0029: brfalse.s IL_002d
IL_002b: ldc.i4.1
IL_002c: ret
IL_002d: ldc.i4.0
IL_002e: ret
} // end of method C::Test3