根据字符串将字符串列表拆分为子列表列表

Question

这个问题最容易用伪代码说明。我有一个这样的列表：

linelist = ["a", "b", "", "c", "d", "e", "", "a"]

我想以以下格式获取它：

questionchunks = [["a", "b"], ["c", "d", "e"], ["a"]]

我的第一次尝试是这样的：

questionchunks = []
qlist = []

for line in linelist:

    if (line != "" and len(qlist) != 0 ):
        questionchunks.append(qlist)
        qlist = []
    else: 
        qlist.append(line)

虽然我的输出有点乱。如果能得到任何指点，我将不胜感激。

Answer 1

这可以使用 itertools.groupby 轻松完成：

>>> from itertools import groupby
>>> linelist = ["a", "b", "", "c", "d", "e", "", "a"]
>>> split_at = ""
>>> [list(g) for k, g in groupby(linelist, lambda x: x != split_at) if k]
[['a', 'b'], ['c', 'd', 'e'], ['a']]

Answer 2

您离目标不远了，这是所需的最少修改

linelist = ["a", "b", "", "c", "d", "e", "", "a"]
questionchunks = []
qlist = []
linelist.append('') # append an empty str at the end to avoid the other condn
for line in linelist:

    if (line != "" ):
        questionchunks.append(line)      # add the element to each of your chunk   
    else: 
        qlist.append(questionchunks)   # append chunk
        questionchunks = []       # reset chunk

print qlist

根据字符串将字符串列表拆分为子列表列表

Split list of strings into list of sublists based on a string

python

string

list