从 Oracle 数据库 table 创建 json
Creating json from Oracle database table
您好,我必须从 Oracle table 创建 json 文件。我有以下表格的数据。
我想要这种格式的数据。
{
"add" :
[
{
"canonicalName" : "Apple Computers",
"synonyms" :
[
"Apple",
"Apple Inc"
]
},
{
"canonicalName" : "Google India",
"synonyms" :
[
"Google"
]
},
{
"canonicalName" : "IBM",
"synonyms" :
[
"IBM Corporation"
]
}
],
"delete" :
[
{
"canonicalName" : "IBM",
"synonyms" :
[
"IBM Corporation"
]
},
{
"canonicalName" : "TCS"
}
],
"update" :
[
{
"canonicalName" : "Infosys",
"synonyms" :
[
"Infosys Tech"
]
},
{
"canonicalName" : "Wipro Tech",
"synonyms" :
[
"Wipro Technology"
]
}
]
}
以下代码运行正常。
with
prep (operation, orgname, fragment) as (
select operation, orgname,
json_object( key 'canonicalName' value orgname,
key 'synonyms'
value nullif(json_arrayagg(synonyms order by synonyms), '[]')
FORMAT JSON ABSENT ON NULL
)
from t
group by orgname, operation
)
select json_objectagg( key operation
value json_arrayagg(fragment order by orgname)
) as json_str
from prep
group by operation;
现在我必须在此 table 中添加一个额外的列。
因此第 tablename
列包含“ORG”和“ITEM”值。所以我必须创建 2 个文件,一个是 item.json,另一个是 ORG.json,依此类推。
我需要将包含 ITEM 的数据放入 item.json,将包含 ORG 的数据放入 ORG.json。
我需要在上面的查询中做哪些更改。
即使 PL/SQL 也可以。您能否建议更改上述查询?
如果我们可以将结果存储到某个数组中并return调用环境
也很好
这是一种方法。您不需要提前知道 TABLENAME
列中的值。相反,查询输出将为 TABLENAME
中的每个唯一值一行,显示在两列中:TABLENAME 和该 TABLENAME 对应的 JSON 字符串。
with
prep1 (tablename, operation, orgname, fragment) as (
select tablename, operation, orgname,
json_object( key 'canonicalName' value orgname,
key 'synonyms'
value nullif(json_arrayagg(synonyms order by synonyms), '[]')
FORMAT JSON ABSENT ON NULL
)
from t
group by tablename, orgname, operation
)
, prep2 (tablename, operation, org_str) as (
select tablename, operation, json_arrayagg(fragment order by orgname)
from prep1
group by tablename, operation
)
select tablename, json_objectagg(key operation value org_str) as json_str
from prep2
group by tablename
;
TABLENAME JSON_STR
--------- ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
ITEM {"add":[{"canonicalName":"Apple Computers","synonyms":["Apple","Apple Inc"]},{"canonicalName":"Google India","synonyms":["Google"]},{"canonicalName":"IBM","synonyms":["IBM Corporation"]}],"update":[{"canonicalName":"Infosys","synonyms":["Infosys Tech"]},{"canonicalName":"Wipro Tech","synonyms":["Wipro Technology"]}],"delete":[{"canonicalName":"IBM","synonyms":["IBM Corporation"]},{"canonicalName":"TCS"}]}
ORG {"add":[{"canonicalName":"Apple Computers","synonyms":["Apple","Apple Inc"]},{"canonicalName":"Google India","synonyms":["Google"]},{"canonicalName":"IBM","synonyms":["IBM Corporation"]}],"update":[{"canonicalName":"Infosys","synonyms":["Infosys Tech"]},{"canonicalName":"Wipro Tech","synonyms":["Wipro Technology"]}],"delete":[{"canonicalName":"IBM","synonyms":["IBM Corporation"]},{"canonicalName":"TCS"}]}
您好,我必须从 Oracle table 创建 json 文件。我有以下表格的数据。
我想要这种格式的数据。
{
"add" :
[
{
"canonicalName" : "Apple Computers",
"synonyms" :
[
"Apple",
"Apple Inc"
]
},
{
"canonicalName" : "Google India",
"synonyms" :
[
"Google"
]
},
{
"canonicalName" : "IBM",
"synonyms" :
[
"IBM Corporation"
]
}
],
"delete" :
[
{
"canonicalName" : "IBM",
"synonyms" :
[
"IBM Corporation"
]
},
{
"canonicalName" : "TCS"
}
],
"update" :
[
{
"canonicalName" : "Infosys",
"synonyms" :
[
"Infosys Tech"
]
},
{
"canonicalName" : "Wipro Tech",
"synonyms" :
[
"Wipro Technology"
]
}
]
}
以下代码运行正常。
with
prep (operation, orgname, fragment) as (
select operation, orgname,
json_object( key 'canonicalName' value orgname,
key 'synonyms'
value nullif(json_arrayagg(synonyms order by synonyms), '[]')
FORMAT JSON ABSENT ON NULL
)
from t
group by orgname, operation
)
select json_objectagg( key operation
value json_arrayagg(fragment order by orgname)
) as json_str
from prep
group by operation;
现在我必须在此 table 中添加一个额外的列。
因此第 tablename
列包含“ORG”和“ITEM”值。所以我必须创建 2 个文件,一个是 item.json,另一个是 ORG.json,依此类推。
我需要将包含 ITEM 的数据放入 item.json,将包含 ORG 的数据放入 ORG.json。
我需要在上面的查询中做哪些更改。
即使 PL/SQL 也可以。您能否建议更改上述查询?
如果我们可以将结果存储到某个数组中并return调用环境
也很好这是一种方法。您不需要提前知道 TABLENAME
列中的值。相反,查询输出将为 TABLENAME
中的每个唯一值一行,显示在两列中:TABLENAME 和该 TABLENAME 对应的 JSON 字符串。
with
prep1 (tablename, operation, orgname, fragment) as (
select tablename, operation, orgname,
json_object( key 'canonicalName' value orgname,
key 'synonyms'
value nullif(json_arrayagg(synonyms order by synonyms), '[]')
FORMAT JSON ABSENT ON NULL
)
from t
group by tablename, orgname, operation
)
, prep2 (tablename, operation, org_str) as (
select tablename, operation, json_arrayagg(fragment order by orgname)
from prep1
group by tablename, operation
)
select tablename, json_objectagg(key operation value org_str) as json_str
from prep2
group by tablename
;
TABLENAME JSON_STR
--------- ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
ITEM {"add":[{"canonicalName":"Apple Computers","synonyms":["Apple","Apple Inc"]},{"canonicalName":"Google India","synonyms":["Google"]},{"canonicalName":"IBM","synonyms":["IBM Corporation"]}],"update":[{"canonicalName":"Infosys","synonyms":["Infosys Tech"]},{"canonicalName":"Wipro Tech","synonyms":["Wipro Technology"]}],"delete":[{"canonicalName":"IBM","synonyms":["IBM Corporation"]},{"canonicalName":"TCS"}]}
ORG {"add":[{"canonicalName":"Apple Computers","synonyms":["Apple","Apple Inc"]},{"canonicalName":"Google India","synonyms":["Google"]},{"canonicalName":"IBM","synonyms":["IBM Corporation"]}],"update":[{"canonicalName":"Infosys","synonyms":["Infosys Tech"]},{"canonicalName":"Wipro Tech","synonyms":["Wipro Technology"]}],"delete":[{"canonicalName":"IBM","synonyms":["IBM Corporation"]},{"canonicalName":"TCS"}]}