如何将 python 字典发送到 C++

Question

这是我的 python 函数：

if __name__ == "__main__":
    file = open("data_input.txt", "r")
    contents = file.read()
    e = ast.literal_eval(contents)
    neighbour_num= 4
    new_data = 300
    result = np.ndarray((4,4),dtype='int32',buffer=np.zeros((4,4),dtype='int32'))
    c_module.mmult_wrapper(e, new_data, neighbour_num, result)

这是我的 C++ 函数，我想在其中使用字典作为数组

   void mmult(double new_data, double neighbour_num, double e[100], int32_t result[16]) {
   double distances[100];
   unsigned distances_front = 0;
   unsigned distances_back = 0;

   double keys[100];
   unsigned keys_front = 0;
   unsigned keys_back = 0;
 

   for(int i=0;i<(int)100; i=i+1) {

      double temp_distance=(new_data-e[i]);

      double sq_tmp=(temp_distance*temp_distance);

      double sqrt=(sq_tmp/2);

      double temp=0;
      while(sqrt!=temp) {
         temp = sqrt;
         sqrt = (((sq_tmp/temp)+temp)/2);
      }
      distances[distances_front++] = (sqrt);
      keys[keys_front++] = (e[i-1]);
   }
   for(int i=0; i<(int)(keys_front - keys_back); i=i+1) {
      for(int j=(i+1); j<(int)(distances_front - distances_back); j=j+1) {
         if(distances[i]>distances[j]) {
            distances[i] = distances[j];
            distances[j] = distances[i];
            keys[i] = keys[j];
            keys[j] = keys[i];
         }
      }
   }
   for(int i=0; i<(int)neighbour_num; i=i+1) {
      result[i] = keys[i];
   }
}

这是我的包装函数

#include <Python.h>
#include <numpy/arrayobject.h>
#include "spyc.h"
#include "caller.h"

static PyObject* mmult_wrapper(PyObject* self, PyObject* args) {

   int32_t e;
   int32_t new_data;
   int32_t neighbour_num;
   int32_t result;

   int res = PyArg_ParseTuple(args, "Oi", &e_obj, &d);

   if (!res)
      return NULL;


   /* call function */
   mmult_caller(e,d);

}

My objective 接受来自 python 函数的字典值，并将其转换为适合包装器中 C 的数组值。我没有 C\C++ 的先验知识，我被卡住了。任何帮助都会有很大帮助。谢谢

Answer 1

您可能需要包括 dictobject.h、floatobject.h、，如果尚未通过其他 headers 引入。这是一种将所有值从浮点数字典中获取到向量的方法。根据字典中的实际内容以及它的结构，您可能需要查看键和其他部分。请注意，这是 C++，因此应该这样编译。


//returns true on success
bool dictToVector(PyObject *  srcDict, std::vector<double> & destVector) {
 destVector.clear();
 if(PyDict_Check(srcDict)) {
  Py_ssize_t numItems = PyDict_Size(srcDict);
  destVector.reserve(numItems);
  Py_ssize_t iteratorPPOS = 0;
  PyObject * currentVal;
  while(PyDict_Next(srcDict, &iteratorPPOS, NULL, &currentVal) {
   // might be worth checking PyFloat_Check...
   destVector.push_back(PyFloat_AsDouble(currentVal));
  }
  return (numItems == destVector.size());
 }
 else { // not a dict return with failure
  return false;
 }
}

你的包装器最后会很相似，因为它需要将 mmult 的结果复制到结果类型 numpy.ndarray。

上面的用法类似于：


PyObject* mmult_wrapper(PyObject * e, PyObject * new_data, PyObject * neighbour_num, PyObject * result) {
 int32_t Cresult[16];
 std::vector<double> Ce;
 bool noErrorSoFar = dictToVector(e,Ce);
 if(Ce.size() == 100) {
  mmult(PyFloat_AsDouble(new_data) , PyFloat_AsDouble( neighbour_num), Ce.data(), Cresult);
 }
else { // not 100 doubles in the data read!
  noErrorSoFar = false;
 }

... //some stuff to copy Cresult to the python, and return something meaningful?
}

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