克隆方法是否克隆覆盖的方法?

Does the clone method clone overridden methods?

如果我克隆了下面class的一个实例,并在实例化时重写了一个方法,那么克隆会有被重写的方法吗?我没有发现任何关于这种行为的信息 https://docs.oracle.com/javase/7/docs/api/java/lang/Cloneable.html nor https://docs.oracle.com/javase/7/docs/api/java/lang/Object.html#clone() .

public class ToBeCloned implements Cloneable{
    public int returnInt() {
        return 1;
    }
    public void printTest() {
        System.out.println("returnInt():"+returnInt()+"\nToBeCloned Original");
    }
    @Override
    public ToBeCloned clone() throws CloneNotSupportedException {
        return (ToBeCloned) super.clone();
    }
}

答案是肯定的,克隆将至少包含 javaSE-1.8 中的重写方法。

下面的程序及其输出说明了这一点:

public class OverridingMethods {
    public static void main(final String[] args) {
        final ToBeCloned toBeCloned1 = new ToBeCloned();
        final ToBeCloned toBeCloned2 = new ToBeCloned() {
            @Override
            public int returnInt() {
                return 2;
            }
            @Override
            public void printTest() {
                System.out.println("returnInt():"+returnInt()+"\nToBeCloned Overridden");
            }
        };
        ToBeCloned toBeCloned3 = null;
        ToBeCloned toBeCloned4 = null;
        ToBeCloned toBeCloned5 = null;
        try {
            toBeCloned3 = toBeCloned1.clone();
            toBeCloned4 = toBeCloned2.clone();
            toBeCloned5 = toBeCloned4.clone();
        } catch (final CloneNotSupportedException e) {
            e.printStackTrace();
        }
        toBeCloned1.printTest();
        toBeCloned2.printTest();
        toBeCloned3.printTest();
        toBeCloned4.printTest();
        toBeCloned5.printTest();
    }
}

程序的输出如下:

returnInt():1
ToBeCloned Original
returnInt():2
ToBeCloned Overridden
returnInt():1
ToBeCloned Original
returnInt():2
ToBeCloned Overridden
returnInt():2
ToBeCloned Overridden

这证明覆盖的方法被保留,即使克隆已经克隆的实例。

如果你这样做

new ToBeCloned() { @Override...}

这只是创建子类并实例化它的一种简短方法。如果您克隆该实例,您将获得同一个匿名子类的另一个实例,具有所有相同的方法。