ruby 深度字符串化哈希
ruby deep stringify hash
我想在 ruby 中深度字符串化哈希,就像每个嵌套哈希也需要是字符串
输入:
{"command": "subscribe", "identifier": { "channel": "TxpoolChannel" } }
输出:
"{\"command\":\"subscribe\",\"identifier\":\"{\\"channel\\":\\"TxpoolChannel\\"}\"}"
是否有现成的函数或gem来实现这个结果?
require 'json'
def deep_to_json(h)
h.transform_values{|v| v.is_a?(Hash) ? deep_to_json(v) : v}.to_json
end
deep_to_json({"command": "subscribe", "identifier": { "channel": "TxpoolChannel" } })
#=> "{\"command\":\"subscribe\",\"identifier\":\"{\\"channel\\":\\"TxpoolChannel\\"}\"}"
但问题是,为什么你需要这样做?
str = '{"co": "su", "id": {"ch": "Tx"}, "pig": {1: :b}, "cat": { "dog": "Woof" } }'
#=> "{\"co\": \"su\", \"id\": {\"ch\": \"Tx\"}, \"pig\": {1: :b}, \"cat\": { \"dog\": \"Woof\" } }"
r = /
(?= # begin a positive lookahead
" # match a double-quote
[^{}]* # match 0* characters other than '{' and '}'
\} # match '}'
) # end positive lookahead
/x # invoke free-spacing regex definition mode
这个正则表达式约定俗成如下
r = /(?="[^{}]*\})/
它匹配 zero-width 位置前面的 double-quote 后跟除左大括号以外的任意数量的字符,后跟右大括号,这意味着 double-quote 是在由大括号分隔的字符串中。这假设,如问题中给出的示例,大括号未嵌套。
s = str.gsub(r, "\")
#=> "{\"co\": \"su\", \"id\": {\\"ch\\": \\"Tx\\"}, \"pig\": {1: :b}, \"cat\": { \\"dog\\": \\"Woof\\" } }"
puts s
{"co": "su", "id": {\"ch\": \"Tx\"}, "pig": {1: :b}, "cat": { \"dog\": \"Woof\" } }
我想在 ruby 中深度字符串化哈希,就像每个嵌套哈希也需要是字符串
输入:
{"command": "subscribe", "identifier": { "channel": "TxpoolChannel" } }
输出:
"{\"command\":\"subscribe\",\"identifier\":\"{\\"channel\\":\\"TxpoolChannel\\"}\"}"
是否有现成的函数或gem来实现这个结果?
require 'json'
def deep_to_json(h)
h.transform_values{|v| v.is_a?(Hash) ? deep_to_json(v) : v}.to_json
end
deep_to_json({"command": "subscribe", "identifier": { "channel": "TxpoolChannel" } })
#=> "{\"command\":\"subscribe\",\"identifier\":\"{\\"channel\\":\\"TxpoolChannel\\"}\"}"
但问题是,为什么你需要这样做?
str = '{"co": "su", "id": {"ch": "Tx"}, "pig": {1: :b}, "cat": { "dog": "Woof" } }'
#=> "{\"co\": \"su\", \"id\": {\"ch\": \"Tx\"}, \"pig\": {1: :b}, \"cat\": { \"dog\": \"Woof\" } }"
r = /
(?= # begin a positive lookahead
" # match a double-quote
[^{}]* # match 0* characters other than '{' and '}'
\} # match '}'
) # end positive lookahead
/x # invoke free-spacing regex definition mode
这个正则表达式约定俗成如下
r = /(?="[^{}]*\})/
它匹配 zero-width 位置前面的 double-quote 后跟除左大括号以外的任意数量的字符,后跟右大括号,这意味着 double-quote 是在由大括号分隔的字符串中。这假设,如问题中给出的示例,大括号未嵌套。
s = str.gsub(r, "\")
#=> "{\"co\": \"su\", \"id\": {\\"ch\\": \\"Tx\\"}, \"pig\": {1: :b}, \"cat\": { \\"dog\\": \\"Woof\\" } }"
puts s
{"co": "su", "id": {\"ch\": \"Tx\"}, "pig": {1: :b}, "cat": { \"dog\": \"Woof\" } }