显示空视图后过滤器列表不会重新出现

Question

出于某种原因，在显示没有匹配项目的空视图后，我的列表视图在从搜索视图中删除所有文本后不会重新出现。

Within my adapter class, AFAIK .clear() in mData.clear(); needs to change to something else but I don't know what to.

ItemListAdapter class

public class ItemListAdapter extends BaseAdapter implements Filterable {

    private List<Victoria> mData;
    private List<Victoria> mFilteredData;
    private LayoutInflater mInflater;
    private ItemFilter mFilter;

    public ItemListAdapter (List<Victoria> data, Context context) {
        mData = data;
        mFilteredData = new ArrayList(mData);
        mInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    }

    @Override
    public int getCount() {
        return mFilteredData.size();
    }

    @Override
    public String getItem(int position) {
        return mFilteredData.get(position).getItem();
    }

    @Override
    public long getItemId(int position) {
        return position;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {

        ViewHolder holder;
        if (convertView == null) {
           convertView = mInflater.inflate(R.layout.item_row, parent, false);
            holder = new ViewHolder();

            holder.title = (TextView) convertView.findViewById(R.id.item_title);
            holder.description = (TextView) convertView.findViewById(R.id.item_description);

            convertView.setTag(holder);
        } else {
            holder = (ViewHolder) convertView.getTag();
        }

        holder.title.setText(mFilteredData.get(position).getItem());
        holder.description.setText(mFilteredData.get(position).getItemDescription());

        return convertView;
    }

    @Override
    public Filter getFilter() {
        if (mFilter == null) {
            mFilter = new ItemFilter();
        }
        return mFilter;
    }

    /**
     * View holder
     */
    static class ViewHolder {
        private TextView title;
        private TextView description;
    }

    /**
     * Filter for filtering list items
     */
    /**
     * <p>An array filter constrains the content of the array adapter with
     * a prefix. Each item that does not start with the supplied prefix
     * is removed from the list.</p>
     */
    private class ItemFilter extends Filter {
        @Override
        protected FilterResults performFiltering(CharSequence constraint) {
            FilterResults results = new FilterResults();

            if (TextUtils.isEmpty(constraint)) {
                results.count = mData.size();
                results.values = mData;
            } else {
                //Create a new list to filter on
                List<Victoria> resultList = new ArrayList<Victoria>();
                for (Victoria str : mData) {
                    if (str.getItemDescription().toLowerCase().contains(constraint.toString().toLowerCase())) {
                        resultList.add(str);
                    }
                }
                results.count = resultList.size();
                results.values = resultList;
            }
            return results;
        }

        /**
         * Runs on ui thread
         * @param constraint the constraint used for the result
         * @param results the results to display
         */
        @SuppressWarnings("unchecked")
        @Override
        protected void publishResults(CharSequence constraint, FilterResults results) {
            if (results.count == 0) {
                //Make list invisible
                //Make text view visible
                mFilteredData.clear();
                notifyDataSetInvalidated();
            } else {
                mFilteredData = (ArrayList<Victoria>)results.values;
                notifyDataSetChanged();
            }
        }
    }
}

过滤前

使用无效字符过滤后

清除搜索视图并再次尝试显示列表后

Answer 1

您正在修改包含原始数据的数组，当de Adapter 重新创建列表时，该数组没有数据。

正确的做法是创建原始数组的副本，return每次过滤列表时都将副本作为结果，保持原始数据不变。在 ArrayAdapter 实现中可以找到一个很好的例子。见源码here.

为了以防万一，我将在此处包含源代码的副本：

/**
 * <p>An array filter constrains the content of the array adapter with
 * a prefix. Each item that does not start with the supplied prefix
 * is removed from the list.</p>
 */
private class ArrayFilter extends Filter {
    @Override
    protected FilterResults performFiltering(CharSequence prefix) {
        FilterResults results = new FilterResults();
        if (mOriginalValues == null) {
            synchronized (mLock) {
                mOriginalValues = new ArrayList<T>(mObjects);
            }
        }
        if (prefix == null || prefix.length() == 0) {
            ArrayList<T> list;
            synchronized (mLock) {
                list = new ArrayList<T>(mOriginalValues);
            }
            results.values = list;
            results.count = list.size();
        } else {
            String prefixString = prefix.toString().toLowerCase();
            ArrayList<T> values;
            synchronized (mLock) {
                values = new ArrayList<T>(mOriginalValues);
            }
            final int count = values.size();
            final ArrayList<T> newValues = new ArrayList<T>();
            for (int i = 0; i < count; i++) {
                final T value = values.get(i);
                final String valueText = value.toString().toLowerCase();
                // First match against the whole, non-splitted value
                if (valueText.startsWith(prefixString)) {
                    newValues.add(value);
                } else {
                    final String[] words = valueText.split(" ");
                    final int wordCount = words.length;
                    // Start at index 0, in case valueText starts with space(s)
                    for (int k = 0; k < wordCount; k++) {
                        if (words[k].startsWith(prefixString)) {
                            newValues.add(value);
                            break;
                        }
                    }
                }
            }
            results.values = newValues;
            results.count = newValues.size();
        }
        return results;
    }
    @Override
    protected void publishResults(CharSequence constraint, FilterResults results) {
        //noinspection unchecked
        mObjects = (List<T>) results.values;
        if (results.count > 0) {
            notifyDataSetChanged();
        } else {
            notifyDataSetInvalidated();
        }
    }

Answer 2

一些小的修复应该会让事情适合你。首先，mData 和 mFilteredData 数据应该始终是两个不同的实例。在构造函数中，让 mFilteredData 成为从 mData

复制的新实例

mFilteredData = new ArrayList(mData);

另外在Filter中，您需要更新相应的代码如下：

if (TextUtils.isEmpty(constraint)) {
    results.count = mData.size();
    results.values = new ArrayList(mData);
}

那么您的 getView() 方法应该从 mFilteredData 而不是 mData 中提取。但理想情况下，getView() 方法应该使用 getItem(position) 方法来访问数据。这样，如果您更改从何处访问数据的实现细节，则不必记得单独更新 getView() 方法。

最后，作为旁注，您的过滤代码之所以有效，只是因为适配器没有改变 mFilteredData 或 mData。通常，必须大量 synchronize 过滤过程和适配器的其他部分，因为 performFiltering() 发生在后台线程上。如果您计划在构建后添加对修改适配器数据的支持...那么您需要开始添加 synchronized 块。

显示空视图后过滤器列表不会重新出现

Filter list not reappearing after empty view shown

java

android

android-activity

android-listview

android-listfragment