如何将与星期一相同数量的工作日分配给周末

Question

我有一个日期维度 table，我需要在其中添加 NumberofBusinessDay 列，它会告诉我它是工作日的天数。例如：

Date        WeekendFlag  BusinessDayFlag  **NumberofBusinessDay** 
01/01/2015  N            N                0
01/02/2015  N            Y                1
01/03/2015  Y            N                2
01/04/2015  Y            N                2
01/05/2015  N            Y                2

我已经将工作日分配给工作日，但我正在努力为周末分配一个数字，这将与下一个工作日相同 - 星期一（如果星期一是假期，它将是星期二），如上图table。这是我目前所拥有的：

Date        WeekendFlag  BusinessDayFlag  **NumberofBusinessDay** 
01/01/2015  N            N                0
01/02/2015  N            Y                1
01/03/2015  Y            N                NULL
01/04/2015  Y            N                NULL
01/05/2015  N            Y                2

如有任何帮助，我们将不胜感激

我为工作日分配 BusinessDays 的查询（仅 2015 年数据）：

SELECT Date, WeekendFlag, BusinessDayFlag
       ,NumberofBusinessDay = CASE WHEN WeekendFlag = 'N' THEN 
       ROW_NUMBER() OVER (Partition BY YearCode, MonthCode ORDER BY WeekendFlag, Date ASC) 
       END
INTO #test
FROM DimDate
WHERE Date between '01/01/2015' AND '12/31/2015' --for testing purposes only
ORDER BY Date ASC

仅供参考 - 将周末记为工作日的目的是因为我们不想错过周末发生的任何活动（有可能），我们希望在下一个工作日计算这些活动。

Answer 1

在 SQL Server 2012+ 中，您可以使用累加和来执行此操作：

select dd.*,
       sum(case when BusinessDayFlag = 'Y' then 1 else 0 end) over (order by date) as NumberOfBusinessDay
from DateDimension;

您可以将其放入更新中：

with toupdate as (
      select dd.*,
             sum(case when BusinessDayFlag = 'Y' then 1 else 0 end) over (order by date) as newNumberOfBusinessDay
      from DateDimension
     )
update toupdate
    set NumberOfBusinessDay = newNumberOfBusinessDay;

在 SQL 服务器的早期版本中，您可以使用 cross apply.

做类似的事情

编辑：

根据您的样本数据，您计算的似乎是工作日，而不是工作日。如果是这样，上面只是使用了错误的变量：

with toupdate as (
      select dd.*,
             sum(case when WeekEndFlag = 'N' then 1 else 0 end) over (order by date) as newNumberOfBusinessDay
      from DateDimension
     )
update toupdate
    set NumberOfBusinessDay = newNumberOfBusinessDay;

这是基于您的示例结果。请注意，这可能是 off-by-1，因此您应该减去 1。不过，根据描述，我不明白为什么第一行的值为 0 而不是 1。

Answer 2

检查下面sql

---- below code will crete table for businessday calculation
create table dimension  (calenderdate date,WeekendFlag  char(1) ,BusinessDayFlag   char(1),NumberofBusinessDay int)

declare  @yearstartdate date
declare  @yearenddate date

SELECT   @yearstartdate = DATEADD(yy, DATEDIFF(yy,0,getdate()), 0) 
SELECT   @yearenddate =DATEADD(yy, DATEDIFF(yy,0,getdate()) + 1, -1)

while datediff (dd,@yearstartdate,DATEADD(DD,1,@yearenddate)) <>0
begin
 insert into dimension 
 select @yearstartdate ,
 case when datename(DW,@yearstartdate) = 'SUNDAY' or datename(DW,@yearstartdate) = 'SATURDAY'
 then 'Y' else 'N' end,
 case when datename(DW,@yearstartdate) = 'SUNDAY' or datename(DW,@yearstartdate) = 'SATURDAY'
 then 'N' else 'Y' end,
 null

 set @yearstartdate = dateadd(dd,1,@yearstartdate)
end
-----verify table
SELECT * FROM dimension 

-----calculate NumberofBusinessDay number  from below code

;with ctebusinessday
as
(
 select calenderdate,
sum(
case when BusinessDayFlag = 'Y' then 1 else 0 end
   ) over (order by calenderdate) as NOfBusinessDay
   from dimension 
)
update b
set b.NumberofBusinessDay =c.NOfBusinessDay
from dimension  b join ctebusinessday c
on b.calenderdate = c.calenderdate
  
  
update dimension 
set NumberofBusinessDay = NumberofBusinessDay + 1
where weekendflag = 'Y'
--verify table
select * from dimension

您可以将任何日期更新为工作日或周末，并从 NumberofBusinessDay 计算代码部分计算 NumberofBusinessDay。我只将星期六标记为周末并填充 table

谢谢

如何将与星期一相同数量的工作日分配给周末

How to assign a same number of business day as Monday to weekend days

sql

sql-server

date

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