Swift OpenWeatherMap API 类型值 'Any' 错误

Question

嘿，我的 swift 代码出错了

Value of type 'Any' has no subscripts

在这一行

if let weatherArray = jsonObj.value(forKey: "weather") as? NSArray {
print("Type \(weatherArray[0]["main"])")
}

我不知道如何修复它我尝试在网上搜索，但我并没有找到解决方案

其余代码

        let session = URLSession.shared
        let weatherURL = url!
        let dataTask = session.dataTask(with: weatherURL) {
        (data: Data?, response: URLResponse?, error: Error?) in
        if let error = error {
            print("Error:\n\(error)")
            }
            
        else {
            if let data = data {
                
                let dataString = String(data: data, encoding: String.Encoding.utf8)
                print("All the weather data:\n\(dataString!)")
                if let jsonObj = try? JSONSerialization.jsonObject(with: data, options: .allowFragments) as? NSDictionary {
                    if let mainDictionary = jsonObj.value(forKey: "main") as? NSDictionary {
                        if let temperature = mainDictionary.value(forKey: "feels_like") {
                            DispatchQueue.main.async {
                                print("Feels like: \(temperature)°C")
                            }
                        }
                    }
                    if let weatherArray = jsonObj.value(forKey: "weather") as? NSArray {
                        print("Type \(weatherArray[0]["main"])")
                
                    }

Answer 1

if let weatherArray = jsonObj.value(forKey: "weather") as? NSArray {
    print("Type \(weatherArray[0]["main"])")
}

你必须再次将你的项目投射到 NSDictionary

if let weatherArray = jsonObj.value(forKey: "weather") as? NSArray,
    let inner = weatherArray[0] as? NSDictionary {
        print("Type \(inner["main"])")
}

Answer 2

您的 weatherArray 是一个未转换值的数组，类似于 [Any]。当您尝试评估 weatherArray[0]["main"] 时，您正在引用类型 Any 的第一个元素并尝试获取带有下标的内容，但 Any 没有实现，因此您会收到错误。

Swift OpenWeatherMap API 类型值 'Any' 错误

Swift OpenWeatherMap API Value of type 'Any' error

api

ios

swift

openweathermap