如何确保在小矩形碰到任何边界（即屏幕移动）后立即显示文本

Question

我正在尝试在移动的小矩形到达边界后显示 'You loose like the looser you are looser' 文本... 但是相反，矩形正在移动越过边界，并且 'You loose' 文本仅在我按下随机按钮后才会出现... 代码如下

import pygame
import time

#initialize
pygame.init()

#colors
red = (255, 0, 0)
green = (0, 255, 0)
blue = (0, 0, 255)
cyan = (0, 255, 255)
black = (0, 0, 0)
grey = (92, 92, 92)
whiteish = (192, 192, 192)
 
#dimensions
width = 800
height = 600

#display surface
window = pygame.display.set_mode((width, height))
window.fill(whiteish)
pygame.display.set_caption('Slither')

#some constant variables
my_font = pygame.font.SysFont(None, 25)
clock = pygame.time.Clock()

def message(msg, color):
    txt = my_font.render(msg, True, color )
    window.blit(txt, [0, 0])

def loop():
    #some variables
    x = int(width/2)
    y = int(height/2)
    delta_x = 0
    delta_y = 0

    #misc vars

    block_size = 10
    apple_x = random.randint(0, height-block_size)
    apple_y = random.randint(0, width - block_size)
    
    fps = 13
    run = True

    while run:
        for event in pygame.event.get():
            if event.type ==pygame.QUIT:
                run = False
            if event.type == pygame.KEYDOWN:
                if event.key == pygame.K_LEFT:
                    delta_x = -block_size
                    delta_y = 0
                if event.key == pygame.K_RIGHT:
                    delta_x = block_size
                    delta_y = 0
                if event.key == pygame.K_UP:
                    delta_x = 0
                    delta_y = -block_size
                if event.key == pygame.K_DOWN:
                    delta_x = 0
                    delta_y = block_size
                if x < 0 or x > width - block_size or y < 0 or y > height - block_size:
                    run = False
        x = x + delta_x
        y = y + delta_y

        window.fill(whiteish)
        pygame.draw.rect(window, (0, 192, 0), (x, y, block_size, block_size), 2)
        clock.tick(fps)
        pygame.display.update()

    message('You loose like the loose you are , LOOSER!', red)
    pygame.display.update()
    time.sleep(2)
    pygame.quit()

loop()

如您所见，上面的代码应该有一个小方块，它会在单击箭头按钮时在屏幕上移动，并继续沿它移动的方向移动，直到按下另一个箭头。现在，当方块到达边界时，应该会出现一条红色文本，程序会在 2 秒后自动关闭。用于处理边界碰撞的代码是这样的...

if x < 0 or x > width - block_size or y < 0 or y > height - block_size:
                    run = False

以上代码跳出无限'while run'循环，跳转到这部分

    message('You loose like the loose you are , LOOSER!', red)
    pygame.display.update()
    time.sleep(2)
    pygame.quit()

但是，文本不会在方块撞到墙壁后立即显示，而是在按下随机按钮后显示

Answer 1

现在你只在有特定事件时执行你的碰撞代码，因为它在事件循环内缩进，所以只有在有事件发生时才会发生，在你的情况下是按键。

for event in pygame.event.get():
    # other code
    if x < 0 or x > width - block_size or y < 0 or y > height - block_size:
         run = False

解决问题只需un-indent那段代码。

while run:
    for event in pygame.event.get():
        if event.type ==pygame.QUIT:
            run = False
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                delta_x = -block_size
                delta_y = 0
            if event.key == pygame.K_RIGHT:
                delta_x = block_size
                delta_y = 0
            if event.key == pygame.K_UP:
                delta_x = 0
                delta_y = -block_size
            if event.key == pygame.K_DOWN:
                delta_x = 0
                delta_y = block_size
      if x < 0 or x > width - block_size or y < 0 or y > height - block_size:
          run = False

如何确保在小矩形碰到任何边界（即屏幕移动）后立即显示文本

how to ensure the text shows immediately after the small rectangle hits any of the bounderies i.e moves of the screen

python

pygame

boundary

collision