如何在 many2many 字段上使用 write() 方法?
How to use write() Method on a many2many field?
~...py
@api.onchange('test_record')
def abcde(self):
rec = self.test_record.id
res = self.env['anc'].browse(rec)
res.write({'partner_id': (4,self.partner_id.id)})
在上面的代码中,我试图做的是更新浏览模型中的合作伙伴(res),但是名为 partner_id 的字段是一个 many2many 字段,我们可以在其中 select 多个合作伙伴.
请注意,这仅适用于 many2many
或 one2many
,如下所示:
(0, 0, { values }) link to a new record that needs to be created with the given values dictionary
(1, ID, { values }) update the linked record with id = ID (write *values* on it)
(2, ID) remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
(3, ID) cut the link to the linked record with id = ID (delete the relationship between the two objects but does not delete the target object itself)
(4, ID) link to existing record with id = ID (adds a relationship)
(5) unlink all (like using (3,ID) for all linked records)
(6, 0, [IDs]) replace the list of linked IDs (like using (5) then (4,ID) for each ID in the list of IDs)
但在你的情况下可能是 many2one
应该是
def abcde(self):
rec = self.test_record.id
res = self.env['anc'].browse(rec)
res.write({'partner_id':[(4,self.partner_id.id)]}) # you need to add it as list
~...py
@api.onchange('test_record')
def abcde(self):
rec = self.test_record.id
res = self.env['anc'].browse(rec)
res.write({'partner_id': (4,self.partner_id.id)})
在上面的代码中,我试图做的是更新浏览模型中的合作伙伴(res),但是名为 partner_id 的字段是一个 many2many 字段,我们可以在其中 select 多个合作伙伴.
请注意,这仅适用于 many2many
或 one2many
,如下所示:
(0, 0, { values }) link to a new record that needs to be created with the given values dictionary
(1, ID, { values }) update the linked record with id = ID (write *values* on it)
(2, ID) remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
(3, ID) cut the link to the linked record with id = ID (delete the relationship between the two objects but does not delete the target object itself)
(4, ID) link to existing record with id = ID (adds a relationship)
(5) unlink all (like using (3,ID) for all linked records)
(6, 0, [IDs]) replace the list of linked IDs (like using (5) then (4,ID) for each ID in the list of IDs)
但在你的情况下可能是 many2one
应该是
def abcde(self):
rec = self.test_record.id
res = self.env['anc'].browse(rec)
res.write({'partner_id':[(4,self.partner_id.id)]}) # you need to add it as list