混淆矩阵查询

Question

我有下面的代码来生成混淆矩阵，它在其中生成 heatmap 和 accuracy_score

来源

代码

import pandas as pd
import seaborn as sn
import matplotlib.pyplot as plt
from sklearn.metrics import accuracy_score
from sklearn import metrics

data = pd.read_excel(r"\Confusion Matrix.xlsx")

df = pd.DataFrame(data)
confusion_matrix = pd.crosstab(df['Actual'], df['Pred'], rownames=['Actual'], colnames=['Predicted'], margins = True)

sn.heatmap(confusion_matrix, annot=True)
plt.show()

accuray_score_in_percentage = accuracy_score(['Actual'], ['Pred'])
accuray_score_in_count = accuracy_score(['Actual'], ['Pred'], normalize=False)

print('The Precentage Accuracy is : ', accuray_score_in_percentage)
print('The Count of corrects are : ', accuray_score_in_count)

输出

从上面的输出中你可以看到百分比精度是：0.0和正确的计数是：0但是它必须是百分比精度是：0.3和正确计数是：3。谁能帮我修改一下代码，让它显示正确的 准确度得分.

此致，

巴拉斯·维卡斯

Answer 1

您不需要混淆矩阵来计算准确度。
尝试：

accuray_score_in_percentage = accuracy_score(df['Actual'], df['Pred'])  
accuray_score_in_count = accuracy_score(df['Actual'], df['Pred'], normalize=False)

如果你真的想使用你的混淆矩阵，你可以这样做：

accuray_score_in_percentage = (confusion_matrix.loc[0,0]+confusion_matrix.loc[1,1])/confusion_matrix.loc["All","All"]
accuray_score_in_count = confusion_matrix.loc[0,0]+confusion_matrix.loc[1,1]

混淆矩阵查询

Confusion Matrix query

python

pandas

confusion-matrix