使用 Decodable 为 base JSON 响应解码 Object 类型和泛型类型的数据
Decode data of Object type and generic type for base JSON response using Decodable
我有一个基础模型 -
struct BaseModel<T:Decodable>: Decodable {
let jsonData: [T]?
let status: Bool?
let message: String?
enum CodingKeys: String, CodingKey {
case jsonData = "data"
case status = "success"
case message
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
if let string = try container.decodeIfPresent(T.self, forKey: .jsonData) {
print(string)
jsonData = [string]
} else {
jsonData = nil
}
} catch DecodingError.typeMismatch {
jsonData = try container.decodeIfPresent([T].self, forKey: .jsonData)
}
status = try container.decodeIfPresent(Bool.self, forKey: .status)
message = try container.decodeIfPresent(String.self, forKey: .message)
}
}
我在 jsonData 下收到两种类型的响应
- 对象
- 数组
如果我收到作为对象的响应,则在解码时出错。如果我选择 let jsonData: T?,那么数组响应的解码就会出现问题。
我在我的网络模型中使用这个模型。看起来像 -
func performOperation<T:Decodable>(urlEndPoint: String, method: HTTPMethod, param: Parameters?, isJsonAvailable: Bool, completion: @escaping(_ response: T?, [T]?, String?, Bool?) ->Void) {
AF.request(urlEndPoint, method: method, parameters: param, headers: header).validate(statusCode: 200..<500).responseDecodable(of: BaseModel<T>.self, decoder: decoder) { (response) in
}
Json 响应 Object -
{
"success": true,
"data": {
"heading": "Same text 1",
"title": "Sample Text 2",
"content": "Sample text 3"
},
"message": "Api response received"
}
Json 在 ArrayList -
情况下的响应
{
"success": true,
"data": [
{
"id": 1,
"name": "Home"
},
{
"id": 2,
"name": "Profile"
}
],
"message": "Menu List"
}
您不需要通用结构。如果没有用户数组,只需创建一个可选的 属性 来分配您的对象:
struct BaseModel {
let data: [User]
let post: Post?
let success: Bool
let message: String
}
struct User: Codable {
let id: Int
let name: String
}
struct Post: Codable {
let heading: String
let title: String
let content: String
}
extension BaseModel: Codable {
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
data = try container.decode([User].self, forKey: .data)
post = nil
} catch DecodingError.typeMismatch {
data = []
post = try container.decode(Post.self, forKey: .data)
}
success = try container.decode(Bool.self, forKey: .success)
message = try container.decode(String.self, forKey: .message)
}
}
如果您的 post 中没有显示其他响应,您也可以使用通用结构执行上述相同的方法:
struct BaseModel<T: Codable> {
let array: [T]
let element: T?
let success: Bool
let message: String
}
extension BaseModel: Codable {
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
array = try container.decode([T].self, forKey: .array)
element = nil
} catch DecodingError.typeMismatch {
array = []
element = try container.decode(T.self, forKey: .array)
}
success = try container.decode(Bool.self, forKey: .success)
message = try container.decode(String.self, forKey: .message)
}
}
我有一个基础模型 -
struct BaseModel<T:Decodable>: Decodable {
let jsonData: [T]?
let status: Bool?
let message: String?
enum CodingKeys: String, CodingKey {
case jsonData = "data"
case status = "success"
case message
}
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
if let string = try container.decodeIfPresent(T.self, forKey: .jsonData) {
print(string)
jsonData = [string]
} else {
jsonData = nil
}
} catch DecodingError.typeMismatch {
jsonData = try container.decodeIfPresent([T].self, forKey: .jsonData)
}
status = try container.decodeIfPresent(Bool.self, forKey: .status)
message = try container.decodeIfPresent(String.self, forKey: .message)
}
}
我在 jsonData 下收到两种类型的响应
- 对象
- 数组
如果我收到作为对象的响应,则在解码时出错。如果我选择 let jsonData: T?,那么数组响应的解码就会出现问题。
我在我的网络模型中使用这个模型。看起来像 -
func performOperation<T:Decodable>(urlEndPoint: String, method: HTTPMethod, param: Parameters?, isJsonAvailable: Bool, completion: @escaping(_ response: T?, [T]?, String?, Bool?) ->Void) {
AF.request(urlEndPoint, method: method, parameters: param, headers: header).validate(statusCode: 200..<500).responseDecodable(of: BaseModel<T>.self, decoder: decoder) { (response) in
}
Json 响应 Object -
{
"success": true,
"data": {
"heading": "Same text 1",
"title": "Sample Text 2",
"content": "Sample text 3"
},
"message": "Api response received"
}
Json 在 ArrayList -
情况下的响应{
"success": true,
"data": [
{
"id": 1,
"name": "Home"
},
{
"id": 2,
"name": "Profile"
}
],
"message": "Menu List"
}
您不需要通用结构。如果没有用户数组,只需创建一个可选的 属性 来分配您的对象:
struct BaseModel {
let data: [User]
let post: Post?
let success: Bool
let message: String
}
struct User: Codable {
let id: Int
let name: String
}
struct Post: Codable {
let heading: String
let title: String
let content: String
}
extension BaseModel: Codable {
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
data = try container.decode([User].self, forKey: .data)
post = nil
} catch DecodingError.typeMismatch {
data = []
post = try container.decode(Post.self, forKey: .data)
}
success = try container.decode(Bool.self, forKey: .success)
message = try container.decode(String.self, forKey: .message)
}
}
如果您的 post 中没有显示其他响应,您也可以使用通用结构执行上述相同的方法:
struct BaseModel<T: Codable> {
let array: [T]
let element: T?
let success: Bool
let message: String
}
extension BaseModel: Codable {
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
array = try container.decode([T].self, forKey: .array)
element = nil
} catch DecodingError.typeMismatch {
array = []
element = try container.decode(T.self, forKey: .array)
}
success = try container.decode(Bool.self, forKey: .success)
message = try container.decode(String.self, forKey: .message)
}
}