如何检查一个对象数组是否包含另一个对象数组的所有ID JS

Question

我有 2 个对象数组；

// First one :
[0: {id: 1},
1: {id: 2},
2: {id: 3},
3: {id: 4}]

// Second one :
[0: {id: 10},
1: {id: 1},
2: {id: 4},
3: {id: 76},
4: {id: 2},
5: {id: 47},
6: {id: 3}]

我想测试第二个是否至少具有与第一个相同的 ID。在这种情况下是正确的，因为第二个包含 1、2、3 和 4 个 ID。

我尝试使用 some() 和 every() 但它不能正常工作

我的尝试：

let res = this.trainingEpisodesList.some( episode => {
    this.completedEpisodes.every( userEpisode => {
         userEpisode.id == episode.id;
     })
});

谢谢 ;)

Answer 1

您可以使用 every and find:

let completedEpisodes = 
[
{id: 1},
{id: 2},
{id: 3},
{id: 4}
]

let trainingEpisodesList = 
[
{id: 10},
{id: 1},
{id: 4},
{id: 76},
{id: 2},
{id: 47},
{id: 3}
]

let containsAllCompleted = trainingEpisodesList.every(c => completedEpisodes.find(e=>e.id==c.id));

console.log(containsAllCompleted);

Answer 2

正确，

let result = one.map(a => a.id);
let result2 = two.map(a => a.id);
const final_result = result.every(val => result2.includes(val));

傻，

var result = one.map(a => a.id);
var result2 = two.map(a => a.id);

var final_result = result.every(function(val) {

  return result2.indexOf(val) >= 0;

});

如何检查一个对象数组是否包含另一个对象数组的所有ID JS

How to check if an array of objects contains all the ids of another array of objects JS

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