类型不匹配 Swift JSON

Question

我认为我正确地创建了结构，但它给出了错误。

typeMismatch(Swift.Array, Swift.DecodingError.Context(codingPath: [], debugDescription: "预期解码数组但发现了字典。", underlyingError: nil))

型号：

struct veriler : Codable {
    let success : Bool
    let result : [result]
    
}

struct result : Codable {
    let country : String
    let totalCases : String
    let newCases : String
    let totalDeaths : String
    let newDeaths : String
    let totalRecovered : String
    let activeCases : String
}

JSON数据：

{
  "success": true,
  "result": [
    {
      "country": "China",
      "totalcases": "80,881",
      "newCases": "+21",
      "totaldeaths": "3,226",
      "newDeaths": "+13",
      "totalRecovered": "68,709",
      "activeCases": "8,946"
    },
    {
      "country": "Italy",
      "totalcases": "27,980",
      "newCases": "",
      "totaldeaths": "2,158",
      "newDeaths": "",
      "totalRecovered": "2,749",
      "activeCases": "23,073"
    },
    "..."
  ]
}

解码：

let decoder = JSONDecoder()
        do {
            let country = try decoder.decode([result].self, from: data!)
          for i in 0..<country.count {
            print (country[i].country)
          }
        } catch {
          print(error)
        }

Answer 1

首先，您需要通过指定自定义 CodingKeys 来修改 result 结构（请注意模型中的 totalCases 与 [=26= 中的 totalcases 之间的不匹配]):

struct result: Codable {
    enum CodingKeys: String, CodingKey {
        case country, newCases, newDeaths, totalRecovered, activeCases
        case totalCases = "totalcases"
        case totalDeaths = "totaldeaths"
    }
    
    let country: String
    let totalCases: String
    let newCases: String
    let totalDeaths: String
    let newDeaths: String
    let totalRecovered: String
    let activeCases: String
}

然后你需要解码 veriler.self 而不是 [result].self:

let decoder = JSONDecoder()
do {
    let result = try decoder.decode(veriler.self, from: data!)
    let countries = result.result
    for i in 0 ..< countries.count {
        print(countries[i].country)
    }
} catch {
    print(error)
}

注意：我建议遵循 Swift 指南并命名结构，如 Result 或 Veriler（只有实例应小写）。

类型不匹配 Swift JSON

Type Mismatch Swift JSON

ios

json

swift

api

type-mismatch