在 TKINTER CALCULATOR 中添加一个 CLEAR ENTRY 按钮
Adding a CLEAR ENTRY button in TKINTER CALCULATOR
我正在用 Tkinter (Python) 编写一个计算器。我想添加一个 CLEAR ENTRY 按钮,用于清除 'entry' 用户提供的内容。不要与“全部清除”按钮混淆。
示例:
用户输入:- 35+87=62
然后按下 CE 按钮,所以他应该显示:- 35+87 如果他再次按下,他应该得到 35 等等直到 0.
我试了很多次,最后还是来找你了。
这是基本代码,(它没有制作任何CE按钮,您可以添加一个)。您可以使用正则表达式。
from tkinter import *
expression = ""
def press(num):
global expression
expression = expression + str(num)
equation.set(expression)
def equalpress():
try:
global expression
total = str(eval(expression))
equation.set(total)
expression = ""
except:
equation.set(" error ")
expression = ""
def clear():
global expression
expression = ""
equation.set("")
if __name__ == "__main__":
# create a GUI window
gui = Tk()
# set the background colour of GUI window
gui.configure(background="light green")
# set the title of GUI window
gui.title("Simple Calculator")
# set the configuration of GUI window
gui.geometry("270x150")
# StringVar() is the variable class
# we create an instance of this class
equation = StringVar()
# create the text entry box for
# showing the expression .
expression_field = Entry(gui, textvariable=equation)
expression_field.grid(columnspan=4, ipadx=70)
equation.set('enter your expression')
button1 = Button(gui, text=' 1 ', fg='black', bg='red',
command=lambda: press(1), height=1, width=7)
button1.grid(row=2, column=0)
button2 = Button(gui, text=' 2 ', fg='black', bg='red',
command=lambda: press(2), height=1, width=7)
button2.grid(row=2, column=1)
button3 = Button(gui, text=' 3 ', fg='black', bg='red',
command=lambda: press(3), height=1, width=7)
button3.grid(row=2, column=2)
button4 = Button(gui, text=' 4 ', fg='black', bg='red',
command=lambda: press(4), height=1, width=7)
button4.grid(row=3, column=0)
button5 = Button(gui, text=' 5 ', fg='black', bg='red',
command=lambda: press(5), height=1, width=7)
button5.grid(row=3, column=1)
button6 = Button(gui, text=' 6 ', fg='black', bg='red',
command=lambda: press(6), height=1, width=7)
button6.grid(row=3, column=2)
button7 = Button(gui, text=' 7 ', fg='black', bg='red',
command=lambda: press(7), height=1, width=7)
button7.grid(row=4, column=0)
button8 = Button(gui, text=' 8 ', fg='black', bg='red',
command=lambda: press(8), height=1, width=7)
button8.grid(row=4, column=1)
button9 = Button(gui, text=' 9 ', fg='black', bg='red',
command=lambda: press(9), height=1, width=7)
button9.grid(row=4, column=2)
button0 = Button(gui, text=' 0 ', fg='black', bg='red',
command=lambda: press(0), height=1, width=7)
button0.grid(row=5, column=0)
plus = Button(gui, text=' + ', fg='black', bg='red',
command=lambda: press("+"), height=1, width=7)
plus.grid(row=2, column=3)
minus = Button(gui, text=' - ', fg='black', bg='red',
command=lambda: press("-"), height=1, width=7)
minus.grid(row=3, column=3)
multiply = Button(gui, text=' * ', fg='black', bg='red',
command=lambda: press("*"), height=1, width=7)
multiply.grid(row=4, column=3)
divide = Button(gui, text=' / ', fg='black', bg='red',
command=lambda: press("/"), height=1, width=7)
divide.grid(row=5, column=3)
equal = Button(gui, text=' = ', fg='black', bg='red',
command=equalpress, height=1, width=7)
equal.grid(row=5, column=2)
clear = Button(gui, text='Clear', fg='black', bg='red',
command=clear, height=1, width=7)
clear.grid(row=5, column='1')
Decimal= Button(gui, text='.', fg='black', bg='red',
command=lambda: press('.'), height=1, width=7)
Decimal.grid(row=6, column=0)
gui.mainloop()
在公式字段中,只允许使用数字、运算符和小数点。要清除最新条目,请从等式末尾搜索第一个运算符 (+ - * /),然后截断字符串。
将此函数用于 ClearEntry 按钮:
def clearentry():
global expression
for i,c in enumerate(expression[::-1]): # reverse string
if c in ['+','-','/','*']: # find first operator
expression = expression[:-i-1] # truncate string
break
else:
expression = "" # no operator found
equation.set(expression)
我将此作为答案发布,因为我的声誉很低,无法发表任何评论。所以,我只是对 Mike67 的回答中的一个缺失点做了一个小补充。
如果在对方程求和后按清除输入按钮,它将显示方程。例如,如果您计算 2+3,而 5 在您的屏幕上。这将显示 2+3。我只是在这两个函数中添加了几行:
def equalpress():
global backup_expression
try:
global expression
total = str(eval(expression))
equation.set(total)
backup_expression = expression
expression = ""
except:
equation.set(" error ")
expression = ""
def clearentry():
global expression,backup_expression
for i,c in enumerate(expression[::-1]): # reverse string
if c in ['+','-','/','*']: # find first operator
expression = expression[:-i-1] # truncate string
break
else: # no operator found
expression = backup_expression
equation.set(expression)
我正在用 Tkinter (Python) 编写一个计算器。我想添加一个 CLEAR ENTRY 按钮,用于清除 'entry' 用户提供的内容。不要与“全部清除”按钮混淆。
示例: 用户输入:- 35+87=62 然后按下 CE 按钮,所以他应该显示:- 35+87 如果他再次按下,他应该得到 35 等等直到 0.
我试了很多次,最后还是来找你了。 这是基本代码,(它没有制作任何CE按钮,您可以添加一个)。您可以使用正则表达式。
from tkinter import *
expression = ""
def press(num):
global expression
expression = expression + str(num)
equation.set(expression)
def equalpress():
try:
global expression
total = str(eval(expression))
equation.set(total)
expression = ""
except:
equation.set(" error ")
expression = ""
def clear():
global expression
expression = ""
equation.set("")
if __name__ == "__main__":
# create a GUI window
gui = Tk()
# set the background colour of GUI window
gui.configure(background="light green")
# set the title of GUI window
gui.title("Simple Calculator")
# set the configuration of GUI window
gui.geometry("270x150")
# StringVar() is the variable class
# we create an instance of this class
equation = StringVar()
# create the text entry box for
# showing the expression .
expression_field = Entry(gui, textvariable=equation)
expression_field.grid(columnspan=4, ipadx=70)
equation.set('enter your expression')
button1 = Button(gui, text=' 1 ', fg='black', bg='red',
command=lambda: press(1), height=1, width=7)
button1.grid(row=2, column=0)
button2 = Button(gui, text=' 2 ', fg='black', bg='red',
command=lambda: press(2), height=1, width=7)
button2.grid(row=2, column=1)
button3 = Button(gui, text=' 3 ', fg='black', bg='red',
command=lambda: press(3), height=1, width=7)
button3.grid(row=2, column=2)
button4 = Button(gui, text=' 4 ', fg='black', bg='red',
command=lambda: press(4), height=1, width=7)
button4.grid(row=3, column=0)
button5 = Button(gui, text=' 5 ', fg='black', bg='red',
command=lambda: press(5), height=1, width=7)
button5.grid(row=3, column=1)
button6 = Button(gui, text=' 6 ', fg='black', bg='red',
command=lambda: press(6), height=1, width=7)
button6.grid(row=3, column=2)
button7 = Button(gui, text=' 7 ', fg='black', bg='red',
command=lambda: press(7), height=1, width=7)
button7.grid(row=4, column=0)
button8 = Button(gui, text=' 8 ', fg='black', bg='red',
command=lambda: press(8), height=1, width=7)
button8.grid(row=4, column=1)
button9 = Button(gui, text=' 9 ', fg='black', bg='red',
command=lambda: press(9), height=1, width=7)
button9.grid(row=4, column=2)
button0 = Button(gui, text=' 0 ', fg='black', bg='red',
command=lambda: press(0), height=1, width=7)
button0.grid(row=5, column=0)
plus = Button(gui, text=' + ', fg='black', bg='red',
command=lambda: press("+"), height=1, width=7)
plus.grid(row=2, column=3)
minus = Button(gui, text=' - ', fg='black', bg='red',
command=lambda: press("-"), height=1, width=7)
minus.grid(row=3, column=3)
multiply = Button(gui, text=' * ', fg='black', bg='red',
command=lambda: press("*"), height=1, width=7)
multiply.grid(row=4, column=3)
divide = Button(gui, text=' / ', fg='black', bg='red',
command=lambda: press("/"), height=1, width=7)
divide.grid(row=5, column=3)
equal = Button(gui, text=' = ', fg='black', bg='red',
command=equalpress, height=1, width=7)
equal.grid(row=5, column=2)
clear = Button(gui, text='Clear', fg='black', bg='red',
command=clear, height=1, width=7)
clear.grid(row=5, column='1')
Decimal= Button(gui, text='.', fg='black', bg='red',
command=lambda: press('.'), height=1, width=7)
Decimal.grid(row=6, column=0)
gui.mainloop()
在公式字段中,只允许使用数字、运算符和小数点。要清除最新条目,请从等式末尾搜索第一个运算符 (+ - * /),然后截断字符串。
将此函数用于 ClearEntry 按钮:
def clearentry():
global expression
for i,c in enumerate(expression[::-1]): # reverse string
if c in ['+','-','/','*']: # find first operator
expression = expression[:-i-1] # truncate string
break
else:
expression = "" # no operator found
equation.set(expression)
我将此作为答案发布,因为我的声誉很低,无法发表任何评论。所以,我只是对 Mike67 的回答中的一个缺失点做了一个小补充。
如果在对方程求和后按清除输入按钮,它将显示方程。例如,如果您计算 2+3,而 5 在您的屏幕上。这将显示 2+3。我只是在这两个函数中添加了几行:
def equalpress():
global backup_expression
try:
global expression
total = str(eval(expression))
equation.set(total)
backup_expression = expression
expression = ""
except:
equation.set(" error ")
expression = ""
def clearentry():
global expression,backup_expression
for i,c in enumerate(expression[::-1]): # reverse string
if c in ['+','-','/','*']: # find first operator
expression = expression[:-i-1] # truncate string
break
else: # no operator found
expression = backup_expression
equation.set(expression)