如何获取特定状态或 ID 的总和并在 laravel 中加入 3 table

Question

my table

table1
|table1_id | name |
| 1         john |
| 2         dave |
| 3         carl |

table2
|table2_id| table1_id| type  |status
| 1       | 1        | shoes |paid
| 2       | 1        | bag   |paid
| 3       | 2        | bag   |paid
| 4       | 2        | shoes   |unpaid

table3
|table3_id|table2_id|item  |amount|
|1        |  1      |nike   |1000  |
|2        |  1      |adidas |2000  |
|3        |  2      |lv     |1000  |
|4        |  3      |lv1    |2000  |
|5        |  3      |lv     |1000  |
|6        |  4      |adidas |1000  |

this is the result I want to display john --- total paid shoes and bag dave <-- total of bag,'shoes is unpaid so 1000 is not added to total'

|name|total |
|john|4000  |
|dave|3000  | 
|carl|0  |

this is my controller it gives me an error the total is same in all name

   public function index()
        {
            $fetch = DB::table('table1')
            ->leftjoin('table2','table1.table1_id','=','table2.table1_id')      
            ->leftjoin('table3','table2.table2_id','=','table3.table2_id')
            ->select('table1.*','table2.*',DB::raw('(select sum(table3.amount) from table3
            join table2 on table2.table2_id = table3.table2_id 
             where table.status = "paid") as used'))
            ->groupBy('table1.table1_id')
              
            ->get();
            return $fetch;
        }

Answer 1

您可以考虑加入子查询，这当然是一种方法。这是一个例子：

$sales = DB::table('table3')
            ->select('table2_id', DB::raw('sum(amount) as cat_sale_amount'))
            ->groupBy('table2_id');

$table2Sales = DB::table('table2')
            ->select('table1_id', DB::raw('sum(cat_sale_amount) as total_sale_amount'))
            ->joinSub($sales, 'sales', function($join){
                $join->on('table2.id', '=', 'sales.table2_id');
            })
            ->where('status', 'paid')
            ->groupBy('table1_id');

$userTotalSales = DB::table('table1')
                  ->select('name', 'total_sale_amount as total')
                  ->leftJoinSub($table2Sales, 'table2Sales', function($join){
                     $join->on('table1.id', '=', 'table2Sales.table1_id');
                  })->get();

第一个子查询将根据 table1 中的 type 给出总销售额，方法是对 table2_id 进行分组并对金额使用求和运算。因此结果将列出 user_id/table2_id 和每种类型的数量。

第二个子查询将通过加入第一个子查询给出个人 customers/user 的总销售额。按 cutomer/user/table1_id 分组以获得第一个查询的金额总和，以获得单个客户的总数。

将第二个加入用户table，你应该会得到想要的结果。

如何获取特定状态或 ID 的总和并在 laravel 中加入 3 table

How to get sum of specific status or id and joining 3 table in laravel

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