使用 libpng 写入 1 位深度灰度 PNG 会导致图像不正确
Writing a 1 bit depth grayscale PNG with libpng results in incorrect image
所以我正在尝试使用 libpng
从位深度为 1 的 unsigned char
数组中写入 png。对于所有位来说,只有黑色和白色,作为灰度图像。我已经成功地为 8 位深度灰度 png 做到了这一点,但不是 1 位深度。这是我的代码:
extern int write_png_bwsq(const char* filename,
int dimen,
const unsigned char *buffer,
char* title)
{
int yrow;
int dim_bytes;
int code = 1;
FILE *fp = NULL;
png_structp png_ptr = NULL;
png_infop info_ptr = NULL;
png_bytep row = NULL;
dim_bytes = (dimen * dimen) / 8;
// Open file for writing (binary mode)
fp = fopen(filename, "wb");
if (fp == NULL) {
fprintf(stderr, "PNG ERROR: Could not open file %s for writing\n", filename);
code = 0;
goto finalise;
}
// Initialize write structure
png_ptr = png_create_write_struct(PNG_LIBPNG_VER_STRING, NULL, NULL, NULL);
if (png_ptr == NULL) {
fprintf(stderr, "PNG ERROR: Could not allocate PNG write struct\n");
code = 0;
goto finalise;
}
// Initialize info structure
info_ptr = png_create_info_struct(png_ptr);
if (info_ptr == NULL) {
fprintf(stderr, "PNG ERROR: Could not allocate PNG info struct\n");
code = 0;
goto finalise;
}
// Setup Exception handling
if (setjmp(png_jmpbuf(png_ptr))) {
fprintf(stderr, "PNG Error: Creating the PNG output failed.\n");
code = 0;
goto finalise;
}
png_init_io(png_ptr, fp);
png_set_IHDR(png_ptr, info_ptr, dimen, dimen,
1, PNG_COLOR_TYPE_GRAY, PNG_INTERLACE_NONE,
PNG_COMPRESSION_TYPE_BASE, PNG_FILTER_TYPE_BASE);
// Sets the title
if (title != NULL) {
png_text title_text;
title_text.compression = PNG_TEXT_COMPRESSION_NONE;
title_text.key = "Title";
title_text.text = title;
png_set_text(png_ptr, info_ptr, &title_text, 1);
}
png_write_info(png_ptr, info_ptr);
row = (png_bytep) buffer;
// Write image data
for (yrow=0 ; yrow<dim_bytes ; yrow++) {
png_write_row(png_ptr, row);
++row;
}
// End write operation
png_write_end(png_ptr, NULL);
finalise:
if (fp != NULL) fclose(fp);
if (info_ptr != NULL) png_free_data(png_ptr, info_ptr, PNG_FREE_ALL, -1);
if (png_ptr != NULL) png_destroy_write_struct(&png_ptr, (png_infopp)NULL);
return code;
}
然后,我有一个单独的文件来准备图像
#include "write_pngs.h"
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
#if CHAR_BIT != 8
# error "CHAR_BIT is not usable on this platform"
#endif
#define PIC_SIZE_DIM 1080
#define PIC_SIZE_BW ((PIC_SIZE_DIM * PIC_SIZE_DIM) / CHAR_BIT)
static unsigned char PIC_BITS[PIC_SIZE_BW] = {0};
static void __write_bits_pic(void)
{
size_t i = 1000;
for(;i < 140000;++i) {
PIC_BITS[i] = ((i + 76) >> 5) & 0xff;
}
}
int main(void) {
__write_bits_pic();
printf("Writing picture of %d bytes and %d bits\n", PIC_SIZE_BW, PIC_SIZE_BW * CHAR_BIT);
return !write_png_bwsq("bwpixs.png",
PIC_SIZE_DIM,
PIC_BITS,
"bwpixs");
}
这会导致图像不正确,它不仅对于 png 来说非常大(仅 1080 x 1080 大约 5mb),而且只有图像的右下角从黑色变为黑色。
我在这里做错了什么? libpng
是否需要任何特殊步骤来编写我没有做的灰度位深度仅为 1 的 png?
您调用 png_write_row()
的次数太多了。你的
for (yrow=0 ; yrow<dim_bytes ; yrow++) {
png_write_row(png_ptr, row);
++row;
}
应该是这样的:
for (yrow=0 ; yrow<dim_bytes ; yrow += dimen / 8) {
png_write_row(png_ptr, row);
row += dimen / 8;
}
为了写入 1080 像素(135 字节)的行。您正在为每个字节调用 png_write_row()
,就好像图像是八个像素宽一样。事实并非如此。
所以我正在尝试使用 libpng
从位深度为 1 的 unsigned char
数组中写入 png。对于所有位来说,只有黑色和白色,作为灰度图像。我已经成功地为 8 位深度灰度 png 做到了这一点,但不是 1 位深度。这是我的代码:
extern int write_png_bwsq(const char* filename,
int dimen,
const unsigned char *buffer,
char* title)
{
int yrow;
int dim_bytes;
int code = 1;
FILE *fp = NULL;
png_structp png_ptr = NULL;
png_infop info_ptr = NULL;
png_bytep row = NULL;
dim_bytes = (dimen * dimen) / 8;
// Open file for writing (binary mode)
fp = fopen(filename, "wb");
if (fp == NULL) {
fprintf(stderr, "PNG ERROR: Could not open file %s for writing\n", filename);
code = 0;
goto finalise;
}
// Initialize write structure
png_ptr = png_create_write_struct(PNG_LIBPNG_VER_STRING, NULL, NULL, NULL);
if (png_ptr == NULL) {
fprintf(stderr, "PNG ERROR: Could not allocate PNG write struct\n");
code = 0;
goto finalise;
}
// Initialize info structure
info_ptr = png_create_info_struct(png_ptr);
if (info_ptr == NULL) {
fprintf(stderr, "PNG ERROR: Could not allocate PNG info struct\n");
code = 0;
goto finalise;
}
// Setup Exception handling
if (setjmp(png_jmpbuf(png_ptr))) {
fprintf(stderr, "PNG Error: Creating the PNG output failed.\n");
code = 0;
goto finalise;
}
png_init_io(png_ptr, fp);
png_set_IHDR(png_ptr, info_ptr, dimen, dimen,
1, PNG_COLOR_TYPE_GRAY, PNG_INTERLACE_NONE,
PNG_COMPRESSION_TYPE_BASE, PNG_FILTER_TYPE_BASE);
// Sets the title
if (title != NULL) {
png_text title_text;
title_text.compression = PNG_TEXT_COMPRESSION_NONE;
title_text.key = "Title";
title_text.text = title;
png_set_text(png_ptr, info_ptr, &title_text, 1);
}
png_write_info(png_ptr, info_ptr);
row = (png_bytep) buffer;
// Write image data
for (yrow=0 ; yrow<dim_bytes ; yrow++) {
png_write_row(png_ptr, row);
++row;
}
// End write operation
png_write_end(png_ptr, NULL);
finalise:
if (fp != NULL) fclose(fp);
if (info_ptr != NULL) png_free_data(png_ptr, info_ptr, PNG_FREE_ALL, -1);
if (png_ptr != NULL) png_destroy_write_struct(&png_ptr, (png_infopp)NULL);
return code;
}
然后,我有一个单独的文件来准备图像
#include "write_pngs.h"
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>
#if CHAR_BIT != 8
# error "CHAR_BIT is not usable on this platform"
#endif
#define PIC_SIZE_DIM 1080
#define PIC_SIZE_BW ((PIC_SIZE_DIM * PIC_SIZE_DIM) / CHAR_BIT)
static unsigned char PIC_BITS[PIC_SIZE_BW] = {0};
static void __write_bits_pic(void)
{
size_t i = 1000;
for(;i < 140000;++i) {
PIC_BITS[i] = ((i + 76) >> 5) & 0xff;
}
}
int main(void) {
__write_bits_pic();
printf("Writing picture of %d bytes and %d bits\n", PIC_SIZE_BW, PIC_SIZE_BW * CHAR_BIT);
return !write_png_bwsq("bwpixs.png",
PIC_SIZE_DIM,
PIC_BITS,
"bwpixs");
}
这会导致图像不正确,它不仅对于 png 来说非常大(仅 1080 x 1080 大约 5mb),而且只有图像的右下角从黑色变为黑色。
我在这里做错了什么? libpng
是否需要任何特殊步骤来编写我没有做的灰度位深度仅为 1 的 png?
您调用 png_write_row()
的次数太多了。你的
for (yrow=0 ; yrow<dim_bytes ; yrow++) {
png_write_row(png_ptr, row);
++row;
}
应该是这样的:
for (yrow=0 ; yrow<dim_bytes ; yrow += dimen / 8) {
png_write_row(png_ptr, row);
row += dimen / 8;
}
为了写入 1080 像素(135 字节)的行。您正在为每个字节调用 png_write_row()
,就好像图像是八个像素宽一样。事实并非如此。