如何重塑我的数据框以在 R 中使用 TTR?
How to reshape my data frame to use TTR in R?
基本上 TTR 允许获取代码的技术指标,数据应该是垂直的,如:
Date Open High Low Close
2014-05-16 16.83 16.84 16.63 16.71
2014-05-19 16.73 16.93 16.66 16.80
2014-05-20 16.80 16.81 16.58 16.70
但我的数据框是这样的:
Sdate Edate Tickers Open_1 Open_2 Open_3 High_1 High_2 High_3 Low_1 Low_2 Low_3 Close_1 Close_2 Close_3
2014-05-16 2014-07-21 TK 31.6 31.8 32.2 32.4 32.4 33.0 31.1 31.5 32.1 32.1 32.1 32.7
2014-05-17 2014-07-22 TGP 25.1 24.8 25.0 25.1 25.3 25.8 24.1 24.4 24.9 24.8 25.0 25.6
2014-05-18 2014-07-23 DNR 3.4 3.5 3.8 3.6 3.8 4.1 3.3 3.5 3.8 3.5 3.7 3.9
如您所见,我有多个代码和时间范围。我检查了 TTR 包,它没有说明如何从中获取水平制作的技术指标和多个代码。我的原始数据有 50 天和数千个代码。要做到这一点,我只知道,我需要为每个代码制作清单,但我很困惑如何做到这一点。我该如何实现?
您可以使用 pivot_longer
获取垂直形状的数据:
out <- tidyr::pivot_longer(df, cols = -c(Sdate,Edate, Tickers),
names_to = c('.value', 'num'),
names_sep = '_')
out
# A tibble: 9 x 8
# Sdate Edate Tickers num Open High Low Close
# <chr> <chr> <chr> <chr> <dbl> <dbl> <dbl> <dbl>
#1 2014-05-16 2014-07-21 TK 1 31.6 32.4 31.1 32.1
#2 2014-05-16 2014-07-21 TK 2 31.8 32.4 31.5 32.1
#3 2014-05-16 2014-07-21 TK 3 32.2 33 32.1 32.7
#4 2014-05-17 2014-07-22 TGP 1 25.1 25.1 24.1 24.8
#5 2014-05-17 2014-07-22 TGP 2 24.8 25.3 24.4 25
#6 2014-05-17 2014-07-22 TGP 3 25 25.8 24.9 25.6
#7 2014-05-18 2014-07-23 DNR 1 3.4 3.6 3.3 3.5
#8 2014-05-18 2014-07-23 DNR 2 3.5 3.8 3.5 3.7
#9 2014-05-18 2014-07-23 DNR 3 3.8 4.1 3.8 3.9
如果您想根据 Ticker
将上述数据拆分为数据框列表,您可以使用 split
.
split(out, out$Tickers)
数据
df <- structure(list(Sdate = c("2014-05-16", "2014-05-17", "2014-05-18"
), Edate = c("2014-07-21", "2014-07-22", "2014-07-23"), Tickers = c("TK",
"TGP", "DNR"), Open_1 = c(31.6, 25.1, 3.4), Open_2 = c(31.8,
24.8, 3.5), Open_3 = c(32.2, 25, 3.8), High_1 = c(32.4, 25.1,
3.6), High_2 = c(32.4, 25.3, 3.8), High_3 = c(33, 25.8, 4.1),
Low_1 = c(31.1, 24.1, 3.3), Low_2 = c(31.5, 24.4, 3.5), Low_3 = c(32.1,
24.9, 3.8), Close_1 = c(32.1, 24.8, 3.5), Close_2 = c(32.1,
25, 3.7), Close_3 = c(32.7, 25.6, 3.9)),
class = "data.frame", row.names = c(NA, -3L))
基本上 TTR 允许获取代码的技术指标,数据应该是垂直的,如:
Date Open High Low Close
2014-05-16 16.83 16.84 16.63 16.71
2014-05-19 16.73 16.93 16.66 16.80
2014-05-20 16.80 16.81 16.58 16.70
但我的数据框是这样的:
Sdate Edate Tickers Open_1 Open_2 Open_3 High_1 High_2 High_3 Low_1 Low_2 Low_3 Close_1 Close_2 Close_3
2014-05-16 2014-07-21 TK 31.6 31.8 32.2 32.4 32.4 33.0 31.1 31.5 32.1 32.1 32.1 32.7
2014-05-17 2014-07-22 TGP 25.1 24.8 25.0 25.1 25.3 25.8 24.1 24.4 24.9 24.8 25.0 25.6
2014-05-18 2014-07-23 DNR 3.4 3.5 3.8 3.6 3.8 4.1 3.3 3.5 3.8 3.5 3.7 3.9
如您所见,我有多个代码和时间范围。我检查了 TTR 包,它没有说明如何从中获取水平制作的技术指标和多个代码。我的原始数据有 50 天和数千个代码。要做到这一点,我只知道,我需要为每个代码制作清单,但我很困惑如何做到这一点。我该如何实现?
您可以使用 pivot_longer
获取垂直形状的数据:
out <- tidyr::pivot_longer(df, cols = -c(Sdate,Edate, Tickers),
names_to = c('.value', 'num'),
names_sep = '_')
out
# A tibble: 9 x 8
# Sdate Edate Tickers num Open High Low Close
# <chr> <chr> <chr> <chr> <dbl> <dbl> <dbl> <dbl>
#1 2014-05-16 2014-07-21 TK 1 31.6 32.4 31.1 32.1
#2 2014-05-16 2014-07-21 TK 2 31.8 32.4 31.5 32.1
#3 2014-05-16 2014-07-21 TK 3 32.2 33 32.1 32.7
#4 2014-05-17 2014-07-22 TGP 1 25.1 25.1 24.1 24.8
#5 2014-05-17 2014-07-22 TGP 2 24.8 25.3 24.4 25
#6 2014-05-17 2014-07-22 TGP 3 25 25.8 24.9 25.6
#7 2014-05-18 2014-07-23 DNR 1 3.4 3.6 3.3 3.5
#8 2014-05-18 2014-07-23 DNR 2 3.5 3.8 3.5 3.7
#9 2014-05-18 2014-07-23 DNR 3 3.8 4.1 3.8 3.9
如果您想根据 Ticker
将上述数据拆分为数据框列表,您可以使用 split
.
split(out, out$Tickers)
数据
df <- structure(list(Sdate = c("2014-05-16", "2014-05-17", "2014-05-18"
), Edate = c("2014-07-21", "2014-07-22", "2014-07-23"), Tickers = c("TK",
"TGP", "DNR"), Open_1 = c(31.6, 25.1, 3.4), Open_2 = c(31.8,
24.8, 3.5), Open_3 = c(32.2, 25, 3.8), High_1 = c(32.4, 25.1,
3.6), High_2 = c(32.4, 25.3, 3.8), High_3 = c(33, 25.8, 4.1),
Low_1 = c(31.1, 24.1, 3.3), Low_2 = c(31.5, 24.4, 3.5), Low_3 = c(32.1,
24.9, 3.8), Close_1 = c(32.1, 24.8, 3.5), Close_2 = c(32.1,
25, 3.7), Close_3 = c(32.7, 25.6, 3.9)),
class = "data.frame", row.names = c(NA, -3L))